Problem 74
Question
Solve the equation. $$x^{2}-2 x-4=0$$
Step-by-Step Solution
Verified Answer
The solutions for the equation are \(x = 1 + \sqrt{5}\) and \(x = 1 - \sqrt{5}\).
1Step 1: Identify a, b, and c
Here the equation is \(x^{2}-2 x -4 = 0\). So, from the equation we identify \(a = 1\), the coefficient of \(x^2\), \(b = -2\), the coefficient of x, and \(c = -4\), the constant term.
2Step 2: Substitute into the Quadratic Formula
Substitute a, b, and c into the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Thus we have \(x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4*1*(-4)}}{2*1}\). Simplifying this we get \(x = \frac{2 \pm \sqrt{20}}{2}\)
3Step 3: Simplifying Further
Simplify the equation further. The square root of 20 simplifies to \(2\sqrt{5}\). Thus we have \(x = 1 \pm \sqrt{5}\)
Key Concepts
Quadratic FormulaSolving Quadratic EquationsAlgebraic Simplification
Quadratic Formula
The quadratic formula is an essential tool in algebra when it comes to solving quadratic equations. It is a formula that provides the solutions to a quadratic equation of the form \(ax^2 + bx + c = 0\). This formula is
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is exactly one real root.
- A negative discriminant indicates complex roots.
Solving Quadratic Equations
Solving quadratic equations effectively involves following a series of logical steps. The typical methods include factorization, completing the square, and using the quadratic formula. For quadratic equations that are not easily factorable, the quadratic formula is often the most straightforward and reliable approach.
Starting with the equation \(x^2 - 2x - 4 = 0\), identifying \(a\), \(b\), and \(c\) is the first step. These coefficients are crucial for substituting into the quadratic formula. Upon substituting, we simplify and solve for \(x\).
Starting with the equation \(x^2 - 2x - 4 = 0\), identifying \(a\), \(b\), and \(c\) is the first step. These coefficients are crucial for substituting into the quadratic formula. Upon substituting, we simplify and solve for \(x\).
- Use: \(x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \times 1 \times (-4)}}{2 \times 1}\)
- Simplify to solve for \(x\).
Algebraic Simplification
Algebraic simplification is the step where we "clean up" our math expressions. It includes simplifying the expression inside the square root, which often involves recognizing perfect squares or using basic arithmetic to reduce numbers.
In this example, simplifying \(\sqrt{20}\) is crucial. We break it down into its simpler components: write \(\sqrt{20} = \sqrt{4 \times 5}\). Recognizing that \(\sqrt{4} = 2\), we can then express it as \(2\sqrt{5}\). It is crucial at this stage to observe how simplification can change the complexity of a problem, making it easier and less error-prone.
In this example, simplifying \(\sqrt{20}\) is crucial. We break it down into its simpler components: write \(\sqrt{20} = \sqrt{4 \times 5}\). Recognizing that \(\sqrt{4} = 2\), we can then express it as \(2\sqrt{5}\). It is crucial at this stage to observe how simplification can change the complexity of a problem, making it easier and less error-prone.
- Result: \(x = 1 \pm \sqrt{5}\)
Other exercises in this chapter
Problem 74
Use the proportion \(\frac{a}{b}=\frac{b}{d},\) where \(a\) \(\boldsymbol{b},\) and \(\boldsymbol{d}\) are positive numbers. Two numbers have a geometric mean o
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Two numbers have a geometric mean of \(10 .\) One number is 21 less than the other. Find the numbers.
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