Problem 73
Question
Use the properties of logarithms to expand the expression as a sum, difference, and/or multiple of logarithms. (Assume all variables are positive.)\(\ln \sqrt{z}\)
Step-by-Step Solution
Verified Answer
\(\ln \sqrt{z} = \frac{1}{2} * \ln{z}\)
1Step 1: Identify the properties of logarithms to use
For the current problem, the property of logarithms to be used is: \(\ln \sqrt{x} = \frac{1}{2}* \ln{x}\). This property is derived from a more general rule: \(\ln{a^b} = b * \ln{a}\).
2Step 2: Apply the property to the expression
Apply this rule to the term \(\sqrt{z}\) and write \( \sqrt{z} \) as \( z^{1/2}\). Substituting it in the expression, we get: \( \ln(\sqrt{z}) = \ln(z^{1/2}) \)
3Step 3: Expand the logarithm
Using the property \(\ln{a^b} = b * \ln{a}\), the expression becomes: \( \frac{1}{2}* \ln{z}\).
Key Concepts
Logarithmic ExpansionPower Rule of LogarithmsVariable Restrictions in Logarithms
Logarithmic Expansion
Logarithmic expansion involves using the properties of logarithms to rewrite complex logarithmic expressions in a simpler form. This is often done to make calculations easier or to better understand the structure of the expression.
In the given exercise, we're asked to expand the expression \(\ln \sqrt{z}\). First, we recognize that a square root can be written as an exponent: \(\sqrt{z} = z^{1/2}\). Using this property helps transform the original problem into something we can further work with.
In the given exercise, we're asked to expand the expression \(\ln \sqrt{z}\). First, we recognize that a square root can be written as an exponent: \(\sqrt{z} = z^{1/2}\). Using this property helps transform the original problem into something we can further work with.
- Expression: \(\ln \sqrt{z}\)
- Re-written as: \(\ln(z^{1/2})\)
Power Rule of Logarithms
The power rule of logarithms is a key tool for expanding logarithmic expressions. It is based on the principle that an exponent inside a logarithm can be moved in front as a multiplier.
Mathematically, this is expressed as \(\ln{a^b} = b \cdot \ln{a}\). This rule is powerful because it allows us to take a complex expression and simplify it by separating the power from the logarithm itself.
For our exercise, applying the power rule to \(\ln(z^{1/2})\), we shift the \(1/2\) in front of the logarithm, transforming the expression into:
Mathematically, this is expressed as \(\ln{a^b} = b \cdot \ln{a}\). This rule is powerful because it allows us to take a complex expression and simplify it by separating the power from the logarithm itself.
For our exercise, applying the power rule to \(\ln(z^{1/2})\), we shift the \(1/2\) in front of the logarithm, transforming the expression into:
- \(\ln(z^{1/2}) = \frac{1}{2} \cdot \ln z\)
Variable Restrictions in Logarithms
When working with logarithms, it's crucial to understand the restrictions on variables. Logarithms are undefined for non-positive numbers, meaning the variables must be positive to ensure the expression is valid.
In our exercise, the assumption is that all variables are positive, which means we can safely expand and simplify without encountering undefined behavior.
Here's why it matters:
In our exercise, the assumption is that all variables are positive, which means we can safely expand and simplify without encountering undefined behavior.
Here's why it matters:
- Logarithm of zero or a negative number is undefined.
- Ensuring \(z > 0\) allows \(\ln z\) and by extension \(\ln(z^{1/2})\) to be valid expressions.
Other exercises in this chapter
Problem 72
Find the domain, vertical asymptote, and \(x\) -intercept of the logarithmic function. Then sketch its graph.\(f(x)=\ln (3-x)\)
View solution Problem 73
Solve the logarithmic equation algebraically. Approximate the result to three decimal places.\(\ln \sqrt{x+2}=1\)
View solution Problem 73
Find the domain, vertical asymptote, and \(x\) -intercept of the logarithmic function. Then sketch its graph.\(h(x)=\ln (x+1)\)
View solution Problem 74
Solve the logarithmic equation algebraically. Approximate the result to three decimal places.\(\ln \sqrt{x-8}=5\)
View solution