Problem 72
Question
Write each sentence as an equation. Let the variable \(x\) represent the number. The product of 6 and a number increased by 3 is 33 .
Step-by-Step Solution
Verified Answer
The sentence translates to the equation as \(6x + 3 = 33\).
1Step 1: Identify the variable
A number in the sentence is represented by the variable \(x\).
2Step 2: Translate the sentence into an equation
'The product of 6 and a number' translates to '6 times \(x\)', or \(6x\). 'Increased by 3' translates to 'plus 3', or \(+3\). 'is' translates to equals, or \(=\). Lastly, '33' stays as \(33\). Putting all of this together results in \(6x + 3 = 33\).
Key Concepts
Translation of Sentences to EquationsVariables in AlgebraSolving Linear Equations
Translation of Sentences to Equations
In algebra, translating sentences into equations is like decoding a message. This process involves converting a problem stated in words into mathematical language. Let’s break down how this works using the provided example sentence: "The product of 6 and a number increased by 3 is 33."
First, identify keywords:
- "The product of 6 and a number" means 6 times a number, which we express as \(6x\).
- "Increased by 3" implies we add 3, written as \(+3\).
- "Is 33" simply means equals 33, or \(= 33\).
Putting it all together creates the equation \(6x + 3 = 33\). The translation process is crucial in solving word problems algebraically as it forms the foundation for identifying relationships between values.
First, identify keywords:
- "Product" means multiplication.
- "Increased by" refers to addition.
- "Is" signals equality, like an equal sign.
- "The product of 6 and a number" means 6 times a number, which we express as \(6x\).
- "Increased by 3" implies we add 3, written as \(+3\).
- "Is 33" simply means equals 33, or \(= 33\).
Putting it all together creates the equation \(6x + 3 = 33\). The translation process is crucial in solving word problems algebraically as it forms the foundation for identifying relationships between values.
Variables in Algebra
Variables are fundamental elements in algebra, essentially acting as placeholders for numbers we seek to find. Think of them as boxes that can hold any number. In our problem, the letter \(x\) is used as the variable representing a specific number.
Key points about variables:
Understanding variables helps us manipulate and solve mathematical equations effectively. They are the bridge between the physical world and abstract mathematical representations, crucial for handling real-life problems.
Key points about variables:
- Variables allow us to create general expressions that apply to many situations.
- They are often represented by letters, with \(x\) being the most common choice.
- In equations, they are the unknowns you solve for.
Understanding variables helps us manipulate and solve mathematical equations effectively. They are the bridge between the physical world and abstract mathematical representations, crucial for handling real-life problems.
Solving Linear Equations
Solving linear equations involves finding the value of the variable that makes the equation true. Let’s use the example equation \(6x + 3 = 33\) and solve it.
- Simplify both sides of the equation if necessary.
- Perform inverse operations to isolate the variable.
- Always check the solution by substituting back into the original equation, confirming that it holds true.
- First, isolate terms involving \(x\) on one side by removing the constant term. Subtract 3 from both sides:
\(6x + 3 - 3 = 33 - 3\) simplifies to \(6x = 30\). - Next, solve for \(x\) by dividing both sides by 6:
\(\frac{6x}{6} = \frac{30}{6}\), simplifying to \(x = 5\).
- Simplify both sides of the equation if necessary.
- Perform inverse operations to isolate the variable.
- Always check the solution by substituting back into the original equation, confirming that it holds true.
Other exercises in this chapter
Problem 72
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