Problem 73
Question
Interactive Solution \(11.73\) at illustrates a model for solving this problem. A pressure difference of \(1.8 \times 10^{3} \mathrm{~Pa}\) is needed to drive water \(\left(\eta=1.0 \times 10^{-3} \mathrm{~Pa} \cdot \mathrm{s}\right)\) through a pipe whose radius is \(5.1 \times 10^{-3} \mathrm{~m}\). The volume flow rate of the water is \(2.8 \times 10^{-4} \mathrm{~m}^{3} / \mathrm{s}\). What is the length of the pipe?
Step-by-Step Solution
Verified Answer
The length of the pipe is approximately 0.107 m.
1Step 1: Understand the Problem
We need to find the length of the pipe given the pressure difference, the viscosity of the fluid, the radius of the pipe, and the volume flow rate of the water.
2Step 2: Use Poiseuille's Law
Poiseuille's Law relates the flow rate (Q), the pressure difference (abla P), the radius (r), the viscosity (eta), and the length (L) of the pipe:\[ Q = \frac{{\pi r^4 abla P}}{{8 \eta L}} \]
3Step 3: Rearrange the Formula to Solve for Length
To find the length (L), rearrange the formula:\[ L = \frac{{\pi r^4 abla P}}{{8 \eta Q}} \]
4Step 4: Plug in the Given Values
Substitute the given values into the equation:- Pressure difference \( abla P = 1.8 \times 10^{3} \ \mathrm{Pa} \)- Radius \( r = 5.1 \times 10^{-3} \ \mathrm{m} \)- Viscosity \( \eta = 1.0 \times 10^{-3} \ \mathrm{Pa \cdot s} \)- Flow rate \( Q = 2.8 \times 10^{-4} \ \mathrm{m}^{3}/s \)\[ L = \frac{{\pi \cdot (5.1 \times 10^{-3})^4 \cdot 1.8 \times 10^{3}}}{{8 \cdot 1.0 \times 10^{-3} \cdot 2.8 \times 10^{-4}}} \]
5Step 5: Calculate the Length
Calculate the value:\[ L = \frac{{\pi \cdot 6.7321 \times 10^{-14} \cdot 1.8 \times 10^{3}}}{{2.24 \times 10^{-6}}} \]\[ L \approx 0.107 \ \mathrm{m} \]
6Step 6: Conclusion
The length of the pipe is approximately \(0.107 \ \mathrm{m}\).
Key Concepts
Poiseuille's LawViscosityPressure DifferenceFlow Rate
Poiseuille's Law
In fluid dynamics, Poiseuille's Law is a key principle that describes how viscous fluid flows through a cylindrical pipe. The law provides a relationship between various parameters that affect the flow rate of the fluid. It is expressed mathematically by the equation:
- \[ Q = \frac{{\pi r^4 \Delta P}}{{8 \eta L}} \]
- \( Q \) is the volumetric flow rate, or how much fluid passes through the pipe per unit of time.
- \( \Delta P \) represents the pressure difference between the ends of the pipe.
- \( r \) is the radius of the pipe.
- \( \eta \) stands for the fluid's viscosity.
- \( L \) indicates the length of the pipe.
Viscosity
Viscosity is a measure of a fluid's resistance to deformation or flow. In simpler terms, it describes how "thick" or "sticky" a fluid is. For example, honey has a higher viscosity compared to water. In the context of Poiseuille's Law, viscosity is a crucial factor because it influences how easily a fluid can move through a pipe.
- Higher viscosity means more resistance, which slows down the flow rate.
- Conversely, lower viscosity fluids flow more freely.
Pressure Difference
Pressure difference, denoted as \( \Delta P \), is a fundamental concept in fluid dynamics, influencing the movement of fluids through Pipelines. It refers to the difference in pressure between two points in a pipe.
- A greater pressure difference typically accelerates fluid flow, propelling it from the high-pressure region to the low-pressure region.
- On the contrary, a smaller pressure difference results in slower flow rates.
Flow Rate
Flow rate in fluid dynamics is the volume of fluid that moves through a specified area in a given time frame. It is often expressed in cubic meters per second \((\mathrm{m}^3/\mathrm{s})\).
- Flow rate provides valuable information about the efficiency and effectiveness of fluid systems, such as water supply networks or fuel pipelines.
- It helps in determining the optimal design and operation conditions for systems requiring precise fluid management.
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