Problem 73
Question
\(\mathrm{Zn}\), on reacting with cold dil. \(\mathrm{HNO}_{3}\) forms (a) \(\mathrm{ZnNO}\) (b) \(\mathrm{NO}_{2}\) (c) \(\mathrm{NH}_{4} \mathrm{NO}_{3}^{3}\) (d) \(\mathrm{NO}\)
Step-by-Step Solution
Verified Answer
(d) ext{NO} is formed.
1Step 1: Analyze the reaction conditions
The reaction involves zinc ( ext{Zn}) and dilute cold nitric acid ( ext{dil. HNO}_3). Cold dilute nitric acid primarily acts as a mild oxidizing agent.
2Step 2: Predict the possible reaction products
Zinc being a metal will dissolve in acid to typically form ext{Zn}^{2+} ions along with the reduction of ext{HNO}_3 which generally produces nitrogen oxides or ammonium compounds, given the dilute conditions.
3Step 3: Identify possible nitrogen oxides formed
In the presence of cold, dilute nitric acid, nitrogen monoxide ( ext{NO}) is a common product. ext{NO}_2 is usually formed in more concentrated conditions, and ext{NH}_4 ext{NO}_3 or similar compounds are formed in very concentrated conditions.
4Step 4: Conclude based on reaction type
Given these reaction conditions (cold and dilute acid), ext{Zn} reacting with ext{HNO}_3 will most likely produce ext{NO}.
Key Concepts
Oxidation-reduction reactionsNitrogen oxide formationChemical reaction conditions
Oxidation-reduction reactions
In chemistry, oxidation-reduction reactions, often referred to as redox reactions, are essential processes where electrons are transferred between substances. In the case of zinc reacting with dilute nitric acid, zinc undergoes oxidation and loses electrons. This is represented by zinc going from a neutral state to a positively charged ion, \(\text{Zn} \rightarrow \text{Zn}^{2+} + 2e^-\). The electrons lost by zinc are used to reduce nitric acid. This makes zinc the reducing agent.During this reaction, the nitric acid acts as an oxidizing agent, accepting electrons from zinc. The process of reduction changes the nitrogen in nitric acid to form various nitrogen oxides, depending on the conditions:
Reducing and oxidizing agents play their roles in these dynamic exchanges, making redox reactions central to many chemical processes.
- In concentrated conditions: \(\text{NO}_2\)
- In dilute conditions: \(\text{NO}\)
- In very concentrated conditions: ammonium nitrate compounds might form
Reducing and oxidizing agents play their roles in these dynamic exchanges, making redox reactions central to many chemical processes.
Nitrogen oxide formation
When zinc reacts with dilute, cold nitric acid, specifically under the given conditions, the primary nitrogen oxide formed is nitrogen monoxide (NO). This occurs because dilute nitric acid under mild temperature conditions preferentially facilitates the formation of less oxidized nitrogen species. The reaction can be simplified as follows:\[\text{3 Zn} + \text{8 HNO}_3 \rightarrow \text{3 Zn}^{2+} + \text{2 NO} + \text{4 H}_2\text{O} + \text{6 NO}_3^-\]In contrast, different conditions can lead to varying nitrogen oxides:
- In more concentrated acid conditions, nitrogen dioxide \(\text{NO}_2\) is more likely to form, characterized by its brownish color and distinct properties.
- Ammonium nitrate forms primarily under highly concentrated nitric acid conditions.
Chemical reaction conditions
Chemical reactions are highly dependent on their specific conditions, such as concentration and temperature. These elements dictate the pathway the reaction takes and the products that are formed. For the zinc and nitric acid reaction, the conditions are cold temperature and dilute acid.Dilute acid suggests that the amount of nitrate ions available is lower, which doesn't favor forming the higher oxidized nitrogen products like \(\text{NO}_2\). Instead, we usually see the production of \(\text{NO}\) because these conditions reduce the oxidizing power of the acid.Temperature also plays a crucial role in chemical reactions. In this case, a colder environment slows down molecular movement, reducing the energy available for the reaction, thereby influencing what products are formed without shifting to higher oxidation states.Conditions such as pressure, solvent, and presence of catalysts can further impact reactions, but in the zinc and nitric acid scenario, concentration and temperature are the primary influences, determining the feasibility and direction of the reaction.
Other exercises in this chapter
Problem 71
Which of the following compound is known as white vitriol? (a) \(\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{Na}_{2} \mathrm{SO}_{4} \cd
View solution Problem 72
The important ore of zinc is (a) cryolite (b) calamine (c) malachite (d) gibbsite
View solution Problem 75
Zinc does not show variable valency, because (a) its d-subshell is incomplete (b) it is relatively soft metal (c) its d-subshell is complete (d) it has two elec
View solution Problem 76
In the reaction \(\mathrm{Zn}+\mathrm{NaOH} \stackrel{\Delta}{\longrightarrow} \mathrm{A}\), the product \(\mathrm{A}\) is (a) \(\mathrm{Zn}(\mathrm{OH})_{2}\)
View solution