Problem 74
Question
Examine the nature of the roots of the quadratic \((b-x)^{2}-4(a-x)(c-x)=0\) where \(a, b, c\) are real.
Step-by-Step Solution
Verified Answer
In the given quadratic equation \((b-x)^{2}-4(a-x)(c-x)=0\), the discriminant is given by \(\Delta = (2b - 4a - 4c)^2 - 4(-3)(4ad - 4ac + b^2 + 4bd)\). However, due to the complexity of the discriminant expression, providing general conditions on \(a, b, c\) for the nature of the roots is not feasible. To investigate the roots' nature for specific cases, we can substitute specific values of \(a, b, c\) and analyze the resulting discriminant value to determine if the roots are real and distinct, real and equal, or complex.
1Step 1: Write the quadratic equation in standard form
We begin by expressing the given quadratic equation in the standard quadratic form, i.e., \(Ax^2 + Bx + C = 0\). This will help us in calculating the discriminant easily.
Given, \((b-x)^{2}-4(a-x)(c-x)=0\)
2Step 2: Expand and simplify the equation
Now, let's expand and simplify the equation:
\((b^2 -2bx + x^2) - 4(ac - ad + cx - xd + ax - bd + x^2 - xd) = 0\)
3Step 3: Collect terms and rewrite the equation
Group the terms with similar powers of x:
\(x^2 - 2bx + b^2 - 4ac + 4ad - 4cx + 4xd - 4ax + 4bd - 4x^2 + 4xd = 0\)
Combine the like terms:
\(-3x^2 + 4ad - 4ac + 2bx + b^2 + 4bd - 4ax - 4cx = 0\)
4Step 4: Calculate the discriminant
The discriminant of a quadratic equation \(Ax^2 + Bx + C = 0\) is given by \(\Delta = B^2 - 4AC\). From the equation in step 3, we have:
\(A = -3\)
\(B = 2b - 4a - 4c\)
\(C = 4ad - 4ac + b^2 + 4bd\)
Now, calculate the discriminant \(\Delta\):
\(\Delta = (2b - 4a - 4c)^2 - 4(-3)(4ad - 4ac + b^2 + 4bd)\)
5Step 5: Simplify and analyze the discriminant
As we know, the nature of the roots can be determined by the discriminant value:
- If \(\Delta > 0\), roots are real and distinct.
- If \(\Delta = 0\), roots are real and equal.
- If \(\Delta < 0\), roots are complex.
The task is to examine the nature of the roots given that \(a, b, c\) are real numbers. For this case, we need to find the conditions on \(a, b, c\) that will make \(\Delta\) positive, negative, or zero. However, due to the complexity of the discriminant expression, it is not possible to provide a straightforward analysis or general conditions for the roots' nature for all real numbers \(a, b, c\).
An approach to analyze the roots' nature would be to solve the discriminant expression for specific values of \(a, b, c\) and observe the conditions leading to different roots' natures.
Key Concepts
Discriminant AnalysisNature of RootsReal and Complex Numbers
Discriminant Analysis
The discriminant plays a crucial role in understanding the nature of the roots of a quadratic equation. It is derived from the standard form of the quadratic equation, \(Ax^2 + Bx + C = 0\), and is defined as \(\Delta = B^2 - 4AC\). By calculating this value, we can determine how the roots will behave.
From here, the calculation of \(\Delta\) involves identifying the coefficients (\(A = -3\), \(B = 2b - 4a - 4c\), \(C = 4ad - 4ac + b^2 + 4bd\)) and substituting them into the formula, providing insight into the potential nature of the roots for different real numbers \(a, b, c\).
- If \(\Delta > 0\), the quadratic equation has two distinct real roots.
- If \(\Delta = 0\), the equation has exactly one real root (a repeated root).
- If \(\Delta < 0\), the equation has two complex roots.
From here, the calculation of \(\Delta\) involves identifying the coefficients (\(A = -3\), \(B = 2b - 4a - 4c\), \(C = 4ad - 4ac + b^2 + 4bd\)) and substituting them into the formula, providing insight into the potential nature of the roots for different real numbers \(a, b, c\).
Nature of Roots
The nature of the roots of a quadratic equation depends on the value of the discriminant \(\Delta\), which reveals what kind of solutions can be expected.
### Real RootsReal roots occur when \(\Delta \geq 0\).
Exploring the nature of roots for the equation \((b-x)^2 - 4(a-x)(c-x) = 0\) requires examining \(\Delta\) for specific cases of \(a, b, c\). This complexity often necessitates technological assistance or special cases to solve definitively.
### Real RootsReal roots occur when \(\Delta \geq 0\).
- If \(\Delta = 0\), the roots are real and repeated, meaning the parabola touches the x-axis at only one point.
- If \(\Delta > 0\), the roots are real and distinct, indicating that the parabola intersects the x-axis at two different points.
Exploring the nature of roots for the equation \((b-x)^2 - 4(a-x)(c-x) = 0\) requires examining \(\Delta\) for specific cases of \(a, b, c\). This complexity often necessitates technological assistance or special cases to solve definitively.
Real and Complex Numbers
Understanding real and complex numbers is essential when analyzing quadratic equations. Real numbers include all the typical numbers we encounter in daily life: positive numbers, negative numbers, and zero. These are the numbers that appear on the standard number line.
However, not all quadratic equations have solutions among real numbers alone. When the discriminant \(\Delta\) is negative, the roots are complex. Complex numbers are numbers that include the imaginary unit \(i\), where \(i^2 = -1\). They are typically expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers.
However, not all quadratic equations have solutions among real numbers alone. When the discriminant \(\Delta\) is negative, the roots are complex. Complex numbers are numbers that include the imaginary unit \(i\), where \(i^2 = -1\). They are typically expressed in the form \(a + bi\), where \(a\) and \(b\) are real numbers.
- Real Numbers: Solutions appear on the x-axis (\(\Delta \geq 0\)).
- Complex Numbers: Solutions extend into the complex plane (\(\Delta < 0\)).
Other exercises in this chapter
Problem 72
For what values of \(m\) the function \(m x^{2}-9 m x+5 m+1\) is negative for all \(x\) ?
View solution Problem 73
Prove that the roots of \((x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0\) are always real and they will be equal if and only if \(a=b=c\).
View solution Problem 75
Show that the equation \(a x^{2}+b x+c=0\) where \(a, b, c\) are real numbers connected by the relation \(4 a+2 b+c=0\) and \(a b>0\) has real roots.
View solution Problem 76
If the roots of the equation \(x^{2}-a x+b=0\) are real and differ by a quantity which is less than \(c(c>0)\), then \(b\) lies between \(\frac{a^{2}-c^{2}}{4}\
View solution