Problem 73
Question
How many ways are there to draw 3 red marbles and 2 blue marbles from a jar that contains 10 red marbles and 12 blue marbles?
Step-by-Step Solution
Verified Answer
There are 7920 ways to draw the marbles.
1Step 1: Understand the Problem
We need to find how many ways there are to draw a specific combination of marbles from a jar. We're drawing 3 red marbles from a total of 10 red marbles and 2 blue marbles from a total of 12 blue marbles.
2Step 2: Combination Formula
The problem involves using the combination formula because the order of selection does not matter. The combination formula is given by \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \) where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
3Step 3: Calculate Red Marble Combinations
We are choosing 3 red marbles from 10. Plug these into the combination formula: \( \binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 \).
4Step 4: Calculate Blue Marble Combinations
Next, we choose 2 blue marbles from 12 blue marbles. Plug these into the combination formula: \( \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \).
5Step 5: Total Number of Ways
Since the selections of red and blue marbles are independent, the total number of ways to draw the marbles is the product of the combinations found in the previous steps: \( 120 \times 66 = 7920 \).
Key Concepts
Understanding the Combination FormulaProbability and Its Role in CombinationsBinomial Coefficient: The Heart of Combination Problems
Understanding the Combination Formula
The combination formula is a vital concept in combinatorics, helping us determine how many ways we can select items from a larger pool, without worrying about the order of selection. When faced with a problem like selecting marbles of different colors from a jar, the order in which we pick marbles doesn’t matter—it's the specific number we pick that's crucial. The combination formula is expressed as:\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \]Here's a breakdown:
! means "n factorial", multiplying all numbers from 1 to n together. - "n" represents the total number of items you're choosing from.
- "r" is the number of items to select.
Probability and Its Role in Combinations
Probability is about finding the chances of a specific event happening. And in our context of selecting marbles, it aligns perfectly with the idea of combinations. Whether for games, experiments, or simple fun jar-picking, probability tells us the likelihood of a particular draw occurring exactly the way we want.
To understand how probability plays with combination, imagine this jar again. We want to know how likely we are to draw a particular set of marbles by chance. This would imply knowing the ratio of our successful draws (our combinations) to all possible draws. However, in this exercise, we aren't asked to calculate probability but instead focus purely on knowing the number of favorable outcomes. But it’s interesting to note how probability would interact with combinations to inform us of these chances.
When we compute the combinations both for red and blue marbles and multiply them—as seen in the exercise—we basically look at all possible successful draws. The understanding of these draws is deeply rooted in probability. Knowing probability lays the groundwork for when we do want to calculate actual odds in future exercises or real-world applications.
Binomial Coefficient: The Heart of Combination Problems
The binomial coefficient is denoted by \( \binom{n}{r} \) and is often synonymous with the combination formula. It's nicknamed so because it appears prominently in binomial expansions—a separate topic rich in its own practical mathematical uses.In our scenario with marble picking: \( \binom{10}{3} \) and \( \binom{12}{2} \) are essentially binomial coefficients, highlighting their importance in choosing marbles.These coefficients serve other roles beyond our example. They're key in:
- Polynomial expansions: helping to expand expressions like \((x+y)^n\).
- Probability theory: as explored previously.
- Simplifying complex problems that involve numerous combinations.
Other exercises in this chapter
Problem 72
How many ways are there to draw a 5-card hand from a 52 -card deck?
View solution Problem 72
Write the series with summation notation. Let the lower limit equal 1. $$2+\frac{5}{8}+\frac{10}{27}+\frac{17}{64}+\frac{26}{125}+\frac{37}{216}$$
View solution Problem 73
Write the series with summation notation. Let the lower limit equal 1. $$1+\frac{1}{2^{2}}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\cdots$$
View solution Problem 74
A professor has 3 copies of an algebra book and 4 copies of a calculus text. How many distinguishable ways can the books be placed on a shelf?
View solution