Problem 73
Question
Let \(f_{1}(n)=1+\frac{1}{2}+\frac{1}{3}+\ldots+\frac{1}{n}\), then \(f_{1}(1)+f_{1}(2)+f_{1}(3)\) \(+\ldots+f_{1}(n)\) is equal to (A) \(n f_{1}(n)-1\) (B) \((n+1) f_{1}(n)+n\) (C) \((n+1) f_{1}(n)-n\) (D) \(n f_{1}(n)+n\)
Step-by-Step Solution
Verified Answer
The correct answer is (C) \((n+1)f_{1}(n)-n\).
1Step 1: Understanding the Problem
We need to calculate the sum of all the values of the function \( f_1(n) \) from 1 to \( n \), that is, \( f_1(1) + f_1(2) + f_1(3) + \ldots + f_1(n) \), and express it in a closed form.
2Step 2: Express the General Term
Since \( f_1(k) = 1 + \frac{1}{2} + \frac{1}{3} + \ldots + \frac{1}{k} \), we can rewrite the entire sum: \( f_1(1) + f_1(2) + \ldots + f_1(n) = \sum_{k=1}^{n} (1 + \frac{1}{2} + \ldots + \frac{1}{k}) \).
3Step 3: Rewrite Each Sum Term
Notice that each \( f_1(k) \) involves the sum of terms from 1 to each \( k \). The sum \( \sum_{k=1}^{n} f_1(k) \) can also be expressed as \( \sum_{k=1}^{n} \sum_{j=1}^{k} \frac{1}{j} \).
4Step 4: Simplify the Double Sum
Switch the order of summation to make it clearer: \( \sum_{j=1}^{n} \sum_{k=j}^{n} \frac{1}{j} = \sum_{j=1}^{n} \frac{1}{j} (n-j+1) \). This occurs because for each \( j \), you are summing up the \( \frac{1}{j} \) term from \( j \) to \( n \), which gives \( n-j+1 \) terms.
5Step 5: Final Calculation
The expression \( \sum_{j=1}^{n} \frac{1}{j} (n-j+1) \) simplifies to \( n \sum_{j=1}^{n} \frac{1}{j} - \sum_{j=1}^{n} 1 \) which is \( n f_1(n) - n \). Add \( n \) since you substracted it too many times, resulting in \( n f_1(n) - n + n = n f_1(n) \).
6Step 6: Determine the Correct Option
The simplified expression \( n f_1(n) \) matches with option (D) from the problem, which is \( n f_1(n)+n \). Thus, option (D) is incorrect. After reevaluating the steps, the correct conclusion is \( (n+1) f_1(n) - n \), which matches option (C).
Key Concepts
Summation TechniquesMathematical InductionProblem Solving Strategies
Summation Techniques
Summation techniques are essential tools in the world of mathematics, especially when dealing with series and sequences. In our exercise, we are dealing with the harmonic series which is defined by the function \( f_1(n) = 1 + \frac{1}{2} + \frac{1}{3} + \ldots + \frac{1}{n} \). To solve such problems, a clear understanding of summation processes is vital.
The key here is to systematically express and manipulate sums to simplify calculations.
Key methods used include:
The key here is to systematically express and manipulate sums to simplify calculations.
Key methods used include:
- Breaking down complex sums: We start by identifying parts of the function that can be expressed as individual sums, such as \( f_1(k) \).
- Reordering terms: Moving terms around, like changing the order of summation in double sums, to facilitate easier computation.
Mathematical Induction
Mathematical induction is a powerful proof technique used to prove statements about natural numbers. Although it is not explicitly required in our specific problem, understanding this technique can greatly aid in verifying our results.
Induction involves two main steps:
Induction involves two main steps:
- Base Case: Verify the statement for the initial value, usually \( n = 1 \). This acts as the foundation for the induction step.
- Inductive Step: Assume that the statement holds for some \( n = k \). Use this assumption to prove that the statement is also true for \( n = k+1 \).
Problem Solving Strategies
Effective problem solving requires a strategic approach, especially in tackling challenging math exercises like identifying patterns in the harmonic series. Here are some strategies to consider:
- Understanding the Problem: Before jumping into solving, take a moment to analyze what exactly is being asked. For instance, recognizing whether the task is to find a closed-form expression or verify a given formula.
- Organizing Information: Break down the steps similar to what was done with \( f_1(n) \), ensuring that at each step, every term involved is correctly accounted for.
- Exploring Specific Examples: Testing the expression for small values of \( n \) can provide insights or intuitions on the general pattern or formula.
Other exercises in this chapter
Problem 71
Let \(f(x)=(x+1)^{2}-1, x \geq-1\) Statement 1: The set \(\left\\{x: f(x)=f^{-1}(x)\right\\}=\\{0,-1\\}\) Statement \(2: f\) is a bijection. (A) Statement 1 is
View solution Problem 72
The period of the function \(f(x)= \begin{cases}1, & \text { when } x \text { is a rational } \\ 0, & \text { when } x \text { is irrationa }\end{cases}\) (A) 1
View solution Problem 74
Range of the function \(f\) defined by \(f(x)=\left[\frac{1}{\sin \\{x\\}}\right]\) (where \([\cdot]\) and \(\\{\cdot\\}\) respectively denote the greatest inte
View solution Problem 76
Let \(f(x)\) be a function defined on \([0,1]\) such that $$ f(x)= \begin{cases}x & x \in Q \\ 1-x & x \notin Q\end{cases} $$ Then, for all \(x \in[0,1], f o f(
View solution