Problem 74
Question
An engine of power \(7500 \mathrm{~W}\) makes a train move on a horizontal surface with constant velocity of \(20 \mathrm{~ms}^{-1} .\) The force involved in the problem is (a) \(375 \mathrm{~N}\) (b) \(400 \mathrm{~N}\) (c) \(500 \mathrm{~N}\) (d) \(600 \mathrm{~N}\)
Step-by-Step Solution
Verified Answer
The force involved is 375 N.
1Step 1: Understanding the Problem
We need to find the force exerted by the engine on the train as it moves with a constant velocity on a horizontal surface. We are given the power of the engine as 7500 W and the velocity as 20 m/s.
2Step 2: Using the Power Formula
The formula relating power, force, and velocity is given by: \[ P = F \times v \] where \( P \) is the power in watts, \( F \) is the force in newtons, and \( v \) is the velocity in meters per second. We can rearrange this formula to solve for the force \( F \) as:\[ F = \frac{P}{v} \]
3Step 3: Substitute the Known Values
Substitute the given values into the formula:\[ F = \frac{7500}{20} \]
4Step 4: Calculate the Force
Perform the division to find the force:\[ F = 375 \text{ N} \] This means the force involved is 375 N.
Key Concepts
Power and Force RelationshipPhysics FormulasNewton's Laws of Motion
Power and Force Relationship
The power and force relationship is a fundamental concept in physics, especially when understanding how machines work. Power signifies the rate at which work is done, and it relates directly to force and velocity. In the problem involving a train on a horizontal surface, we learn that power (P) connects to force (F) by the equation:
- \( P = F \times v \)
- Power (\( P \)): It is the energy transfer per unit time, measured in watts (W).
- Force (\( F \)): Causes the train to move and is measured in newtons (N).
- Velocity (\( v \)): Constant speed of the object, in meters per second (m/s).
Physics Formulas
Physics relies on several essential formulas that relate different physical quantities. They serve as tools to interpret and calculate unseen forces and motions around us. Let's highlight one crucial equation from the original exercise:
To solve practical problems, understanding and using these formulas is vital:
- Power Equation: \( P = F \times v \)
To solve practical problems, understanding and using these formulas is vital:
- Identify the known quantities – these are parameters like power, speed, force.
- Choose the appropriate formula – like the power equation, so it fits the situations described.
- Re-arrange the equation – solve for the unknown, by using algebraic manipulation.
Newton's Laws of Motion
Newton's Laws of Motion underpin almost every principle of classical mechanics, and are crucial when solving dynamics problems. The scenario with the train involves concepts from these laws:
These laws form the foundation of relationships discussed, guiding steps in determining forces in motion.
- First Law (Inertia): An object stays at rest or moves at a constant velocity unless acted upon by a net external force.
- Second Law (Force and Acceleration): The principle expressed by \( F = ma \) indicates how force relates to mass and acceleration.
- Third Law (Action and Reaction): For every action, there is an equal and opposite reaction.
These laws form the foundation of relationships discussed, guiding steps in determining forces in motion.
Other exercises in this chapter
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