Problem 74
Question
\(71-76\) m simplify the expression. (This type of expression arises in calculus when using the "quotient rule.") $$ \frac{\left(1-x^{2}\right)^{1 / 2}+x^{2}\left(1-x^{2}\right)^{-1 / 2}}{1-x^{2}} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \( (1-x^2)^{-3/2} \).
1Step 1: Recognize the Problem Type
This expression involves square roots and a function in the denominator. Simplifying expressions like this is often seen in calculus problems when using rules like the quotient rule.
2Step 2: Expand the Expression
The given expression is \( \frac{(1-x^2)^{1/2} + x^2(1-x^2)^{-1/2}}{1-x^2} \). A common technique is to combine terms under the square root for a clearer form.
3Step 3: Simplify the Numerator
Rewriting the numerator \((1-x^2)^{1/2} + x^2(1-x^2)^{-1/2}\), we combine these under a common denominator: \(\frac{(1-x^2) + x^2}{(1-x^2)^{1/2}}\). This simplifies to: \( \frac{1}{(1-x^2)^{1/2}}\).
4Step 4: Simplify the Overall Expression
Now divide the simplified numerator \( \frac{1}{(1-x^2)^{1/2}} \) by the denominator \( 1-x^2 \). This simplifies to \( \frac{1}{(1-x^2)^{3/2}} \).
5Step 5: Review the Simplified Expression
The expression is now fully simplified as \( (1-x^2)^{-3/2} \). Ensure no further simplifications are available.
Key Concepts
Simplifying ExpressionsQuotient RuleSquare RootsFunction Simplification
Simplifying Expressions
Simplifying expressions is all about making complex mathematical expressions easier to work with. It involves reducing an expression to its most basic form. The process makes calculation and understanding more straightforward. In calculus, simplification often involves:
- Combining like terms.
- Breaking down complex fractions.
- Using algebraic identities to condense expressions.
Quotient Rule
The quotient rule is a method used in calculus to find the derivative of a quotient of two functions. Essentially, if you have a function that is the division of two separate functions, you'll use this rule. The quotient rule can be given by:\[\frac{d}{dx}\left(\frac{u(x)}{v(x)}\right) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2}\]Where:
- v(x) are functions of x.
- u'(x) and v'(x) are derivatives of u(x) and v(x) respectively.
Square Roots
Square roots challenge students because they involve finding a number that gives the original number when squared. In expressions, radical symbols or fractional exponents represent square roots. For example, \((1-x^2)^{1/2}\) and \((1-x^2)^{-1/2}\) signify the presence of square roots. When working with such expressions:
- Seek to find common bases to simplify them.
- Recognize that \((a)^{1/2}\) is the same as \(\sqrt{a}\).
- Understand that negative exponents, like \((1-x^2)^{-1/2}\), reflect reciprocal square roots.
Function Simplification
Function simplification in calculus refers to the process of changing a complex function into a simpler form. Simplified forms make functions easier to differentiate, integrate, or analyze. Techniques for function simplification often involve:
- Combining terms with common variables and operations.
- Eliminating complex fractions by rationalizing denominators.
- Using known algebraic identities and calculus properties to reduce terms.
Other exercises in this chapter
Problem 73
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