Problem 73
Question
The enantiomeric excess and observed specific rotation of a mixture containing \(6 \mathrm{~g}\) of \((+)-2\) -butanol and \(4(\mathrm{~g})\) of \((-)-2\) -butanol are respectively (If the specific rotation of enantiomerically pure \((+)-2\) -butanol is \(+13.5\) units) (a) \(80 \%\), \(+2.7\) unit (b) \(20 \%,-27\) unit (c) \(20 \%,+2.7\) unit (d) \(80 \%\), \(-27\) unit
Step-by-Step Solution
Verified Answer
(c) 20%, +2.7 unit
1Step 1: Determine Total Mass
Calculate the total mass of the mixture, which is the sum of the masses of \( (+)-2 \ ext{-butanol} \) and \( (-)-2 \ ext{-butanol} \). Total Mass = 6 g + 4 g = 10 g.
2Step 2: Calculate Mole Fraction of Each Enantiomer
Determine the mole fraction of each enantiomer by dividing their respective masses by the total mass. Mole fraction of \( (+)-2 \ ext{-butanol} \) = \( \frac{6}{10} = 0.6 \). Mole fraction of \( (-)-2 \ ext{-butanol} \) = \( \frac{4}{10} = 0.4 \).
3Step 3: Compute Enantiomeric Excess (ee)
The enantiomeric excess is the absolute difference between the mole fractions of the enantiomers, then presented as a percentage.\[ ee = \left| 0.6 - 0.4 \right| \times 100\% = 20\% \]
4Step 4: Calculate Observed Specific Rotation
The observed specific rotation is calculated using the formula \( [\alpha]_{\text{obs}} = ee \times [\alpha]_{\text{pure}} \).Since \( (+)-2 \ ext{-butanol} \) is in excess:\[ [\alpha]_{\text{obs}} = \frac{0.2}{1.0} \times (+13.5) = +2.7 \] units.
5Step 5: Identify Correct Answer
From the calculations, the enantiomeric excess is \( 20\% \) and the observed specific rotation is \( +2.7 \) units. Therefore, the correct answer is option (c) \( 20\%, +2.7 \) unit.
Key Concepts
Understanding Specific RotationDeciphering EnantiomersExploring Optical Activity
Understanding Specific Rotation
Specific rotation is a fundamental concept in understanding how certain substances interact with polarized light. It refers to the measure of how much a chiral compound can rotate the plane of polarized light as it passes through it. When polarized light enters a solution containing these chiral substances, it rotates either to the right, called dextrorotatory
- expressed as a positive value
- expressed as a negative value
- the nature of the compound itself
- the concentration of the compound in the solution
- the length of the path through which the light travels
Deciphering Enantiomers
Enantiomers are fascinating chemical structures that are mirror images of each other, much like your left and right hands. These molecules share the same molecular formula and sequence of bonded atoms but differ in three-dimensional orientation. This unique characteristic gives rise to different configurations known as optically active isomers.
Enantiomers can exert a profound effect in various chemical and biological environments, mainly because they can interact with other chiral entities differently because of their spatial arrangement. In nature and synthetic chemistry, differentiating between enantiomers can be crucial because they might possess distinct chemical properties, react differently with various enzymes, or have different effects in biological systems.
Recognizing the importance of enantiomers in a chemical mixture is part of determining enantiomeric excess, which describes how much one enantiomer is present in greater proportion than the other. This directly influences the observed optical activity of the solution where the enantiomer concentration imbalance is quantified.
Exploring Optical Activity
Optical activity is a property of chiral substances, where these substances have the ability to rotate the plane of polarized light. This concept is central to not only chemistry but also fields like pharmacology and materials science.
When a compound is optically active, it means that the interaction of chiral molecules with polarized light results in optical rotation, which can be measured and analyzed. This rotation can be measured using a polarimeter, and it provides invaluable information about the purity and concentration of enantiomers in a sample.
Optically active compounds are categorized based on their rotation behavior:
- Dextrorotatory compounds rotate light to the right, denoted by a positive sign.
- Levorotatory compounds rotate light to the left, denoted by a negative sign.
Other exercises in this chapter
Problem 64
The instrument which can be used to measure optical activity, i.e., specific rotation (a) Refractometer (b) Photometer (c) Voltmeter (d) Polarimeter
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Which of the following pair of isomers cannot be separated by fractional crystallisation or fractional distillation? (a) Maleic acid and fumaric acid (b) (+)-Ta
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