Problem 74
Question
Solve each equation for the indicated variable. Assume no denominators are \(0 .\) $$E=\frac{e^{2} k}{2 r}, \quad \text { for } e$$
Step-by-Step Solution
Verified Answer
e = \(\sqrt{\frac{2rE}{k}}\)
1Step 1: Isolate the variable
First, multiply both sides of the equation by the denominator to eliminate it. Multiply both sides by \(2r\): \[2rE = e^2 k\]
2Step 2: Solve for e^2
Next, isolate \(e^2\) by dividing both sides of the equation by \(k\): \[e^2 = \frac{2rE}{k}\]
3Step 3: Take the square root
Finally, solve for \(e\) by taking the square root of both sides of the equation: \[e = \sqrt{\frac{2rE}{k}}\]
Key Concepts
Variable IsolationEliminating DenominatorsSquare Root
Variable Isolation
Variable isolation is an essential concept in algebra. It involves rearranging an equation to get the unknown variable by itself on one side of the equation. This makes it easier to solve for that variable.
For example, in our problem, we are given the equation: \(E=\frac{e^{2} k}{2 r}\) We want to solve for \(e\). To do this, we need to isolate \(e\) by performing operations that cancel out all other terms on the same side of the equation. This usually involves steps like addition, subtraction, multiplication, or division. By following these operations systematically, we can get the variable by itself and find its value.
For example, in our problem, we are given the equation: \(E=\frac{e^{2} k}{2 r}\) We want to solve for \(e\). To do this, we need to isolate \(e\) by performing operations that cancel out all other terms on the same side of the equation. This usually involves steps like addition, subtraction, multiplication, or division. By following these operations systematically, we can get the variable by itself and find its value.
Eliminating Denominators
Eliminating denominators is a crucial step when dealing with equations involving fractions. It simplifies the equation and makes solving it much easier.
In our equation: \(E=\frac{e^{2} k}{2 r}\) The denominator is \(2r\). To eliminate this denominator, we multiply both sides of the equation by \(2r\). This gives us: \(2rE = e^2 k\) By removing the fraction, the equation becomes simpler and more straightforward to solve. Now, we can focus on isolating the variable \(e\).
In our equation: \(E=\frac{e^{2} k}{2 r}\) The denominator is \(2r\). To eliminate this denominator, we multiply both sides of the equation by \(2r\). This gives us: \(2rE = e^2 k\) By removing the fraction, the equation becomes simpler and more straightforward to solve. Now, we can focus on isolating the variable \(e\).
Square Root
Taking the square root is a common method used when solving equations that involve squares of a variable. It helps in finding the value of the variable that, when squared, gives the original number.
Let's look at the equation: \(2rE = e^2 k\) To isolate \(e\), we first divide both sides by \(k\) to get: \(e^2=\frac{2rE}{k}\) Finally, we take the square root of both sides to solve for \(e\): \(e = \underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{ \text }\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\text{\text }\text{ \text \text }\underline{\phantom{xxx}}\text{\text }\text{ \text\text\underline{\phantom{xxx}}\text{\text{\text\text{\text{\text\text{\text\text\text\text{\text{\text}\text\text{text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text(text \text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text \text{\text{text: \taking the square root of both sides we finally solve and find: \) \text 'text '\text}\frac{2rE}{k}\( : \text}{e = } Linking the square root is crucial here as it simplifies finding exact value of the var:si:ng the unknown and helps arrive at the solution easier. With this, we know the complete solution for }\text \text} variable \) ‘value’ $' text.}is e is value
Let's look at the equation: \(2rE = e^2 k\) To isolate \(e\), we first divide both sides by \(k\) to get: \(e^2=\frac{2rE}{k}\) Finally, we take the square root of both sides to solve for \(e\): \(e = \underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{ \text }\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\underline{\phantom{xxx}}\underline{\phantom{xxx}}\text{\text }\underline{\phantom{xxx}}\text{\text }\text{ \text \text }\underline{\phantom{xxx}}\text{\text }\text{ \text\text\underline{\phantom{xxx}}\text{\text{\text\text{\text{\text\text{\text\text\text\text{\text{\text}\text\text{text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text(text \text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text\text \text{\text{text: \taking the square root of both sides we finally solve and find: \) \text 'text '\text}\frac{2rE}{k}\( : \text}{e = } Linking the square root is crucial here as it simplifies finding exact value of the var:si:ng the unknown and helps arrive at the solution easier. With this, we know the complete solution for }\text \text} variable \) ‘value’ $' text.}is e is value
Other exercises in this chapter
Problem 74
Solve each rational inequality. Write each solution set in interval notation. $$\frac{3}{x-2}
View solution Problem 74
Solve each equation. $$(x-3)^{2 / 5}=(4 x)^{1 / 5}$$
View solution Problem 74
For each function as defined that is one-to-one, (a) write an equation for the inverse function in the form y = ƒ -11x2, (b) graph ƒ and ƒ -1 on the same axes,
View solution Problem 75
Find each quotient. Write the answer in standard form \(a+b i .\) $$\frac{-5}{i}$$
View solution