Problem 73
Question
Write an equation of a circle with the given center and radius. center \((2,-3),\) radius 6
Step-by-Step Solution
Verified Answer
The equation of the circle with the given center and radius is: \((x - 2)^2 + (y + 3)^2 = 36\).
1Step 1: Identify the given values
Identify the given center and radius of the circle. Center is given as \((2,-3)\), so the values of \(h\) and \(k\) are 2 and -3 respectively. Radius is given as 6, so the value of \(r\) is 6.
2Step 2: Substitute values into the standard form equation
Plugging these values to our standard circle equation we get: \((x - 2)^2 + (y - (-3))^2 = 6^2\).
3Step 3: Simplify the equation
Simplify the equation to its final form: \((x - 2)^2 + (y + 3)^2 = 36\).
Key Concepts
Standard Form EquationCenter-Radius FormCoordinate Geometry
Standard Form Equation
The equation of a circle in the standard form is a key concept in coordinate geometry. It is expressed as \[(x - h)^2 + (y - k)^2 = r^2,\]where
For example, in the exercise, the center was given as \((2, -3)\) and the radius as \(6\). Substituting these into the standard form equation: \((x - 2)^2 + (y + 3)^2 = 36\). Here, the \(36\) is the radius squared \(6^2\). This format is often the easiest way to write and understand a circle's equation because it directly reflects the circle's geometrical properties.
- \(h\) and \(k\) represent the coordinates of the center of the circle, \((h, k)\).
- \(r\) is the radius of the circle.
For example, in the exercise, the center was given as \((2, -3)\) and the radius as \(6\). Substituting these into the standard form equation: \((x - 2)^2 + (y + 3)^2 = 36\). Here, the \(36\) is the radius squared \(6^2\). This format is often the easiest way to write and understand a circle's equation because it directly reflects the circle's geometrical properties.
Center-Radius Form
The center-radius form of a circle's equation is essentially the same as the standard form. However, it's emphasized as highlighting the circle's core properties:
This form makes it easy to visualize the circle and understand its location and size on a coordinate plane. For the exercise, using the center-radius form helped us quickly identify the circle's position and accurately plug the values \((h = 2, k = -3, r = 6)\) into our equation.
- The center, \((h, k),\) gives you the exact point around which the circle is drawn.
- The radius, \(r,\) defines how far the boundary of the circle is from its center.
This form makes it easy to visualize the circle and understand its location and size on a coordinate plane. For the exercise, using the center-radius form helped us quickly identify the circle's position and accurately plug the values \((h = 2, k = -3, r = 6)\) into our equation.
Coordinate Geometry
In coordinate geometry, circles are beautifully symmetrical shapes, described mathematically to determine their location exactly on a plane. It involves using coordinates to express the geometric properties of shapes. For circles, you need:
- The circle's center point, which provides the base coordinates for positioning.
- The radius, which denotes the circle's size and ensures all points on the circle are equidistant from the center.
Other exercises in this chapter
Problem 72
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