Problem 74
Question
Solve. Write answers in standard form. $$ -x(7-2 x)=-6-(3-x) $$
Step-by-Step Solution
Verified Answer
The equation has no real roots.
1Step 1: Distribute and simplify both sides
Distribute the \( -x \) across the terms inside the parentheses on the left side of the equation \( -x(7 - 2x) \). This gives \( -7x + 2x^2 \). On the right side, distribute the negative sign across the parentheses \( (3 - x) \) to get \( -6 - 3 + x \). So the equation becomes: \[ 2x^2 - 7x = -9 + x \]
2Step 2: Move all terms to one side
Move all terms to one side of the equation to set it to zero. Subtract \( x \) from both sides: \[ 2x^2 - 7x - x = -9 \] which simplifies to: \[ 2x^2 - 8x = -9 \] Now, add 9 to both sides to get: \[ 2x^2 - 8x + 9 = 0 \]
3Step 3: Solve the quadratic equation
Now we need to solve the quadratic equation \( 2x^2 - 8x + 9 = 0 \). First, identify \( a = 2 \), \( b = -8 \), and \( c = 9 \). Use the quadratic formula \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] to find the roots.
4Step 4: Calculate the discriminant
Calculate the discriminant \( b^2 - 4ac \). Substitute the values: \[ (-8)^2 - 4 \cdot 2 \cdot 9 = 64 - 72 = -8 \] Since the discriminant is negative \( (-8) \), this indicates the equation has no real roots.
Key Concepts
Discriminant in Quadratic EquationsUsing the Quadratic FormulaUnderstanding Quadratic Equations in Standard Form
Discriminant in Quadratic Equations
When solving quadratic equations like the one in this exercise, the discriminant plays a crucial role in determining the nature of the roots. The discriminant is found in the quadratic formula, specifically under the square root symbol: \( \Delta = b^2 - 4ac\).
Here's why it's important:
Here's why it's important:
- If the discriminant is positive, the quadratic equation has two distinct real roots.
- If the discriminant is zero, there is precisely one real root, which means the quadratic has a repeated (or double) root.
- If the discriminant is negative, as in this exercise, the equation has no real roots, indicating that the roots are complex or imaginary.
Using the Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations, which are equations of the form \[ax^2 + bx + c = 0\].
The formula itself is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\].
This formula allows you to find the variable \(x\) by simply substituting the coefficients \(a\), \(b\), and \(c\) from the equation. In practice:
The formula itself is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\].
This formula allows you to find the variable \(x\) by simply substituting the coefficients \(a\), \(b\), and \(c\) from the equation. In practice:
- Calculate the discriminant \(b^2 - 4ac\).
- Substitute the discriminant value and coefficients into the formula.
- Use the plus-minus sign to show that there are potentially two solutions.
Understanding Quadratic Equations in Standard Form
Quadratic equations are often expressed in what is called the "standard form," which is:\[ax^2 + bx + c = 0\].
Here, \(a\), \(b\), and \(c\) are constants, with \(aeq 0\). The standard form is practical because it immediately tells you several things:
Here, \(a\), \(b\), and \(c\) are constants, with \(aeq 0\). The standard form is practical because it immediately tells you several things:
- The coefficient \(a\) indicates the parabola's direction: if \(a > 0\), it opens upwards; if \(a < 0\), it opens downwards.
- The equation can be easily manipulated for further analysis, such as factoring or applying the quadratic formula.
- Having it in this form helps easily identify the coefficients \(a\), \(b\), and \(c\) needed for computations.
Other exercises in this chapter
Problem 73
Solve for the specified variable. $$ V=\frac{1}{3} \pi r^{2} h \text { for } r $$
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For the given representation of a function \(f,\) graph the reflection across the \(x\)-axis and graph the reflection across the \(y\)-axis. Line graph determin
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Solve for the specified variable. $$ V=\frac{1}{2} g t^{2}+h \text { for } t $$
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Two functions, \(f\) and \(g,\) are related by the given equation. Use the numerical representation of \(f\) to make a numerical representation of \(\mathbf{g}\
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