Problem 74 - Chemistry: The Central Science

Question

Give the chemical formula for each of the following ionic compounds: (a) sodium phosphate, (b) zinc nitrate, (c) barium bromate, (d) iron(II) perchlorate, (e) cobalt(II) hydrogen carbonate, (f) chromium(III) acetate, (g) potassium dichromate.

Step-by-Step Solution

Answer

(a) \( \text{Na}_3\text{PO}_4 \), (b) \( \text{Zn(NO}_3\text{)\(_2\) \), (c) \( \text{Ba(BrO}_3\text{)\(_2\) \), (d) \( \text{Fe(ClO}_4\text{)\(_2\) \), (e) \( \text{Co(HCO}_3\text{)\(_2\) \), (f) \( \text{Cr(CH}_3\text{COO)\(_2\) \), (g) \( \text{K}_2\text{Cr}_2\text{O}_7 \).

Step 1: (a) Sodium Phosphate

: Sodium phosphate is composed of sodium ions (Na⁺) and phosphate ions (PO₄³⁻). In order to create a neutral compound, we need three sodium ions for one phosphate ion, giving us the chemical formula: \( \text{Na}_3\text{PO}_4 \)

Step 2: (b) Zinc Nitrate

: Zinc Nitrate is composed of zinc ions (Zn²⁺) and nitrate ions (NO₃⁻). In order to create a neutral compound, we need one zinc ion for two nitrate ions, giving us the chemical formula: \( \text{Zn(NO}_3\text{)\(_2\) \)

Step 3: (c) Barium Bromate

: Barium bromate is composed of barium ions (Ba²⁺) and bromate ions (BrO₃⁻). In order to create a neutral compound, we need one barium ion for two bromate ions, giving us the chemical formula: \( \text{Ba(BrO}_3\text{)\(_2\) \)

Step 4: (d) Iron(II) Perchlorate

: Iron(II) perchlorate is composed of iron(II) ions (Fe²⁺) and perchlorate ions (ClO₄⁻). In order to create a neutral compound, we need one iron(II) ion for two perchlorate ions, giving us the chemical formula: \( \text{Fe(ClO}_4\text{)\(_2\) \)

Step 5: (e) Cobalt(II) Hydrogen Carbonate

: Cobalt(II) hydrogen carbonate is composed of cobalt(II) ions (Co²⁺) and hydrogen carbonate ions (HCO₃⁻). In order to create a neutral compound, we need one cobalt(II) ion for two hydrogen carbonate ions, giving us the chemical formula: \( \text{Co(HCO}_3\text{)\(_2\) \)

Step 6: (f) Chromium(II) Acetate

: Chromium(II) acetate is composed of chromium(II) ions (Cr²⁺) and acetate ions (CH₃COO⁻). In order to create a neutral compound, we need one chromium(II) ion for two acetate ions, giving us the chemical formula: \( \text{Cr(CH}_3\text{COO)\(_2\) \)

Step 7: (g) Potassium Dichromate

: Potassium dichromate is composed of potassium ions (K⁺) and dichromate ions (Cr₂O₇²⁻). In order to create a neutral compound, we need two potassium ions for one dichromate ion, giving us the chemical formula: \( \text{K}_2\text{Cr}_2\text{O}_7 \)