Problem 74
Question
For exercises \(55-86\), use prime factorization to find the least common multiple. $$ 21 x^{3} y^{5} ; 84 x y^{2} $$
Step-by-Step Solution
Verified Answer
84 x^3 y^5
1Step 1: Find Prime Factorization of 21
The prime factorization of 21 is: \[ 21 = 3 \times 7 \]
2Step 2: Find Prime Factorization of 84
The prime factorization of 84 is: \[ 84 = 2^2 \times 3 \times 7 \]
3Step 3: Determine the Highest Powers of Each Prime Factor
Identify the highest power of each prime factor in the factorizations of 21 and 84. Prime factors are 2, 3, and 7. The highest powers are: \[ 2^2, 3^1, 7^1 \]
4Step 4: Find the Least Common Multiple of Numerical Part
The least common multiple (LCM) of the numerical part 21 and 84 is: \[ LCM = 2^2 \times 3 \times 7 = 84 \]
5Step 5: Find LCM of Variable Part
For the variable part, use the highest power of each variable found in the terms: \[ x^3, y^5 \]
6Step 6: Combine Results
Combine the numerical LCM and the variable parts to get the final LCM: \[ LCM = 84 x^3 y^5 \]
Key Concepts
prime factorizationhighest powersvariables in LCM
prime factorization
Prime factorization is the process of breaking down a composite number into a product of its prime factors. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves.
To find the prime factorization, you can keep dividing the number by the smallest possible prime number until you are left with prime numbers.
For example, in this exercise, the prime factorizations were found as follows:
1. For 21: We divide by 3 (smallest prime factor of 21), then by 7. This gives: \(21 = 3 \times 7\)
2. For 84: We first divide by 2 (smallest prime factor of 84), then again by 2. Next, we divide by 3, and finally by 7. This gives: \(84 = 2^2 \times 3 \times 7\)
To find the prime factorization, you can keep dividing the number by the smallest possible prime number until you are left with prime numbers.
For example, in this exercise, the prime factorizations were found as follows:
1. For 21: We divide by 3 (smallest prime factor of 21), then by 7. This gives: \(21 = 3 \times 7\)
2. For 84: We first divide by 2 (smallest prime factor of 84), then again by 2. Next, we divide by 3, and finally by 7. This gives: \(84 = 2^2 \times 3 \times 7\)
highest powers
When finding the least common multiple (LCM), it is crucial to find the highest powers of all prime factors involved. This ensures that the LCM is divisible by each original number.
Here’s how to determine the highest powers:
1. List out all prime factors from both numbers.
2. For each prime factor, use the highest exponent found in the factorizations.
In this example, the prime factors are 2, 3, and 7. Their highest powers are:\[2^2, 3^1, \text{and} 7^1\]. These are the values we use in calculating the LCM for the numerical part.
Here’s how to determine the highest powers:
1. List out all prime factors from both numbers.
2. For each prime factor, use the highest exponent found in the factorizations.
In this example, the prime factors are 2, 3, and 7. Their highest powers are:\[2^2, 3^1, \text{and} 7^1\]. These are the values we use in calculating the LCM for the numerical part.
variables in LCM
The Least Common Multiple (LCM) also includes the variable parts in algebraic expressions. To include variables, follow the same steps for prime factors:
1. Identify all variables in the expressions.
2. For each variable, find the highest power present.
In our example, the expressions have variables \(x\) and \(y\):
Combining these results with the numerical LCM gives us the final LCM: \( 84 x^3 y^5 \).
1. Identify all variables in the expressions.
2. For each variable, find the highest power present.
In our example, the expressions have variables \(x\) and \(y\):
- From \( x^3 y^5 \), we have \( x^3 \) and \( y^5 \).
- From \( 84xy^2 \), we have \( x \) and \( y^2 \).
Combining these results with the numerical LCM gives us the final LCM: \( 84 x^3 y^5 \).
Other exercises in this chapter
Problem 73
For exercises \(55-86\), use prime factorization to find the least common multiple. $$ 28 x^{2} y^{5} ; 84 x y^{3} $$
View solution Problem 73
For exercises 39-82, simplify. $$ \frac{5 b+15}{4 b+4} \div \frac{2 b+6}{7 b+7} $$
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For exercises \(67-82\), use the five steps and a proportion. In 2010 , about \(2,465,940\) Americans died. Find the number of Americans who died without a will
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For exercises \(75-78\), one part of simplifying a rational expression is completed. Problem: To simplify \(\frac{\frac{4}{15 x}}{\frac{8}{15}}\), rewrite the e
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