Problem 73
Question
For the following problems, perform the divisions. $$ \left(6 a^{4}-2 a^{3}-3 a^{2}+a+4\right) \div(3 a-1) $$
Step-by-Step Solution
Verified Answer
Answer: The result is \(2a^3 - \frac{1}{3}a^2 + \frac{(\frac{2}{3}a + 4)}{3a - 1}\).
1Step 1: Set up the long division
Write the dividend, \((6a^4 - 2a^3 - 3a^2 + a + 4)\), inside the division symbol, and write the divisor, \((3a - 1)\), outside the division symbol, preparing for a long division process.
2Step 2: Divide the first term of dividend by the first term of divisor
For the first term of the dividend, which is \(6a^4\), divide it by the first term of the divisor, which is \(3a\). The quotient is \(2a^3\).
3Step 3: Multiply the divisor by the quotient
Multiply \((3a-1)\) by the achieved quotient term, \(2a^3\). We get \(6a^4 - 2a^3\).
4Step 4: Subtract the result from the current dividend
Line up the obtained result \(6a^4 - 2a^3\) under the dividend \((6a^4 - 2a^3 - 3a^2 + a + 4)\) and subtract. We get \((-1a^2 + a + 4)\) as the remainder.
5Step 5: Divide the highest degree term of the new remainder by the first term of divisor
Divide the term with the highest degree in the remainder, \(-a^2\), by the first term in the divisor, \(3a\). The quotient is \(-\frac{1}{3}a^2\).
6Step 6: Multiply the divisor by the quotient
Multiply \((3a-1)\) by the achieved quotient, \(-\frac{1}{3}a^2\). We get \(-a^2 + \frac{1}{3}a\).
7Step 7: Subtract the result from the current remainder
Line up the obtained result \((-1a^2 + \frac{1}{3}a)\) under the current remainder \((-1a^2 + a + 4)\), and subtract. We get the new remainder as \((\frac{2}{3}a + 4)\).
Since the degree of the new remainder is strictly less than the degree of the divisor, we cannot proceed with the division process any further.
8Step 8: Write the final answer
The final answer is the quotient terms plus the remainder of the last step divided by the divisor. Thus, the final answer is:
$$2a^3 - \frac{1}{3}a^2 + \frac{(\frac{2}{3}a + 4)}{3a - 1}$$
Key Concepts
Long Division in PolynomialsUnderstanding Dividends and DivisorsThe Quotient: Results of the DivisionInterpreting the Remainder
Long Division in Polynomials
Long division in polynomials is similar to the procedure used for dividing numbers, although it involves expressions with variables. Here, the goal is to find how many times a polynomial (the divisor) fits into another polynomial (the dividend). This process helps understand the division of expressions and is an essential tool in algebra.
- Just like with numbers, align terms by degree from highest to lowest when setting up the division.
- Follow the same repetitive steps: divide, multiply, and subtract until you can't go further.
Understanding Dividends and Divisors
In polynomial long division, the terms hold specific roles: the dividend and the divisor. The dividend is the polynomial you are dividing, while the divisor is the polynomial you are dividing by.
In our example,
In our example,
- The dividend is the polynomial \(6a^4 - 2a^3 - 3a^2 + a + 4\).
- The divisor is \(3a - 1\).
The Quotient: Results of the Division
The quotient in polynomial long division is the polynomial that represents how many times the divisor can be multiplied to fit into the dividend. In other words, it's the answer you get when you divide one polynomial by another.
Throughout the division process:
Throughout the division process:
- You find each term of the quotient by dividing the first term of the remaining polynomial by the first term of the divisor.
- The quotient's degree will generally be the difference between the degrees of the dividend and the divisor.
Interpreting the Remainder
In division, including polynomial division, the remainder is what's left after the divisor has been multiplied by the quotient and subtracted from the dividend. It should have a lesser degree than the divisor, meaning further division isn't feasible.
In the given exercise:
In the given exercise:
- The remainder we ended up with is \(\frac{2}{3}a + 4\).
- It's expressed as part of the final answer: \(\frac{(\frac{2}{3}a + 4)}{3a - 1}\).
Other exercises in this chapter
Problem 72
Factor \(10 x^{2}-17 x+3\).
View solution Problem 73
For the following problems, perform the indicated operations. $$ \frac{3 x+1}{x^{2}+3 x+2}+\frac{5 x+6}{x^{2}+6 x+5}-\frac{3 x-7}{x^{2}-2 x-35} $$
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For the following problems, solve each literal equation for the designated letter. \(I=\frac{E}{R+r}\) for \(R\)
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For the following problems, convert the given rational expressions to rational expressions having the same denominators. $$ \frac{8}{z}, \frac{3}{4 z^{3}} $$
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