Problem 73
Question
Prove that $$ \left(\begin{array}{l}n \\\r\end{array}\right)=\left(\begin{array}{c}n \\\n-r\end{array}\right) $$
Step-by-Step Solution
Verified Answer
The equality \(\binom{n}{r} = \binom{n}{n-r}\) is proven by comparing these two binomial coefficients. After using the binomial coefficient formula for both sides, it's clear that the two expressions are equal, which confirms the equality.
1Step 1: Define binomial coefficient
The formula for a binomial coefficient is given by \[\binom{n}{r} = \frac{n!}{r!(n-r)!}\] where \(n!\) is the factorial of n, \(r!\) the factorial of r, and \((n-r)!\) the factorial of \(n-r\). The factorial of a number is the product of all positive integers less than or equal to that number.
2Step 2: Calculate binomial coefficient for \(\binom{n}{n-r}\)
Apply the same formula to calculate the binomial coefficient \(\binom{n}{n-r}\). Using the formula, \[\binom{n}{n-r} = \frac{n!}{(n-r)!(n-(n-r))!}\] Simplifying the denominator, \[\binom{n}{n-r} = \frac{n!}{(n-r)!r!}\]
3Step 3: Comparison
Now comparing the two expressions \(\binom{n}{r} = \binom{n}{n-r}\), it can be seen that they are equal, as the right side equals \(\frac{n!}{r!(n-r)!}\) which is equal to the left side. This confirms the equality.
Key Concepts
Understanding FactorialsCombinatorics and Binomial CoefficientsAlgebraic Proof of Binomial Coefficient Equality
Understanding Factorials
Factorials are a fundamental concept in mathematics, specifically in the areas of algebra and combinatorics. A factorial, denoted by the symbol "!", represents the product of all positive integers up to a specified number. For instance, the factorial of a number \(n\), written as \(n!\), is calculated as \(n \times (n-1) \times (n-2) \times \ldots \times 1\).
A few examples to illustrate:
A few examples to illustrate:
- \(4! = 4 \times 3 \times 2 \times 1 = 24\)
- \(3! = 3 \times 2 \times 1 = 6\)
- \(0! = 1\) (by definition, to ensure correctness in combinations and permutations)
Combinatorics and Binomial Coefficients
Combinatorics is the branch of mathematics that deals with counting, arranging, and finding patterns among a set of items. A key element of combinatorics is understanding combinations, which are selections of items from a larger set without regard to the order of selection.
The binomial coefficient, denoted as \(\binom{n}{r}\), is a mathematical way to express the number of possible combinations of \(r\) items from a set of \(n\) distinct items. Its formula is given by:
The binomial coefficient, denoted as \(\binom{n}{r}\), is a mathematical way to express the number of possible combinations of \(r\) items from a set of \(n\) distinct items. Its formula is given by:
- \[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]
Algebraic Proof of Binomial Coefficient Equality
An algebraic proof is a logical process where we use algebraic expressions and identities to demonstrate the truth of a mathematical statement. In this exercise, the goal is to prove the equality \(\binom{n}{r} = \binom{n}{n-r}\).
We start by expressing both sides using the binomial coefficient formula:
This equality demonstrates a fascinating property of combinations: the count of possible selections of \(r\) items from \(n\) is identical to the count of choosing \(n-r\) items, acknowledging that selecting items to involve those not selected as well.
We start by expressing both sides using the binomial coefficient formula:
- For \(\binom{n}{r}\): \[\frac{n!}{r!(n-r)!}\]
- For \(\binom{n}{n-r}\): \[\frac{n!}{(n-r)!r!}\]
This equality demonstrates a fascinating property of combinations: the count of possible selections of \(r\) items from \(n\) is identical to the count of choosing \(n-r\) items, acknowledging that selecting items to involve those not selected as well.
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