Problem 74
Question
Find the exact values of the six trigonometric functions of \(\theta\) if \(\theta\) is in standard position and \(P\) is on the terminal side. $$P(-1,2)$$
Step-by-Step Solution
Verified Answer
Sine: \( \frac{2\sqrt{5}}{5} \), Cosine: \( \frac{-\sqrt{5}}{5} \), Tangent: \(-2\), Cotangent: \(-\frac{1}{2}\), Secant: \(-\sqrt{5}\), Cosecant: \(\sqrt{5}\).
1Step 1: Identify the Given Point
We are given the coordinates of point \( P(-1, 2) \). This means that \( x = -1 \) and \( y = 2 \) in the coordinate plane.
2Step 2: Calculate the Distance from Origin - r
To find the value of \( r \), which is the distance from the origin to the point \( P \), we use the distance formula: \[ r = \sqrt{x^2 + y^2} \]Substituting the given values:\[ r = \sqrt{(-1)^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \]
3Step 3: Calculate Sine and Cosine
The sine of \( \theta \) is the ratio of \( y \) to \( r \):\[ \sin(\theta) = \frac{y}{r} = \frac{2}{\sqrt{5}} \]The cosine of \( \theta \) is the ratio of \( x \) to \( r \):\[ \cos(\theta) = \frac{x}{r} = \frac{-1}{\sqrt{5}} \]
4Step 4: Calculate Tangent and Cotangent
The tangent of \( \theta \) is the ratio of \( y \) to \( x \):\[ \tan(\theta) = \frac{y}{x} = \frac{2}{-1} = -2 \]The cotangent is the reciprocal of tangent:\[ \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{-1}{2} \]
5Step 5: Calculate Secant and Cosecant
The secant of \( \theta \) is the reciprocal of cosine:\[ \sec(\theta) = \frac{1}{\cos(\theta)} = -\sqrt{5} \]The cosecant is the reciprocal of sine:\[ \csc(\theta) = \frac{1}{\sin(\theta)} = \sqrt{5} \]
6Step 6: Simplify Trigonometric Functions
Rationalize the denominators where necessary. For the sine and cosine functions, we rationalize:\[ \sin(\theta) = \frac{2\sqrt{5}}{5} \]\[ \cos(\theta) = \frac{-\sqrt{5}}{5} \]
Key Concepts
Right Triangle TrigonometryRatios and ProportionsCoordinate Geometry
Right Triangle Trigonometry
Right triangle trigonometry is a foundational concept in mathematics, allowing us to explore relationships between angles and side lengths in triangles. A right triangle has one 90-degree angle, and the sides are labeled relative to another angle, namely the opposite, adjacent, and hypotenuse. These sides are used to define six trigonometric functions:
- Sine (\( \sin \theta \) ) is the ratio of the opposite side to the hypotenuse.
- Cosine (\( \cos \theta \) ) is the ratio of the adjacent side to the hypotenuse.
- Tangent (\( \tan \theta \) ) is the ratio of the opposite side to the adjacent side.
- Cosecant (\( \csc \theta \) ) is the reciprocal of sine.
- Secant (\( \sec \theta \) ) is the reciprocal of cosine.
- Cotangent (\( \cot \theta \) ) is the reciprocal of tangent.
Ratios and Proportions
Ratios and proportions are essential mathematical concepts that describe how quantities relate to each other. A ratio is a comparative value between two or more quantities, indicating how many times one value contains or is contained within the other. For instance, in trigonometry, the ratios of sides in right triangles form the basis of trigonometric functions.A proportion, on the other hand, states that two ratios are equal. In our exercise, the trigonometric functions such as sine, cosine, and tangent create proportions between the sides of a right triangle and help solve unknowns. For instance:
- \( \sin(\theta) = \frac{y}{r} \): This expresses the ratio of the length of the opposite side (y) to the hypotenuse (r).
- Rationalizing denominators involves maintaining proportions in simplified forms, such as converting \( \frac{2}{\sqrt{5}} \) to \( \frac{2\sqrt{5}}{5} \).
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, integrates algebra and geometry to define and solve geometric problems through coordinate systems. Points are represented as coordinate pairs \((x, y)\), which are distances from the perpendicular lines of the x-axis and y-axis, respectively.In the context of trigonometric problems in the coordinate plane:
- The point \((-1, 2)\) helps identify the position of an angle's terminal side when theta is in standard position, showing direction from the origin.
- The distance from the origin (\(r\)) is calculated using the distance formula: \( r = \sqrt{x^2 + y^2} \).
- Once r is determined, it sets the stage for determining trigonometric function values by creating a right triangle with x and y as perpendicular components.
Other exercises in this chapter
Problem 73
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