Problem 73
Question
\(\mathrm{Fe}^{3+}\) forms octahedral complexes with \(\mathrm{NCS}^{-}\) and with \(\mathrm{NO}_{2}^{-}\) ligands. One complex displays a greater paramagnetism than the other. (a) Write the formula for each of these complex ions. (b) Use the spectrochemical series to predict whether the complex ions are high-spin or low-spin. (c) Identify which complex ion is more paramagnetic. (d) Draw the crystal-field splitting diagram, including delectrons, for each complex ion.
Step-by-Step Solution
Verified Answer
The high-spin \\([\text{Fe}(\text{NCS})_{6}]^{3-}\\) complex is more paramagnetic.
1Step 1: Write the Formula for Each Complex Ion
The oxidation state of Fe in both complexes is +3, making it \( \text{Fe}^{3+} \). For the \( \text{NCS}^{-} \) ligand, the complex will be \([\text{Fe}(\text{NCS})_{6}]^{3-}\). For the \( \text{NO}_{2}^{-} \) ligand, the complex will be \([\text{Fe}(\text{NO}_{2})_{6}]^{3-}\).
2Step 2: Predict High-Spin or Low-Spin Using the Spectrochemical Series
The spectrochemical series lists ligands in order of their ability to split the d-orbitals. \( \text{NCS}^{-} \) is a weak field ligand, typically producing high-spin complexes, while \( \text{NO}_{2}^{-} \) is a stronger field ligand, often resulting in low-spin complexes. Therefore, \([\text{Fe}(\text{NCS})_{6}]^{3-}\) is high-spin, and \([\text{Fe}(\text{NO}_{2})_{6}]^{3-}\) is low-spin.
3Step 3: Identify the More Paramagnetic Complex Ion
A high-spin complex has more unpaired electrons and is thus more paramagnetic than a low-spin complex. \([\text{Fe}(\text{NCS})_{6}]^{3-}\) is high-spin with five unpaired electrons, whereas \([\text{Fe}(\text{NO}_{2})_{6}]^{3-}\) is low-spin with one unpaired electron. Thus, \([\text{Fe}(\text{NCS})_{6}]^{3-}\) is more paramagnetic.
4Step 4: Draw the Crystal-Field Splitting Diagram for Each Complex Ion
Fe is in the +3 oxidation state, resulting in a \([\text{Ar}]3d^5\) electron configuration. In \([\text{Fe}(\text{NCS})_{6}]^{3-}\), being high-spin, the electrons are arranged as up-arrow in the three lower energy \( t_{2g} \) orbitals and two in the \( e_{g} \) orbitals. For \([\text{Fe}(\text{NO}_{2})_{6}]^{3-}\), being low-spin, electrons fill the \( t_{2g} \) orbitals first (all paired in \( t_{2g} \)) before any populate \( e_{g} \), leading to mostly paired electrons.
Key Concepts
ParamagnetismSpectrochemical SeriesHigh-spin vs Low-spin Complexes
Paramagnetism
Paramagnetism refers to the magnetic property of a material that has unpaired electrons. When these unpaired electrons are present, the material is attracted to an external magnetic field. The more unpaired electrons there are, the stronger the paramagnetism observed. In coordination chemistry, the presence of unpaired electrons in metal complexes can be predicted by looking at the electron configuration. For instance, in the case of the octahedral complex \([\text{Fe}(\text{NCS})_{6}]^{3-}\), the high-spin configuration leaves electrons unpaired. This results in stronger paramagnetism compared to low-spin arrangements, like in \([\text{Fe}(\text{NO}_{2})_{6}]^{3-}\), where electrons are more likely to be paired.Understanding paramagnetism is crucial for interpreting magnetic susceptibility experiments, which can help determine the number of unpaired electrons in a complex. Hence, complexes with more unpaired electrons, like \([\text{Fe}(\text{NCS})_{6}]^{3-}\), appear more paramagnetic.
Spectrochemical Series
The spectrochemical series is a key concept in crystal field theory, ranking ligands based on their ability to split d-orbitals. This series guides us in predicting the electron configuration within metal complexes and whether they will adopt a high-spin or low-spin state.
- Weak field ligands, like \(\text{NCS}^{-}\), cause a small splitting in the d-orbitals, promoting a high-spin configuration where electrons tend to remain unpaired.
- Strong field ligands, such as \(\text{NO}_{2}^{-}\), lead to a larger splitting, encouraging a low-spin state where electrons pair up in lower energy orbitals.
High-spin vs Low-spin Complexes
High-spin and low-spin configurations are determined by how electrons distribute themselves among the d-orbitals in a metal complex, based largely on the field strength of the ligand.High-spin Complexes:
- Formed with weak field ligands.
- Result in maximized unpaired electron count.
- Usually increase the paramagnetic character of a complex.
- Formed with strong field ligands.
- Minimize the number of unpaired electrons by pairing as many as possible in the lower energy set of orbitals.
- Usually exhibit less paramagnetism compared to high-spin complexes.
Other exercises in this chapter
Problem 70
Draw the possible geometric isomers, if any, of (a) \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]\) (b) \(\left[\mathrm{Pt}\left(\m
View solution Problem 71
Draw the crystal-field splitting diagrams and put in the d electrons for these octahedral complexes. In those cases where they are possible, draw diagrams for b
View solution Problem 74
Explain why \(\mathrm{Cr}^{2+}\) forms high-spin and low-spin octahedral complexes, but \(\mathrm{Cr}^{3+}\) does not.
View solution Problem 75
How many unpaired electrons are in the high-spin and low-spin octahedral complexes of \(\mathrm{Cr}^{2+} ?\)
View solution