Problem 74
Question
The reciprocal of a function \(f(x)\) can be written as either \(1 / f(x)\) or \([f(x)]^{-1} .\) The point of this problem is to make clear that a reciprocal of a function has nothing to do with the inverse of a function. As an example, let \(f(x)=x+1, x \in \mathbf{R}\). Find both \([f(x)]^{-1}\) and \(f^{-1}(x)\), and compare the two functions. Graph all three functions together.
Step-by-Step Solution
Verified Answer
The reciprocal is \([f(x)]^{-1} = \frac{1}{x+1}\) and the inverse is \(f^{-1}(x) = x - 1\); they are different functions.
1Step 1: Calculate the Reciprocal of the Function
To determine the reciprocal of the function \(f(x) = x + 1\), we take the expression \([f(x)]^{-1}\), which means we are finding \(1 / f(x)\). Substitute \(f(x)\) as \(x + 1\) into the reciprocal formula:\[ [f(x)]^{-1} = \frac{1}{x+1}. \]
2Step 2: Determine the Inverse of the Function
Finding the inverse of the function \(f(x) = x + 1\) involves swapping the roles of \(x\) and \(y\). Start with \(y = x + 1\). Swap \(x\) and \(y\):\[ x = y + 1. \]Now solve for \(y\):\[ y = x - 1. \] Thus, the inverse function is \(f^{-1}(x) = x - 1\).
3Step 3: Compare the Reciprocal and Inverse Functions
The reciprocal \([f(x)]^{-1} = \frac{1}{x+1}\) and the inverse \(f^{-1}(x) = x - 1\) are fundamentally different. The reciprocal is a transformation of the output of the original function that involves division, while the inverse is a transformation that 'undoes' the function, switching inputs and outputs.
4Step 4: Graph the Functions
To visualize the functions, plot \(f(x) = x + 1\), \([f(x)]^{-1} = \frac{1}{x+1}\), and \(f^{-1}(x) = x - 1\) on a graph.For \(f(x) = x+1\), the graph is a straight line passing through (0, 1) with a slope of 1.For \([f(x)]^{-1} = \frac{1}{x+1}\), the graph is a hyperbola with a vertical asymptote at \(x = -1\) and a horizontal asymptote at \(y = 0\).For \(f^{-1}(x) = x-1\), the graph is also a straight line, but with a slope of 1 passing through (-1, 0).These graphs show the different behaviors of the reciprocal, the original function, and the inverse.
Key Concepts
Inverse FunctionFunction GraphingReal Numbers
Inverse Function
The concept of an inverse function is crucial to understand in mathematics. An inverse function essentially undoes the action of the original function. If you apply a function to a number and then apply its inverse, you'll get back to the original number. For a function to have an inverse, each value of the function must be unique; this is known as a one-to-one correspondence.
To find the inverse of a function, you swap the roles of the input and output. For instance, if you have a function defined as \(y = f(x)\), its inverse is found by solving \(x = f(y)\) in terms of \(y\). Once the inverse is determined, it is usually denoted as \(f^{-1}(x)\).
In the exercise above, for \(f(x) = x + 1\), the inverse is determined by switching \(x\) and \(y\), giving \(y = x - 1\), so \(f^{-1}(x) = x - 1\). This new function will "unwind" the original function, taking us back to our starting point.
To find the inverse of a function, you swap the roles of the input and output. For instance, if you have a function defined as \(y = f(x)\), its inverse is found by solving \(x = f(y)\) in terms of \(y\). Once the inverse is determined, it is usually denoted as \(f^{-1}(x)\).
In the exercise above, for \(f(x) = x + 1\), the inverse is determined by switching \(x\) and \(y\), giving \(y = x - 1\), so \(f^{-1}(x) = x - 1\). This new function will "unwind" the original function, taking us back to our starting point.
Function Graphing
Graphing functions provides a visual way to understand different mathematical concepts, including reciprocals and inverses. Each function has a unique graphical representation, which helps to highlight its properties and behavior.
For the function \(f(x) = x + 1\), the graph appears as a straight line. It has a slope of 1 and crosses the y-axis at (0, 1). This linearity makes it easy to understand how the function behaves across all real numbers.
The reciprocal of this function, \([f(x)]^{-1} = \frac{1}{x+1}\), appears graphically as a hyperbola. The graph of a hyperbola has characteristic asymptotes, which are lines that the graph approaches but never touches. Here, these are the vertical line \(x = -1\) and the horizontal line \(y = 0\). This shows how the values of the reciprocal function stretch out indefinitely as \(x\) approaches -1.
The inverse function \(f^{-1}(x) = x - 1\) also demonstrates a linear graph, similar to the original function but with a different position—shifting down by 2 units. By graphing these functions, students can gain a deeper understanding of how operations like reciprocals and inverses modify function behavior geometrically.
For the function \(f(x) = x + 1\), the graph appears as a straight line. It has a slope of 1 and crosses the y-axis at (0, 1). This linearity makes it easy to understand how the function behaves across all real numbers.
The reciprocal of this function, \([f(x)]^{-1} = \frac{1}{x+1}\), appears graphically as a hyperbola. The graph of a hyperbola has characteristic asymptotes, which are lines that the graph approaches but never touches. Here, these are the vertical line \(x = -1\) and the horizontal line \(y = 0\). This shows how the values of the reciprocal function stretch out indefinitely as \(x\) approaches -1.
The inverse function \(f^{-1}(x) = x - 1\) also demonstrates a linear graph, similar to the original function but with a different position—shifting down by 2 units. By graphing these functions, students can gain a deeper understanding of how operations like reciprocals and inverses modify function behavior geometrically.
Real Numbers
Real numbers are a vast and continuous set of numbers that include both rational and irrational numbers. They form the backbone of many mathematical topics and are essential in functions and their transformations, such as reciprocals and inverses.
In the exercises, all functions were evaluated over real numbers, which means all possible inputs and outputs are considered. This helps in understanding the broader implications and use of these functions universally.
When working with functions like \(f(x) = x + 1\), its inverse \(f^{-1}(x) = x - 1\), and its reciprocal \([f(x)]^{-1} = \frac{1}{x+1}\), the values from the set of real numbers determine where the functions are defined and where they might have restrictions, like avoiding division by zero. It's crucial when graphing to pay attention to these values to ensure accurate representation.
The understanding of real numbers and their properties assists in making sense of concepts like continuity, limits, and behavior of functions across their domain. This foundational knowledge ensures students grasp how mathematical principles apply across different scenarios.
In the exercises, all functions were evaluated over real numbers, which means all possible inputs and outputs are considered. This helps in understanding the broader implications and use of these functions universally.
When working with functions like \(f(x) = x + 1\), its inverse \(f^{-1}(x) = x - 1\), and its reciprocal \([f(x)]^{-1} = \frac{1}{x+1}\), the values from the set of real numbers determine where the functions are defined and where they might have restrictions, like avoiding division by zero. It's crucial when graphing to pay attention to these values to ensure accurate representation.
The understanding of real numbers and their properties assists in making sense of concepts like continuity, limits, and behavior of functions across their domain. This foundational knowledge ensures students grasp how mathematical principles apply across different scenarios.
Other exercises in this chapter
Problem 73
Evaluate the following exponential expressions: (a) \(2^{4} 8^{-2 / 3}\) (b) \(\frac{3^{3} 3^{-1 / 2}}{3^{1 / 2}}\) (c) \(\frac{5^{k}(25)^{k-1}}{5^{2-k}}\)
View solution Problem 74
The following table is based on a functional relationship be tween \(x\) and \(y\) that is either an exponential or a power function: \begin{tabular}{lc} \hline
View solution Problem 74
Evaluate the following exponential expressions: (a) \(\left(2^{4} 2^{-3 / 2}\right)^{2}\) (b) \(\left(\frac{6^{5 / 2} 6^{2 / 3}}{6^{1 / 3}}\right)^{3}\) (c) \(\
View solution Problem 75
The following table is based on a functional relationship between \(x\) and \(y\) that is either an exponential or a power function: \begin{tabular}{cc} \hline
View solution