Problem 73
Question
The Conjugate Zeros Theorem says that the complex zeros of a polynomial with real coefficients occur in complex conjugate pairs. Explain how this fact proves that a polynomial with real coefficients and odd degree has at least one real zero.
Step-by-Step Solution
Verified Answer
An odd-degree polynomial with real coefficients has at least one real zero due to the necessity of an odd total number of zeros, meaning not all zeros can be pairs of conjugates.
1Step 1: Understand the Conjugate Zeros Theorem
The Conjugate Zeros Theorem states that if a polynomial has real coefficients, any complex zeros must occur in conjugate pairs. This means if \(a+bi\) is a zero, then \(a-bi\) must also be a zero.
2Step 2: Analyze the Implications of the Conjugate Zeros Theorem
Given that the complex zeros occur in conjugate pairs, if there is an odd total number of zeros (including real and complex zeros), there must be at least one zero that is not part of a conjugate pair. Since conjugate pairs contribute an even number of zeros, an odd total number of zeros implies at least one real zero.
3Step 3: Connect with Polynomials of Odd Degree
A polynomial of odd degree must have an odd number of zeros (counting multiplicity) according to the Fundamental Theorem of Algebra. Since complex zeros come in pairs, the count of these must be even. Hence, when the degree is odd, at least one zero must be real.
Key Concepts
Complex Numbers and Conjugate PairsPolynomials with Real Coefficients and Their BehaviorUnderstanding the Fundamental Theorem of Algebra
Complex Numbers and Conjugate Pairs
Understanding complex numbers is vital when learning about polynomials with real coefficients. Complex numbers have both a real part and an imaginary part. They are typically expressed as \(a + bi\), where \(a\) is the real part and \(b\) is the coefficient of the imaginary part, \(i\). One of the unique properties of polynomials with real coefficients is that their complex zeros appear as conjugate pairs. If a polynomial has a complex zero \(a + bi\), the Conjugate Zeros Theorem tells us that \(a - bi\) must also be a zero. This symmetric pairing is because the imaginary parts must cancel out when summed.
- Complex numbers are formed with a real and an imaginary part.
- Complex conjugates like \(a + bi\) and \(a - bi\) balance out imaginary components.
- When multiplied, conjugates yield real coefficients, preserving the polynomial's nature.
Polynomials with Real Coefficients and Their Behavior
A polynomial with real coefficients is an algebraic expression in which all the coefficients are real numbers. When dealing with such polynomials, it is guaranteed by the Conjugate Zeros Theorem that any complex roots occur as conjugate pairs.Polynomials with real coefficients can take a variety of forms. For example, the polynomial \(f(x) = x^3 - 4x\) is cubic, meaning it's of degree three, and all of its coefficients are real numbers. Despite its simplicity, the behavior of such polynomials can be complex and fascinating.
- Real coefficients lead to symmetric pairs of complex zeros.
- Degree of the polynomial dictates the number of zeros.
- The sum of all zeros equals the opposite of the coefficient of the term with one less degree, divided by the leading coefficient.
Understanding the Fundamental Theorem of Algebra
The Fundamental Theorem of Algebra is a key concept in understanding polynomials. It states that every non-constant polynomial equation with complex coefficients has at least one complex root. This theorem assures that a polynomial of degree \(n\) has exactly \(n\) roots, considering multiplicity.Applying this theorem to polynomials with real coefficients helps explain why these polynomials must have real, as well as complex roots. Specifically, when a polynomial's degree is odd, like \(x^3 - 2x + 1 = 0\), it is guaranteed to have at least one real root.
- Every polynomial equation of degree \(n\) has exactly \(n\) roots.
- Roots can be real or complex, and complex roots appear in conjugate pairs for real coefficients.
- For polynomials with odd degrees, there must be a real zero because complex zeros always come in pairs.
Other exercises in this chapter
Problem 72
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