Problem 73
Question
A fictional weak base, ZaH_ , reacts with water to yield a solution with a \(\mathrm{OH}^{-}\) ion concentration of \(2.68 \times 10^{-4}\) \(\mathrm{mol} / \mathrm{L}\) . The chemical equation for the reaction is \(\mathrm{ZaH}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1) \rightleftharpoons \mathrm{ZaH}_{3}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})\) If \(\left[\mathrm{ZaH}_{2}\right]\) at equilibrium is 0.0997 \(\mathrm{mol} / \mathrm{L}\) , what is the value of \(K_{\mathrm{b}}\) for \(\mathrm{ZaH}_{2} ?\)
Step-by-Step Solution
Verified Answer
The base dissociation constant (Kb) for ZaH2 is approximately 7.25x10⁻⁶.
1Step 1: Write the base dissociation expression for ZaH2
The base dissociation for ZaH2 can be written as:
ZaH2(aq) + H2O(l) ↔ ZaH3+(aq) + OH-(aq)
2Step 2: Determine the expression for the Kb
The expression for the base dissociation constant (Kb) can be written as:
\[ K_b = \frac{[ZaH_3^+][OH^-]}{[ZaH_2]} \]
3Step 3: Determine the change in concentrations
We are given the equilibrium concentration of ZaH2 ([ZaH2] = 0.0997 mol/L) and the concentration of OH- ions ([OH-] = 2.68x10⁻⁴ mol/L).
Let's denote the initial concentration of ZaH3+ as [ZaH3+]. Now, the change in concentration of OH- is equal to the change in concentration of ZaH3+, so we can write:
[ZaH3+] = [OH-] = 2.68x10⁻⁴ mol/L
Also, the equilibrium concentration of ZaH2:
[ZaH2] = 0.0997 mol/L
4Step 4: Find the Kb value
Now, substituting the equilibrium concentrations in the Kb expression and solving for Kb:
\[ K_b = \frac{[ZaH_3^+][OH^-]}{[ZaH_2]} = \frac{(2.68 \times 10^{-4})(2.68 \times 10^{-4})}{0.0997} \]
Calculating Kb:
Kb ≈ 7.25x10⁻⁶
So, the base dissociation constant (Kb) for ZaH2 is approximately 7.25x10⁻⁶.
Key Concepts
Weak BaseEquilibrium ConcentrationChemical Reaction EquationHydroxide Ion Concentration
Weak Base
A weak base is a base that does not completely ionize or dissociate in water. Instead of fully splitting into its ions, it establishes an equilibrium between the un-dissociated and dissociated forms. This means that in a solution of a weak base, only a small fraction of the base molecules are actually converted into ions.
For the fictional weak base ZaH₂, it partially reacts with water, meaning that not all ZaH₂ molecules will become ZaH₃⁺ and OH⁻. This incomplete association is characteristic of weak bases.
For the fictional weak base ZaH₂, it partially reacts with water, meaning that not all ZaH₂ molecules will become ZaH₃⁺ and OH⁻. This incomplete association is characteristic of weak bases.
- Weak bases have a low base dissociation constant ( K_b ), indicating limited ionization.
- They differ from strong bases, which dissociate completely in solution.
- The extent of ionization of weak bases affects their equilibrium position in chemical reactions.
Equilibrium Concentration
Equilibrium concentration refers to the concentration of reactants and products in a chemical reaction once a state of balance, or equilibrium, is reached. At equilibrium, the rate at which the reactants convert to products equals the rate at which the products revert to reactants.
In the case of ZaH₂, the equilibrium concentration is the amount of ZaH₂, ZaH₃⁺, and OH⁻ present in the solution when the reaction has reached equilibrium. Given the information:
In the case of ZaH₂, the equilibrium concentration is the amount of ZaH₂, ZaH₃⁺, and OH⁻ present in the solution when the reaction has reached equilibrium. Given the information:
- The equilibrium concentration of the weak base ZaH₂ is 0.0997 mol/L.
- The equilibrium concentration of hydroxide ions ( OH^{-} ) is 2.68×10⁻⁴ mol/L.
Chemical Reaction Equation
The chemical reaction equation represents the transformation that occurs when ZaH₂ reacts with water. For this weak base, it's essential to understand how the equation is written because it depicts the process of dissociation and equilibrium.
The balanced chemical reaction for ZaH₂ in water is depicted as: ZaH₂(aq) + H₂O(l) ↔ ZaH₃⁺(aq) + OH⁻(aq) . This equation illustrates several key points:
The balanced chemical reaction for ZaH₂ in water is depicted as: ZaH₂(aq) + H₂O(l) ↔ ZaH₃⁺(aq) + OH⁻(aq) . This equation illustrates several key points:
- **Reactants**: ZaH₂ and H₂O initially present in the reaction.
- **Products**: ZaH₃⁺ and OH⁻ formed as the base dissociates.
- **Reversibility**: The double arrow (↔) signifies that the reaction is not one-way but reaches equilibrium with both forward and reverse processes.
Hydroxide Ion Concentration
The hydroxide ion concentration (
[OH^-]
) is a crucial parameter in understanding the basicity or alkaline property of a solution. In a solution containing a weak base like ZaH₂, the
[OH^-]
tells us how many hydroxide ions are available.
For ZaH₂'s reaction with water, we've determined the hydroxide ion concentration is 2.68×10⁻⁴ mol/L at equilibrium. This ion concentration is essential for several reasons:
For ZaH₂'s reaction with water, we've determined the hydroxide ion concentration is 2.68×10⁻⁴ mol/L at equilibrium. This ion concentration is essential for several reasons:
- It determines the pH level of the solution, indicating its basic nature.
- It helps in calculating the base dissociation constant ( K_b ).
- It's a direct outcome of the dissociation of the weak base ZaH₂ in water.
Other exercises in this chapter
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Select a strong acid, and explain how you would prepare a dilute solution of the acid. Select a weak acid, and explain how you would prepare a concentrated solu
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What is the relationship between the pOH and the OH- ion concentration of a solution?
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