Problem 74
Question
Under which of the following conditions would toluene \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}_{3}\), be converted into bromomethyl benzene, \(\mathrm{C}_{6} \mathrm{H}_{3}-\mathrm{CH}_{2} \mathrm{Br}\) ? (a) reaction with \(\mathrm{Br}_{2}\) in dark (b) reaction with \(\mathrm{Br}_{2} / \mathrm{FeBr}_{3}\) (c) reaction with \(\mathrm{Br}_{2}\) in sunlight (d) reaction with \(\mathrm{HBr}\)
Step-by-Step Solution
Verified Answer
Reaction with Br2 in sunlight (option c) converts toluene to bromomethyl benzene.
1Step 1: Understanding the Reaction Pathways
To determine under which conditions toluene is converted to bromomethyl benzene, recognize the type of reaction needed. Toluene must undergo a substitution at the benzylic position, which typically requires a free radical halogenation.
2Step 2: Evaluating Option (a): Reaction with Br2 in Dark
In the dark, bromine molecules remain stable and do not generate free radicals. Therefore, there is no reaction with toluene as no benzylic hydrogen is abstracted. This condition is not suitable for forming bromomethyl benzene.
3Step 3: Evaluating Option (b): Reaction with Br2 / FeBr3
This combination is typical for electrophilic aromatic substitution, which affects the aromatic ring rather than the benzylic position. Hence, it would result in bromination on the benzene ring, not across the methyl group.
4Step 4: Evaluating Option (c): Reaction with Br2 in Sunlight
Sunlight provides energy to form bromine radicals from Br2, initiating a radical substitution reaction at the benzylic carbon, i.e., the formation of bromomethyl benzene. This fits the requirement for replacing a hydrogen at the benzylic position with a bromine.
5Step 5: Evaluating Option (d): Reaction with HBr
HBr provides bromine as a nucleophile rather than generating radicals, and thus does not lead to the required substitution at the benzylic position. It is not suitable for converting toluene to bromomethyl benzene.
Key Concepts
Free Radical HalogenationBenzylic SubstitutionElectrophilic Aromatic Substitution
Free Radical Halogenation
In free radical halogenation, a molecule like bromine (Br extsubscript{2}) breaks down into free radicals, which are highly reactive atoms or molecules with unpaired electrons. This process is usually initiated by heat or light, which provides the energy needed to overcome the bond energy of Br extsubscript{2}.
When toluene (C extsubscript{6}H extsubscript{5}-CH extsubscript{3}) is exposed to bromine in the presence of sunlight, the bromine molecules dissociate into bromine radicals. These radicals attack the benzylic hydrogen in toluene, forming a carbon radical at the benzylic position.
When toluene (C extsubscript{6}H extsubscript{5}-CH extsubscript{3}) is exposed to bromine in the presence of sunlight, the bromine molecules dissociate into bromine radicals. These radicals attack the benzylic hydrogen in toluene, forming a carbon radical at the benzylic position.
- This benzylic radical is then stabilized by a reaction with another bromine molecule, replacing one of the hydrogens with a bromine atom to form bromomethyl benzene (C extsubscript{6}H extsubscript{5}-CH extsubscript{2}Br).
- The free radical chain reaction continues until the bromine or toluene runs out.
Benzylic Substitution
Benzylic substitution involves the substitution of a hydrogen atom on the carbon atom directly attached to the benzene ring, known as the benzylic position. This position has unique reactivity due to resonance stabilization, enabling it to undergo various reactions more readily than aliphatic carbon positions.
In the case of toluene, the benzylic site is where the methyl group (CH extsubscript{3}) connects to the benzene ring.
In the case of toluene, the benzylic site is where the methyl group (CH extsubscript{3}) connects to the benzene ring.
- For bromination at this site, it’s crucial to use conditions that promote the formation of radicals.
- Energy sources like light (option c) trigger the transformation efficiently, leading to the desired product.
Electrophilic Aromatic Substitution
Electrophilic aromatic substitution (EAS) is a common reaction where an electrophile replaces a hydrogen atom in an aromatic system. This is typical of aromatic compounds due to their electron-rich nature.
However, when considering tolulene, which consists of a benzene ring attached to a methyl group, if one looks to substitute a benzylic hydrogen, EAS is not the appropriate pathway; this would instead lead to the aromatic ring being substituted.
However, when considering tolulene, which consists of a benzene ring attached to a methyl group, if one looks to substitute a benzylic hydrogen, EAS is not the appropriate pathway; this would instead lead to the aromatic ring being substituted.
- Reaction option (b), using Br extsubscript{2}/FeBr extsubscript{3}, is the classic condition for EAS, directing the bromination to the electron-rich aromatic ring due to the electrophilic character of the bromine in the presence of the iron catalyst.
- Thus, while bromination occurs, it does not happen at the benzylic position as needed for producing bromomethyl benzene.
Other exercises in this chapter
Problem 72
\(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Cl} \stackrel{\text { alc. } \mathrm{KOH}}{\longrightarrow}(\mathrm{X}) \stackrel{\mathrm{HBr}}{\longr
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\(\mathrm{R}-\mathrm{OH}+\mathrm{HX} \longrightarrow \mathrm{R}-\mathrm{X}+\mathrm{H}_{2} \mathrm{O}\) In the above reaction, the reactivity of different alcoho
View solution Problem 75
The number of isomeric alkyl halides possible for \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{Cl}\) is (a) 5 (b) 6 (c) 4 (d) 8
View solution Problem 77
Chlorination of toluene in the presence of light and heat followed by treatment with aqueous NaOH gives (a) p-cresol (b) o-cresol (c) benzoic acid (d) 2,4 -dihy
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