Problem 73
Question
Use the appropriate reciprocal identity to find each function value. Rationalize denominators when applicable. $$\sin \theta, \text { given that } \csc \theta=\sqrt{2}$$
Step-by-Step Solution
Verified Answer
\( \sin \theta = \frac{\sqrt{2}}{2} \)
1Step 1: Understand the Reciprocal Identity
Recall that the cosecant function is the reciprocal of the sine function. This means if \( \csc \theta = \sqrt{2} \), then \( \sin \theta = \frac{1}{\csc \theta} \).
2Step 2: Substitute the Given Value
We are given that \( \csc \theta = \sqrt{2} \). Substituting this into the reciprocal identity, we have: \( \sin \theta = \frac{1}{\sqrt{2}} \).
3Step 3: Rationalize the Denominator
To rationalize the denominator of \( \frac{1}{\sqrt{2}} \), multiply the numerator and the denominator by \( \sqrt{2} \). This gives us:\[\sin \theta = \frac{1 \cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{\sqrt{2}}{2}\]
4Step 4: Final Expression for \(\sin \theta\)
The rationalized and simplified value for \( \sin \theta \) is \( \frac{\sqrt{2}}{2} \).
Key Concepts
Reciprocal IdentitiesRationalizing the DenominatorCosecant and Sine Relationship
Reciprocal Identities
Reciprocal identities are a key concept in trigonometry that simplify the relationship between various trigonometric functions. In essence, a reciprocal identity explains how one trigonometric function is the "inverse" of another. For example, the reciprocal identity for sine and cosecant states that cosecant is the reciprocal of sine.
- If you know one function value, you can easily find the other by taking the reciprocal. In mathematical terms, it means that if you have a value for \( \csc \theta \), the equivalent \( \sin \theta \) can be found using \( \sin \theta = \frac{1}{\csc \theta} \).
- This relationship is useful because it allows you to switch between functions, especially when only one of them is given.
Rationalizing the Denominator
Rationalizing the denominator is a mathematical process used to eliminate radicals from the bottom part of a fraction. In trigonometry, we often find expressions involving square roots in the denominators, and simplifying these is essential for cleaner expressions and easier further calculations.
- When presented with a fraction like \( \frac{1}{\sqrt{2}} \), it is often preferred to express it without a radical in the denominator.
- To do this, multiply both the numerator and the denominator by the radical you wish to remove. In this case, multiply by \( \sqrt{2} \) to obtain \( \frac{\sqrt{2}}{2} \).
Cosecant and Sine Relationship
In trigonometry, understanding the relationship between different trigonometric functions is vital. The sine and cosecant relationship is one such example, where the two functions are directly dependent on one another through a reciprocal connection.
- Mathematically, \( \csc \theta = \frac{1}{\sin \theta} \) and conversely, \( \sin \theta = \frac{1}{\csc \theta} \). This means if you know one, you can find the other easily.
- So, when you are given that \( \csc \theta = \sqrt{2} \), you can find \( \sin \theta \) by computing \( \sin \theta = \frac{1}{\sqrt{2}} \), and then rationalizing this gives \( \sin \theta = \frac{\sqrt{2}}{2} \).
Other exercises in this chapter
Problem 72
Graph each function over a two-period interval. $$y=3+\frac{1}{2} \tan x$$
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Convert each radian measure to degrees. $$\frac{8 \pi}{3}$$
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Graph each function over a two-period interval. $$y=-1+\frac{1}{2} \cot (2 x-3 \pi)$$
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Convert each radian measure to degrees. $$\frac{7 \pi}{4}$$
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