Problem 74
Question
In Problems \(71-74\), convert the given equation to rectangular coordinates. $$ \rho \sin ^{2} \phi=\cos \phi $$
Step-by-Step Solution
Verified Answer
The equation in rectangular coordinates is \( x^2 + y^2 = z \).
1Step 1: Understand the Given Equation
The equation \( \rho \sin^2 \phi = \cos \phi \) is given in spherical coordinates. Spherical coordinates consist of \( \rho \) (the radial distance), \( \phi \) (the polar angle), and \( \theta \) (the azimuthal angle). Our task is to convert this equation into rectangular coordinates \( (x, y, z) \).
2Step 2: Recall Relationships Between Spherical and Rectangular Coordinates
In spherical coordinates, \( \rho = \sqrt{x^2 + y^2 + z^2} \), \( \sin \phi = \frac{r}{\rho} \) where \( r = \sqrt{x^2 + y^2} \), and \( \cos \phi = \frac{z}{\rho} \). We'll use these relationships for the conversion.
3Step 3: Substitute Spherical Coordinate Expressions
Substitute \( \sin \phi = \frac{r}{\rho} \) and \( \cos \phi = \frac{z}{\rho} \) into the equation. Therefore, \( \rho \left( \frac{r}{\rho} \right)^2 = \frac{z}{\rho} \), simplifying to \( \frac{r^2}{\rho} = \frac{z}{\rho} \).
4Step 4: Remove \( \rho \) from the Equation
We can cancel \( \rho \) from both sides (assuming \( \rho eq 0 \)), resulting in \( r^2 = z \). Recall that \( r^2 = x^2 + y^2 \), giving us \( x^2 + y^2 = z \).
5Step 5: Write the Equation in Rectangular Coordinates
The equation in rectangular coordinates is \( x^2 + y^2 = z \).
Key Concepts
Spherical CoordinatesRectangular CoordinatesCoordinate TransformationMathematical Problem Solving
Spherical Coordinates
Spherical coordinates offer a convenient way to describe the position of a point in three-dimensional space. Unlike rectangular coordinates, which rely on the orthogonal x, y, and z axes, spherical coordinates use three values:
- \( \rho \): The radial distance from the origin to the point.
- \( \phi \): The polar angle measured from the positive z-axis.
- \( \theta \): The azimuthal angle, akin to longitude, measured in the xy-plane from the positive x-axis.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, employ a perpendicular triple-axis system (x, y, z) to specify a point's location. This method breaks down space into three dimensions, making it intuitive for many geometry and algebra problems.
- x-axis: Measures horizontal distance.
- y-axis: Measures vertical distance perpendicular to the x-axis.
- z-axis: Extends into the third dimension, perpendicular to both x and y axes.
Coordinate Transformation
Coordinate transformation involves changing the way a point's position is described. Moving from spherical to rectangular coordinates requires specific relationships between these two systems:
- Radial distance \(\rho\) is equal to the three-dimensional vector length, \(\sqrt{x^2 + y^2 + z^2}\).
- Polar angle \(\phi\) relates to the vertical elevation, expressed as \(\cos \phi = \frac{z}{\rho}\), and \(\sin \phi = \frac{\sqrt{x^2 + y^2}}{\rho}\).
- Azimuthal angle \(\theta\) has no direct influence in this problem since the original equation does not include \(\theta\).
Mathematical Problem Solving
Solving mathematical problems, particularly those involving coordinate transformations, requires a clear understanding of the relationships between different systems. Initially, it's crucial to comprehend the question and system you're working in. Retain fundamental relations and properties of each coordinate system at your fingertips.
- Identify the Coordinates: Recognize spherical components \(\rho, \phi, \theta\).
- Apply Known Formulas: Use relationships like \(\sin \phi\) and \(\cos \phi\) for transformations.
- Transform Methodically: Carefully substitute and simplify to switch to rectangular form.
- Check Your Result: Transformations should maintain the essence of the original equation in a new form.
Other exercises in this chapter
Problem 72
Convert the given equation to rectangular coordinates. $$ \phi=\pi / 3 $$
View solution Problem 73
In Problems \(71-74\), convert the given equation to rectangular coordinates. $$ \rho=2 \sec \phi $$
View solution Problem 75
In Problems \(75-78\), find the volume of the solid that is bounded by the graphs of the given equations. $$ z=\sqrt{x^{2}+y^{2}}, x^{2}+y^{2}+z^{2}=9 $$
View solution Problem 76
In Problems \(75-78\), find the volume of the solid that is bounded by the graphs of the given equations. $$ x^{2}+y^{2}+z^{2}=4, y=x, y=\sqrt{3} x, z=0, \text
View solution