Problem 73
Question
Find each product. $$(7 x+5 y)^{2}$$
Step-by-Step Solution
Verified Answer
The product of \((7 x+5 y)^{2}\) is \(49x^2 + 70xy + 25y^2\).
1Step 1: Understanding the Problem
We are given a square of a binomial. The term \((7 x+5 y)^{2}\) should be understood as \((7x+5y)*(7x+5y)\). Hence, we have to multiply the binomial by itself.
2Step 2: Expanding the Binomial
We will use the formula \((a+b)^2 = a^2+2ab+b^2\), where \(a\) is \(7x\) and \(b\) is \(5y\). Substituting these terms in place of \(a\) and \(b\), we have \((7x)^2+2*(7x)*(5y)+(5y)^2\).
3Step 3: Simplifying the Expression
Simplify each term in the expanded expression: \(49x^2 + 70xy + 25y^2\).
Other exercises in this chapter
Problem 72
Write each number in decimal notation. $$ 5.84 \times 10^{-7} $$
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simplify each algebraic expression. $$ \frac{1}{3}(3 x)+[(4 y)+(-4 y)] $$
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Explain how to multiply rational expressions.
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In Exercises \(57-84\), factor completely, or state that the polynomial is prime. $$y^{5}-81 y$$
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