Problem 73
Question
Is the derivative of the reciprocal of \(f(x)\) the reciprocal of the derivative of \(f(x)\) ? Why or why not?
Step-by-Step Solution
Verified Answer
No, the derivative of the reciprocal is not the reciprocal of the derivative.
1Step 1: Define the Functions
We are given the reciprocal of the function \(f(x)\), which is \(\frac{1}{f(x)}\). We want to find its derivative and compare it to the reciprocal of the derivative of \(f(x)\), which is \(\frac{1}{f'(x)}\).
2Step 2: Differentiate the Reciprocal Function
Using the chain rule, the derivative of \(\frac{1}{f(x)}\) is given by \(\left(\frac{1}{f(x)}\right)' = -\frac{f'(x)}{(f(x))^2}\). This relies on the formula for differentiating reciprocal functions: \(\left(\frac{1}{u}\right)' = -\frac{u'}{u^2}\) where \(u = f(x)\).
3Step 3: Check Reciprocal of Derivative of f(x)
The reciprocal of the derivative of \(f(x)\) is simply \(\frac{1}{f'(x)}\).
4Step 4: Compare Results
From Step 2, we derive \(-\frac{f'(x)}{(f(x))^2}\) as the derivative of the reciprocal function. From Step 3, we have \(\frac{1}{f'(x)}\). Clearly, these two results are not equal. They differ in both form and multiplication factors.
Key Concepts
DerivativeReciprocal FunctionChain Rule
Derivative
The derivative is a fundamental concept in calculus. It measures how a function changes as its input changes. Think of it as the "slope" of the function at any point along its curve. To calculate the derivative, you consider how much the function's output changes when you slightly change its input, creating a new function that gives you this rate of change wherever you are on the graph of the original function.
Some important points about derivatives include:
Some important points about derivatives include:
- The derivative of a function at a point tells you the best linear approximation of the function near that point.
- It's often denoted by \(f'(x)\) or using the Leibniz notation \(\frac{dy}{dx}\).
Reciprocal Function
A reciprocal function flips the value of a function over the identity line. Essentially, the reciprocal of a function \(f(x)\) is \(\frac{1}{f(x)}\). When working with reciprocal functions, you often deal with quantities that are inversely related.
In the realm of derivatives, applying a derivative to a reciprocal function involves special rules. The derivative of a reciprocal function, \(\frac{1}{f(x)}\), involves using the formula:
In the realm of derivatives, applying a derivative to a reciprocal function involves special rules. The derivative of a reciprocal function, \(\frac{1}{f(x)}\), involves using the formula:
- \(\left(\frac{1}{f(x)}\right)' = -\frac{f'(x)}{(f(x))^2}\)
- This is derived using the chain rule, a helpful tool when differentiating composite functions.
Chain Rule
The chain rule is a pivotal tool in calculus for differentiating composite functions, which are functions made up of other functions. It allows you to find the derivative of a composed function, where one function is applied to the result of another, by breaking it down into simpler parts.
This concept is captured in the formula: \( (g(f(x)))' = g'(f(x)) \cdot f'(x) \), where you multiply the derivative of the outside function \(g\) evaluated at the inside function \(f(x)\) by the derivative of the inside function \(f(x)\).
This concept is captured in the formula: \( (g(f(x)))' = g'(f(x)) \cdot f'(x) \), where you multiply the derivative of the outside function \(g\) evaluated at the inside function \(f(x)\) by the derivative of the inside function \(f(x)\).
- To use the chain rule, remember that you're essentially peeling away the layers of the composition, differentiating each in turn.
- It makes work with derivatives of nested functions seamless and efficient.
Other exercises in this chapter
Problem 72
Is the function given by \(F(x)=\frac{3}{x-5}\) continuous on \(\mathbb{R} ?\)
View solution Problem 73
For each function, find the points on the graph at which the tangent line is horizontal. If none exist, state that fact. $$ y=-\frac{1}{3} x^{3}+6 x^{2}-11 x-50
View solution Problem 73
The Candy Factory sells candy by the pound, charging \(\$ 1.50\) per pound for quantities up to and including 20 pounds. Above 20 pounds, the Candy Factory char
View solution Problem 74
For each function, find the points on the graph at which the tangent line is horizontal. If none exist, state that fact. $$ y=-x^{3}+x^{2}+5 x-1 $$
View solution