Problem 73
Question
Graph the logarithmic function using transformation techniques. State the domain and range of \(f\). $$f(x)=\log (x-1)$$
Step-by-Step Solution
Verified Answer
The domain of \( f(x) = \log(x - 1) \) is \( x > 1 \) and the range is \((-\infty, \infty)\).
1Step 1: Understand the Basic Logarithmic Function
The basic logarithmic function is \( g(x) = \log(x) \). Its graph is a vertical translation of the natural logarithm. The domain of \( g(x) \) is \( x > 0 \) and the range is all real numbers.
2Step 2: Analyze the Transformation
The given function is \( f(x) = \log(x - 1) \). This function represents a horizontal shift of the basic logarithmic function. Specifically, it is shifted 1 unit to the right, which means the graph of \( g(x) = \log(x) \) will start at \( x = 1 \).
3Step 3: State the Domain
For \( f(x) = \log(x - 1) \), the expression inside the logarithm must be greater than 0. Therefore, the domain is \( x - 1 > 0 \), which simplifies to \( x > 1 \). Thus, the domain of \( f(x) \) is \( x > 1 \).
4Step 4: State the Range
The range of the logarithmic function is all real numbers because, as \( x \) approaches 1 from the right, \( f(x) = \log(x - 1) \) goes to negative infinity, and as \( x \) grows larger, it goes to positive infinity. Therefore, the range of \( f(x) \) is \( (-\infty, \infty) \).
5Step 5: Graph the Function
Begin by plotting the basic log function \( y = \log(x) \). Then shift the entire graph one unit to the right to reflect the transformation \( f(x) = \log(x - 1) \). The vertical asymptote will be at \( x = 1 \). Plot a few points to confirm the shape, such as \((2, 0)\) and \((10, 1)\), because when \( x = 2 \), \( f(x) = \log(1) = 0 \), and when \( x=10 \), \( f(x) \) is approximately \(1\).
Key Concepts
Domain and RangeTransformation TechniquesGraphing Functions
Domain and Range
When working with any logarithmic function, it is crucial to understand the concepts of domain and range. The **domain** of a function refers to all possible input values (or "x" values) for which the function is defined. For a logarithmic function like the one we've examined, the inside of the logarithm, known as the argument, must be greater than zero. Therefore, for the function \( f(x) = \log(x - 1) \), you solve \( x - 1 > 0 \), resulting in \( x > 1 \). This means that the domain of \( f \) is all numbers greater than 1.
Now let's consider the **range**. This includes all possible output values (or "y" values) the function can achieve. A distinctive property of logarithmic functions is that their range is always all real numbers. This is because, as \( x \) approaches the lowest boundary from the right (that is 1, for \( x > 1 \)), the function outputs negative infinity. Conversely, as \( x \) increases, the function outputs positive infinity. Therefore, the range of \( f(x) \) is \((-\infty, \infty)\). Such understanding of the domain and range helps in identifying the behavior of the function.
Now let's consider the **range**. This includes all possible output values (or "y" values) the function can achieve. A distinctive property of logarithmic functions is that their range is always all real numbers. This is because, as \( x \) approaches the lowest boundary from the right (that is 1, for \( x > 1 \)), the function outputs negative infinity. Conversely, as \( x \) increases, the function outputs positive infinity. Therefore, the range of \( f(x) \) is \((-\infty, \infty)\). Such understanding of the domain and range helps in identifying the behavior of the function.
Transformation Techniques
Transformation techniques involve modifying a function in a way that shifts, stretches, compresses, or reflects its graph while maintaining its basic shape. For logarithmic functions, these transformations help in translating the basic function \( g(x) = \log(x) \) into a new function.
In the function \( f(x) = \log(x - 1) \), we observe a **horizontal translation**. This happens because the function subtracts 1 from the argument. A horizontal shift always moves the graph along the x-axis. Specifically, \( x - 1 \) results in a translation rightwards by 1 unit. Hence, each point on the graph of \( \log(x) \) moves 1 unit to the right, shifting the vertical asymptote from \( x = 0 \) to \( x = 1 \). Utilizing transformations properly allows one to quickly understand how a function will appear when graphed and aids in identifying key features of the graph.
In the function \( f(x) = \log(x - 1) \), we observe a **horizontal translation**. This happens because the function subtracts 1 from the argument. A horizontal shift always moves the graph along the x-axis. Specifically, \( x - 1 \) results in a translation rightwards by 1 unit. Hence, each point on the graph of \( \log(x) \) moves 1 unit to the right, shifting the vertical asymptote from \( x = 0 \) to \( x = 1 \). Utilizing transformations properly allows one to quickly understand how a function will appear when graphed and aids in identifying key features of the graph.
Graphing Functions
Graphing a logarithmic function involves plotting points and observing the shape and direction of the graph. For the function \( f(x) = \log(x - 1) \), you begin with the parent graph of \( g(x) = \log(x) \). After understanding the transformation, implement the horizontal shift of 1 unit to the right.
When graphing, it’s helpful to plot specific points to guide the drawing. Start with calculating a few values: like \( (2, 0) \), where \( f(x) = \log(1) = 0 \), and \( (10, 1) \), where \( f(x) \approx 1 \) for \( x = 10 \). These anchor points give clarity to the shape of the graph.
When graphing, it’s helpful to plot specific points to guide the drawing. Start with calculating a few values: like \( (2, 0) \), where \( f(x) = \log(1) = 0 \), and \( (10, 1) \), where \( f(x) \approx 1 \) for \( x = 10 \). These anchor points give clarity to the shape of the graph.
- The graph passes through these calculated points.
- This graph rises to the right and falls sharply to the left but never crosses the vertical asymptote at \( x=1 \).
- Always remember, the vertical asymptote is a line the graph approaches but never touches or crosses.
Other exercises in this chapter
Problem 73
Determine whether each statement is true or false. $$\ln (x y)^{3}=(\ln x+\ln y)^{3}$$
View solution Problem 73
Plot \(f(x)=3^{x}\) and its inverse on the same graph.
View solution Problem 74
If \(\$ 9,000\) is invested in a savings account earning \(6 \%\) interest compounded continuously, how many years will pass until there is \(\$ 15,000 ?\)
View solution Problem 74
Determine whether each statement is true or false. $$\frac{\ln a}{\ln b}=\frac{\log a}{\log b}$$
View solution