Problem 74
Question
A sample of \(3.00 \mathrm{~g}\) of \(\mathrm{SO}_{2}(g)\) originally in a \(5.00-\mathrm{L}\) vessel at \(21^{\circ} \mathrm{C}\) is transferred to a \(10.0-\mathrm{L}\) vessel at \(26^{\circ} \mathrm{C}\). A sample of \(2.35 \mathrm{~g}\) of \(\mathrm{N}_{2}(g)\) originally in a \(2.50-\mathrm{L}\) vessel at \(20^{\circ} \mathrm{C}\) is transferred to this same \(10.0-\mathrm{L}\) vessel. (a) What is the partial pressure of \(\mathrm{SO}_{2}(g)\) in the larger container? (b) What is the partial pressure of \(\mathrm{N}_{2}(g)\) in this vessel? (c) What is the total pressure in the vessel?
Step-by-Step Solution
Verified Answer
The partial pressure of SO2 is 0.115 atm, the partial pressure of N2 is 0.206 atm, and the total pressure is 0.321 atm.
1Step 1: Calculate Initial Moles of SO2
First, calculate the number of moles of SO2 using its molar mass. The molar mass of SO2 is approximately 64.07 g/mol. Use the formula: \( n = \frac{m}{M} \) where \( m = 3.00 \text{ g} \) and \( M = 64.07 \text{ g/mol} \). This gives: \( n = \frac{3.00}{64.07} = 0.0468 \text{ mol} \).
2Step 2: Apply Ideal Gas Law for SO2 in New Conditions
Next, use the ideal gas law in the new conditions to find the partial pressure \( P \) of SO2 in the 10.0-L vessel at 26°C. Convert the temperature to Kelvin: \( T = 26 + 273.15 = 299.15 \text{ K} \). The ideal gas equation is \( PV = nRT \). Solve for \( P \): \( P = \frac{nRT}{V} = \frac{0.0468 \times 0.0821 \times 299.15}{10.0} = 0.115 \text{ atm} \).
3Step 3: Calculate Initial Moles of N2
Calculate the number of moles of N2 using its molar mass. The molar mass of N2 is approximately 28.02 g/mol. Use the formula: \( n = \frac{m}{M} \) where \( m = 2.35 \text{ g} \) and \( M = 28.02 \text{ g/mol} \). This gives: \( n = \frac{2.35}{28.02} = 0.0839 \text{ mol} \).
4Step 4: Apply Ideal Gas Law for N2 in New Conditions
Use the ideal gas law for N2 in the new vessel conditions. The temperature 26°C is converted to Kelvin: \( T = 299.15 \text{ K} \). Use the ideal gas law: \( P = \frac{nRT}{V} = \frac{0.0839 \times 0.0821 \times 299.15}{10.0} = 0.206 \text{ atm} \).
5Step 5: Calculate Total Pressure in the Vessel
The total pressure in the vessel is the sum of the partial pressures of SO2 and N2. Total pressure \( P_{total} = P_{SO2} + P_{N2} = 0.115 + 0.206 = 0.321 \text{ atm} \).
Key Concepts
Partial PressureMoles CalculationTemperature Conversion
Partial Pressure
Partial pressure is an essential concept when dealing with gas mixtures. It represents the pressure exerted by an individual gas within a mixture if it alone occupied the entire volume of the container, under the same temperature conditions. This concept is derived from Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas. Let's consider an example with gases SO₂ and N₂ in a 10.0-L vessel. To find the partial pressure of SO₂, we use the ideal gas law formula: \[ P = \frac{nRT}{V} \]Where:
- \( n \) is the number of moles of the gas,
- \( R \) is the ideal gas constant (0.0821 atm•L/mol•K),
- \( T \) is the temperature in Kelvin, and
- \( V \) is the volume of the container.
Moles Calculation
Calculating moles is key for determining how gases behave under different conditions. The mole is a standard scientific unit used to measure large quantities of very small entities, such as atoms or molecules. To find the number of moles, you can use the formula:\[ n = \frac{m}{M} \]Where:
- \( n \) is the number of moles,
- \( m \) is the mass of the substance (in grams), and
- \( M \) is the molar mass of the substance (grams per mole).
Temperature Conversion
Temperature conversion is a critical initial step in gas law calculations. Gases behave differently at different temperatures, and the ideal gas law formula \( PV = nRT \) requires that temperature is in Kelvin. This is because Kelvin is an absolute temperature scale based on the molecular motion, where 0 K is absolute zero, the point at which molecular motion ceases entirely.To convert Celsius to Kelvin, use the formula:\[ T(K) = T(°C) + 273.15 \]For example, an initial temperature of 26°C must be converted to Kelvin:\[ T = 26 + 273.15 = 299.15 \text{ K} \]This converted temperature is then used in subsequent calculations involving the ideal gas law. Properly converting temperature ensures accurate calculations and predictions of gas behavior. Missteps in conversion can lead to significant errors, as the precision of gas law calculations hinges on accurate temperature values.
Other exercises in this chapter
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