Problem 73
Question
Solve for \(x .\) See Example 3. $$ \log _{x} \frac{\sqrt{3}}{3}=\frac{1}{2} $$
Step-by-Step Solution
Verified Answer
\( x = \frac{1}{3} \).
1Step 1: Convert Logarithmic Equation to Exponential Form
The logarithmic equation given is \( \log_{x} \frac{\sqrt{3}}{3} = \frac{1}{2} \). To convert this to an exponential equation, recall that \( \log_{b}(y) = z \) means \( b^{z} = y \). Therefore, \( x^{1/2} = \frac{\sqrt{3}}{3} \).
2Step 2: Square Both Sides
To remove the square root on the left, square both sides of the equation: \[ (x^{1/2})^{2} = \left(\frac{\sqrt{3}}{3}\right)^{2} \] This simplifies to \( x = \frac{3}{9} \) since \( \left(\frac{\sqrt{3}}{3}\right)^{2} = \frac{3}{9} \).
3Step 3: Simplify the Expression
Now, simplify \( \frac{3}{9} \) to find the solution for \( x \): \[ x = \frac{1}{3} \] Thus, \( x = \frac{1}{3} \).
Key Concepts
Exponential FormSquare RootsSimplifying Fractions
Exponential Form
Understanding exponential form is key when working with logarithmic equations. It's the method of expressing repeated multiplication of the same factor. For instance, if you have a base, say, \( b \), raised to an exponent, \( z \), it means \( b \) is multiplied by itself \( z \) times.
In simpler terms, if you're given a logarithmic equation like \( \log_{b}(y) = z \), you can convert it to **exponential form**. This means you rewrite it as \( b^{z} = y \). This transformation helps solve equations by switching from a logarithm to a power.
In simpler terms, if you're given a logarithmic equation like \( \log_{b}(y) = z \), you can convert it to **exponential form**. This means you rewrite it as \( b^{z} = y \). This transformation helps solve equations by switching from a logarithm to a power.
- **Base (b):** The number that is raised to a power.
- **Exponent (z):** The power to which the base is raised.
- **Result (y):** The outcome of this multiplication.
Square Roots
Square roots are often encountered in mathematical problems and can sometimes complicate operations. A square root is essentially the opposite of squaring a number. For a number \( a \), its square root is expressed as \( \sqrt{a} \), meaning a number that when multiplied by itself yields \( a \).
Relation to Logarithmic Equations
In the context of logarithmic equations, square roots often appear as part of the terms that require adjustment to solve the problem. In our exercise, squaring both sides of the equation \( (x^{1/2})^{2} = (\frac{\sqrt{3}}{3})^{2} \) helped remove the square root on the left side, simplifying the solution process.- Steps in Square Root Elimination:
- Identify the square root within the equation.
- Square both sides to eliminate the square root.
- Resulting equation becomes easier to work with.
Simplifying Fractions
Simplifying fractions is a fundamental skill in algebra that finds relevance across various types of equations, including logarithmic equations. A fraction is simplified when it is expressed in its lowest terms, which means reducing the numerator and denominator to their smallest possible values while the fraction remains equivalent.
When faced with a fraction \( \frac{a}{b} \), you simplify it by finding the greatest common divisor (GCD) of \( a \) and \( b \), then dividing both by that number.
When faced with a fraction \( \frac{a}{b} \), you simplify it by finding the greatest common divisor (GCD) of \( a \) and \( b \), then dividing both by that number.
Application in the Solution
In the problem we solved, simplifying \( \frac{3}{9} \) to \( \frac{1}{3} \) was crucial. Here’s how:- Identify greatest common divisor (GCD) of 3 and 9, which is 3.
- Divide both the numerator and the denominator by this GCD.
- Resulting fraction is \( \frac{1}{3} \), offering a clearer answer.
Other exercises in this chapter
Problem 73
Solve each equation. Give the exact solution and, when appropriate, an approximation to four decimal places. $$ 15=9^{x+2} $$
View solution Problem 73
Graph \(f(x)=3^{x}\). Then use the graph to estimate the value of \(3^{1.5}\)
View solution Problem 73
Explain how the graph of a one-to-one function can be used to draw the graph of its inverse function.
View solution Problem 74
Assume that there are no deposits or withdrawals. Continuous Compound Interest. An initial investment of \(\$ 2,000\) earns \(8 \%\) interest, compounded contin
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