Problem 73
Question
For Problems \(73-76\), simplify each complex fraction. $$ 1-\frac{n}{1-\frac{1}{n}} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{-(n^2 - n + 1)}{n-1} \).
1Step 1: Simplifying the Inner Fraction
First, concentrate on the inner fraction \( \frac{1}{n} \). The entire expression is \( 1 - \frac{n}{1 - \frac{1}{n}} \), so focus on simplifying \( 1 - \frac{1}{n} \) which is in the denominator of the second term.
2Step 2: Combining Terms in the Denominator
Express \( 1 - \frac{1}{n} \) with a common denominator: \( \frac{n}{n} - \frac{1}{n} = \frac{n-1}{n} \). This gives us a new denominator for the complex fraction.
3Step 3: Rewriting the Complex Fraction
Now substitute the simplified denominator back into the original expression: \( 1 - \frac{n}{\frac{n-1}{n}} \).
4Step 4: Simplify the Division
To simplify \( \frac{n}{\frac{n-1}{n}} \), multiply by the reciprocal: \( n \times \frac{n}{n-1} = \frac{n^2}{n-1} \).
5Step 5: Simplify the Expression
The expression becomes \( 1 - \frac{n^2}{n-1} \). Rewrite as: \( \frac{n-1}{n-1} - \frac{n^2}{n-1} = \frac{n-1-n^2}{n-1} \).
6Step 6: Final Simplification
Combine the terms in the numerator to get \( \frac{-(n^2 - n+1)}{n-1} \). This is the simplified form of the original complex fraction.
Key Concepts
Simplifying FractionsAlgebraic ExpressionsReciprocal Multiplication
Simplifying Fractions
When dealing with complex fractions, the main goal is to simplify them into a more manageable form. A complex fraction involves a fraction in the numerator, the denominator, or both.
In the example given, the complex fraction is represented as \(1 - \frac{n}{1 - \frac{1}{n}}\). Here, we see that part of this expression includes a fraction within a fraction.
When simplifying such fractions, it is often best to start with the innermost fraction. For instance, seeing \(1 - \frac{1}{n}\) within the denominator can be simplified first by finding a common denominator.
Each layer of simplification brings you closer to your final answer.
In the example given, the complex fraction is represented as \(1 - \frac{n}{1 - \frac{1}{n}}\). Here, we see that part of this expression includes a fraction within a fraction.
When simplifying such fractions, it is often best to start with the innermost fraction. For instance, seeing \(1 - \frac{1}{n}\) within the denominator can be simplified first by finding a common denominator.
- Convert \(1\) to a fraction by rewriting it as \(\frac{n}{n}\).
- Subtract \(\frac{1}{n}\) from \(\frac{n}{n}\) to get \(\frac{n-1}{n}\).
Each layer of simplification brings you closer to your final answer.
Algebraic Expressions
Handling algebraic expressions requires understanding how to combine and rearrange variables and numbers.
In this exercise, expressions are simplified step by step through arithmetic and algebraic operations. For example, expressions like \(1 - \frac{n}{\frac{n-1}{n}}\) need careful attention to order and operations. Recall these tips:
Like a puzzle, every piece fits together when you approach it systematically.
In this exercise, expressions are simplified step by step through arithmetic and algebraic operations. For example, expressions like \(1 - \frac{n}{\frac{n-1}{n}}\) need careful attention to order and operations. Recall these tips:
- Replacing complex expressions with equivalent, simpler terms aids clarity.
- Find common denominators to facilitate subtracting and adding terms within the fractions.
Like a puzzle, every piece fits together when you approach it systematically.
Reciprocal Multiplication
Multiplying by the reciprocal transforms division into multiplication, simplifying complex fractions. For instance, consider the step \(\frac{n}{\frac{n-1}{n}}\). Rather than dividing by a fraction, multiply by its reciprocal.
The reciprocal of \(\frac{n-1}{n}\) is \(\frac{n}{n-1}\). By multiplying \(n\) by the reciprocal of \(\frac{n-1}{n}\), the expression becomes \(n \cdot \frac{n}{n-1} = \frac{n^2}{n-1}\).
This approach simplifies the division process and makes the computations more straightforward. When the reciprocal is applied correctly, the complex fraction unravels into simpler terms.
The reciprocal of \(\frac{n-1}{n}\) is \(\frac{n}{n-1}\). By multiplying \(n\) by the reciprocal of \(\frac{n-1}{n}\), the expression becomes \(n \cdot \frac{n}{n-1} = \frac{n^2}{n-1}\).
This approach simplifies the division process and makes the computations more straightforward. When the reciprocal is applied correctly, the complex fraction unravels into simpler terms.
- Reciprocal multiplication is efficient and reduces errors
- Switch division into multiplication to make calculations simpler
Other exercises in this chapter
Problem 72
The link between positive and negative exponents \(\left(a^{-n}=\frac{1}{a^{n}}\right)\) along with the property \(\frac{a^{n}}{a^{m}}=a^{n-m}\) can also be use
View solution Problem 73
Add or subtract as indicated and express your answers in simplest form. (Objective 3) $$\frac{6}{x}-\frac{12}{2 x+1}$$
View solution Problem 74
Add or subtract as indicated and express your answers in simplest form. (Objective 3) $$\frac{2}{x}-\frac{6}{3 x-2}$$
View solution Problem 74
For Problems \(73-76\), simplify each complex fraction. $$ 2-\frac{3 n}{1+\frac{4}{n}} $$
View solution