Problem 73
Question
Find the limit. $$ \lim _{x \rightarrow 0} \ln (\cos x) $$
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Understand the Behavior of Cosine Function
First, recognize that as \( x \) approaches 0, \( \cos x \) approaches \( \cos(0) \), which is 1. Therefore, \( \cos x \) is close to 1 and remains positive within a small neighborhood around 0.
2Step 2: Use Natural Logarithm Properties
We need the limit of \( \ln(\cos x) \) as \( x \) approaches 0. Since \( \ln(1) = 0 \) and \( \cos x \rightarrow 1 \), if we can express \( \ln(\cos x) \) in a form that can use known limits, it can simplify the process.
3Step 3: Expand Cosine Using Taylor Series
\( \cos x \) can be expanded using its Taylor series around 0: \( \cos x = 1 - \frac{x^2}{2} + \frac{x^4}{4!} - \ldots \). For \( x \) close to 0, \( \cos x \approx 1 - \frac{x^2}{2} \).
4Step 4: Use Logarithmic Approximation
Recall the approximation for natural logarithm \( \ln(1 + u) \approx u \) when \( u \) is close to 0. Here, \( u = -\frac{x^2}{2} \), thus \( \ln(\cos x) \approx \ln(1 - \frac{x^2}{2}) \approx -\frac{x^2}{2} \).
5Step 5: Evaluate the Limit
Now calculate\( \lim _{x \rightarrow 0} \left(-\frac{x^2}{2}\right) = -\frac{1}{2} \lim _{x \rightarrow 0} x^2 = 0\) since \( \lim _{x \rightarrow 0} x^2 = 0\).
6Step 6: Final Step: Conclude the Limit
The limit is found to be 0, which means \( \lim _{x \rightarrow 0} \ln(\cos x) = 0 \). Therefore, the given limit resolves to 0 as \( x \) approaches 0.
Key Concepts
Taylor SeriesNatural LogarithmCosine Function
Taylor Series
In mathematics, the Taylor series allows us to express functions as infinite sums of terms calculated from the values of their derivatives at a single point. This is particularly useful when approximating functions near that point. For example, the Taylor series expansion of the cosine function around 0 is:
By using these series, complicated functions can be analyzed more easily at "small" values and simplified computations are enabled, as seen in this exercise where we used it to find the limit of \( \ln(\cos x) \).
- \( \cos x = 1 - \frac{x^2}{2} + \frac{x^4}{4!} - \frac{x^6}{6!} + \ldots \)
- \( \cos x \approx 1 - \frac{x^2}{2} \)
By using these series, complicated functions can be analyzed more easily at "small" values and simplified computations are enabled, as seen in this exercise where we used it to find the limit of \( \ln(\cos x) \).
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is the logarithm to the base \( e \), where \( e \) is approximately equal to 2.718. The natural logarithm is extensively used in calculus to simplify differentiation and integration processes, especially dealing with exponential functions. A key feature of the natural logarithm that is utilized in limit calculations is:
- \( \ln(1 + u) \approx u \)
- We used \( u = -\frac{x^2}{2} \)
Cosine Function
The cosine function, one of the fundamental trigonometric functions, connects an angle in a right triangle to the ratio of the adjacent side over the hypotenuse. Its analytical nature is especially useful when expressed as a Taylor series. Understanding its behavior as \( x \) approaches a certain value is important. As demonstrated in this exercise, as \( x \) approaches 0:
Such trigonometric properties assist in understanding complex expressions and their limitations. Moreover, cosine’s relation within the Taylor series framework broadens our toolbox for handling problems involving small angle approximations and facilitates smooth transitions when working in calculus.
- \( \cos x \rightarrow 1 \)
Such trigonometric properties assist in understanding complex expressions and their limitations. Moreover, cosine’s relation within the Taylor series framework broadens our toolbox for handling problems involving small angle approximations and facilitates smooth transitions when working in calculus.
Other exercises in this chapter
Problem 72
Find the limit. $$ \lim _{x \rightarrow 2} \log _{5}\left(8 x-x^{4}\right) $$
View solution Problem 72
Find \(\frac{d^{3}}{d x^{9}}\left(x^{8} \ln x\right)\)
View solution Problem 74
Find the limit. $$ \lim _{x \rightarrow+0^{+}} \ln (\sin x) $$
View solution Problem 74
Evaluate \(\lim _{x \rightarrow \pi} \frac{e^{\sin x}-1}{x-\pi}\)
View solution