Problem 73
Question
Solve each problem. Suppose that an insect population in millions is modeled by $$f(x)=\frac{10 x+1}{x+1}$$ where \(x \geq 0\) is in months. (a) Graph \(f\) in the window \([0,14]\) by \([0,14] .\) Find the equation of the horizontal asymptote. (b) Determine the initial insect population. (c) What happens to the population after several months? (d) Interpret the horizontal asymptote.
Step-by-Step Solution
Verified Answer
(a) Horizontal asymptote is \( y = 10 \). (b) Initial population is 1 million. (c) Population stabilizes at 10 million. (d) Asymptote \( y = 10 \) indicates long-term population.
1Step 1: Plotting the Graph
To graph the function \( f(x) = \frac{10x+1}{x+1} \), we first note its behavior over the interval \([0, 14]\). As \( x \) approaches 0, the function behaves like a straight line (since \( 10x \) dominates), and as \( x \) becomes very large, the function approaches its horizontal asymptote. Plotting values from 0 to 14, you can manually find points or use a graphing tool to illustrate how \( f(x) \) behaves within the given window.
2Step 2: Identify Horizontal Asymptote
To find the horizontal asymptote, consider the function as \( x \to \infty \). The horizontal asymptote reflects the limit \( \lim_{x \to \infty} f(x) = \lim_{x \to \infty} \frac{10x+1}{x+1} = \lim_{x \to \infty} \frac{10+\frac{1}{x}}{1+\frac{1}{x}} = 10 \). So, the horizontal asymptote is given by the equation \( y = 10 \).
3Step 3: Calculate Initial Population
To find the initial population, substitute \( x = 0 \) into the function \( f(x) = \frac{10x+1}{x+1} \). This gives us the initial insect population: \( f(0) = \frac{10(0)+1}{0+1} = 1 \) million. Thus, the initial population is 1 million insects.
4Step 4: Behavior of Population Over Time
As \( x \) increases indicating several months passing by, the function \( f(x) = \frac{10x+1}{x+1} \) approaches its horizontal asymptote, \( y = 10 \). This suggests that the insect population approaches 10 million as time progresses.
5Step 5: Interpreting Horizontal Asymptote
The horizontal asymptote \( y = 10 \) means that, in the long term, the population stabilizes around 10 million. It represents the carrying capacity or a stable population number that it will reach eventually if there are no other changes in conditions.
Key Concepts
Horizontal AsymptoteInitial PopulationGraphing Functions
Horizontal Asymptote
A horizontal asymptote is a horizontal line that a graph approaches but never quite reaches. It indicates the behavior of a rational function as the input grows very large or very small. In the context of the function \(f(x) = \frac{10x+1}{x+1}\), the horizontal asymptote helps us understand the long-term behavior of the population model.
For the given function, we find the horizontal asymptote by taking the limit of \(f(x)\) as \(x\) approaches infinity. By simplifying, we get:
For the given function, we find the horizontal asymptote by taking the limit of \(f(x)\) as \(x\) approaches infinity. By simplifying, we get:
- Divide each term by \(x\) to give \( \lim_{x \to \infty} \frac{10 + \frac{1}{x}}{1 + \frac{1}{x}} \).
- As \(x\) becomes very large, \(\frac{1}{x}\) approaches 0.
- Thus, the limit simplifies to 10, making the horizontal asymptote \(y = 10\).
Initial Population
The initial population refers to the size of the population at the starting point of observation, which in this case is when \(x = 0\). To determine it, we simply substitute \(x = 0\) into the function:
Understanding the initial population provides a reference for measuring growth or decline over time. It tells us where the observed changes start and can help in predicting future questions or differences as months pass, based on the ongoing population growth through this model.
- \(f(0) = \frac{10(0) + 1}{0 + 1} = 1\).
Understanding the initial population provides a reference for measuring growth or decline over time. It tells us where the observed changes start and can help in predicting future questions or differences as months pass, based on the ongoing population growth through this model.
Graphing Functions
Graphing functions involves plotting points and examining the behavior of a function across its domain. For \(f(x) = \frac{10x+1}{x+1}\), graphing will visually demonstrate trends associated with the function. Let's break down the process:
The overall shape of the graph will resemble an increasing curve that gradually flattens as it nears the asymptote, indicating a slowing growth rate as it stabilizes close to the asymptotic value. This overall view is vital for understanding the balance point between growth pressures and limiting factors impacting the population size.
- Start by calculating a few key values, especially at the beginning and end of the interval, like \(f(0)\) and close to the boundaries.
- Note how the graph approaches the horizontal asymptote \(y = 10\).
- Plot points at regular intervals within the given window of \([0, 14]\).
The overall shape of the graph will resemble an increasing curve that gradually flattens as it nears the asymptote, indicating a slowing growth rate as it stabilizes close to the asymptotic value. This overall view is vital for understanding the balance point between growth pressures and limiting factors impacting the population size.
Other exercises in this chapter
Problem 72
Graph each rational function by hand. Give the domain and range, and discuss symmetry. Give the equations of any asymptotes. $$f(x)=\frac{-2 x^{2}}{x^{2}+2}$$
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Determine the domain of each function. Do not use a calculator. $$f(x)=\sqrt{5+4 x}$$
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Solve each equation involving "nested" radicals for all real solutions analytically. Support your solutions with a graph. $$\sqrt{\sqrt{28 x+8}}=\sqrt{3 x+2}$$
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Graph each rational function by hand. Give the domain and range, and discuss symmetry. Give the equations of any asymptotes. $$f(x)=\frac{2 x^{2}}{x^{4}+1}$$
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