Problem 73
Question
Factor using the \(A C\) method. $$ 4 x 2+28 x+40 $$
Step-by-Step Solution
Verified Answer
The expression factors to \(4(x + 2)(x + 5)\).
1Step 1: Identify A, B, and C
In the quadratic expression \(4x^2 + 28x + 40\), identify the coefficients: \(A = 4\), \(B = 28\), and \(C = 40\).
2Step 2: Compute A*C
Multiply \(A\) and \(C\) together. This gives us \(4 \times 40 = 160\).
3Step 3: Find two numbers that multiply to A*C and add to B
We need two numbers that multiply to \(160\) and add up to \(28\). After examining the factors of \(160\), the numbers \(8\) and \(20\) satisfy both conditions: \(8 \times 20 = 160\) and \(8 + 20 = 28\).
4Step 4: Rewrite the middle term using the two numbers
Rewrite the expression \(4x^2 + 28x + 40\) as \(4x^2 + 8x + 20x + 40\).
5Step 5: Factor by grouping
Group the terms: \((4x^2 + 8x) + (20x + 40)\). Factor out the common factors in each group: \(4x(x + 2) + 20(x + 2)\).
6Step 6: Factor out the common binomial
Notice \((x + 2)\) is a common factor: \((4x + 20)(x + 2)\).
7Step 7: Simplify the expression
Factor out the greatest common factor from the first part: \(4(x + 5)(x + 2)\). So the expression is factored as \(4(x + 2)(x + 5)\).
Key Concepts
AC methodcoefficientsfactoring by groupinggreatest common factor
AC method
The AC method is a popular approach for factoring quadratic equations. This technique involves using the coefficients of the quadratic equation, particularly focusing on the relationship between the terms.
To start, we need to identify the coefficients of the quadratic expression, which are typically expressed in the form of \(Ax^2 + Bx + C\). In the provided exercise, our equation is \(4x^2 + 28x + 40\), where we identify the coefficients as:
To start, we need to identify the coefficients of the quadratic expression, which are typically expressed in the form of \(Ax^2 + Bx + C\). In the provided exercise, our equation is \(4x^2 + 28x + 40\), where we identify the coefficients as:
- \(A = 4\)
- \(B = 28\)
- \(C = 40\)
coefficients
Coefficients are the numerical factors that multiply with variables in any algebraic expression or equation. In the expression \(4x^2 + 28x + 40\), the coefficients we focus on are \(4\), \(28\), and \(40\). These numbers serve different purposes in the equation:
- \(A = 4\), which is the coefficient of the \(x^2\) term
- \(B = 28\), which is the coefficient of the \(x\) term
- \(C = 40\), which is the constant term with no variable attached
factoring by grouping
Factoring by grouping is a strategic method used in breaking down complex expressions into simpler factors. This method comes in handy after you've rewritten the quadratic in a form that exposes common factors.
In this exercise, after the quadratic expression \(4x^2 + 28x + 40\) is rewritten using the numbers \(8\) and \(20\) as \(4x^2 + 8x + 20x + 40\), you then apply factoring by grouping:
In this exercise, after the quadratic expression \(4x^2 + 28x + 40\) is rewritten using the numbers \(8\) and \(20\) as \(4x^2 + 8x + 20x + 40\), you then apply factoring by grouping:
- First, group terms to enable factorization: \((4x^2 + 8x)\) and \((20x + 40)\)
- Factor out the Greatest Common Factor (GCF) from each grouped pair: from the first group, \(4x(x + 2)\), and from the second group, \(20(x + 2)\)
greatest common factor
The Greatest Common Factor (GCF) is the largest factor that divides two or more numbers. It plays a crucial role in the process of factoring expressions, particularly in factoring by grouping.
During the grouping of terms, identifying the GCF allows us to simplify groups of terms. In the expression \((4x^2 + 8x)\) and \((20x + 40)\):
During the grouping of terms, identifying the GCF allows us to simplify groups of terms. In the expression \((4x^2 + 8x)\) and \((20x + 40)\):
- The first group, \(4x^2 + 8x\), has a GCF of \(4x\). This means \(4x\times (x + 2)\) is a simplified form, where \(4x\) is factored out.
- For the second group, \(20x + 40\), the GCF is \(20\). This simplifies to \(20 \times (x + 2)\).
Other exercises in this chapter
Problem 73
The sides of a square measure \(x+3\) units. If the area is 25 square units, then find \(x\).
View solution Problem 73
Create a trinomial that does not factor and share it along with an explanation of why it does not factor.
View solution Problem 74
Solve. $$ (x-12)(x+4)(2 x-1)=0 $$
View solution Problem 74
The height of a triangle is 2 units more than its base. If the area is 40 square units, then find the length of the base.
View solution