Problem 72
Question
Write each phrase as an algebraic expression and simplify if possible. Let \(x\) represent the unknown number. Six times the difference of a number and five
Step-by-Step Solution
Verified Answer
The expression is \(6x - 30\).
1Step 1: Identify Key Phrases
The phrase we have is 'Six times the difference of a number and five.' The important parts to identify are the operations and the unknown variable, which is given as \(x\).
2Step 2: Translate Phrases into Expression
The word 'difference' implies subtraction. 'The difference of a number and five' translates to \(x - 5\). The phrase 'six times' implies multiplication, so six times the expression \(x - 5\) is written as \(6(x - 5)\).
3Step 3: Simplify the Expression
The expression \(6(x - 5)\) can be simplified by distributing the 6 to each term inside the parentheses. Thus, \(6 \cdot x - 6 \cdot 5 = 6x - 30\).
Key Concepts
Simplifying ExpressionsTranslating Phrases to AlgebraDistributive Property
Simplifying Expressions
Simplifying an algebraic expression involves reducing it to its most concise form. This can often mean performing operations like addition, subtraction, multiplication, or division to combine like terms or eliminate unnecessary elements. When we simplify, we're aimed at making the expression easier to understand or work with. In our exercise, we start with the expression \(6(x - 5)\). By applying simplification techniques, particularly the distributive property (which we'll explore further in another section), we break down the expression step-by-step.Here's how we can approach it:
- Original Expression: \(6(x - 5)\)
- Apply Distributive Property: \(6 \cdot x - 6 \cdot 5\)
- Final Simplified Expression: \(6x - 30\)
Translating Phrases to Algebra
Translating phrases into algebraic expressions is a key skill in algebra that allows us to move between verbal statements and mathematical ones. This involves understanding the words and identifying common mathematical operations they imply. Consider the phrase from our example, 'Six times the difference of a number and five'. Here, it's crucial to:
- Recognize 'difference' as subtraction, leading to the expression \(x - 5\).
- Understand 'six times' as a multiplier (multiplication), so six times the difference becomes \(6(x - 5)\).
Distributive Property
The distributive property is a fundamental concept in algebra that helps in simplifying expressions and making calculations easier. This property states that a single term multiplied by a sum or difference inside a parenthesis can be distributed to each of the terms inside. For example, in the expression \(6(x - 5)\), you use the distributive property by multiplying 6 by each term inside the parentheses:
- Multiply 6 by \(x\) to get \(6x\).
- Multiply 6 by \(-5\) to get \(-30\).
Other exercises in this chapter
Problem 72
Decide whether the given number is a solution of the given equation. \(-x-6=-x-1 ;-10\)
View solution Problem 72
Simplify each of the following. See Example 17. $$ -(-8.4) $$
View solution Problem 72
Find the quotient of \(-\frac{5}{12}\) and \(\frac{5}{12}\).
View solution Problem 72
Insert \(,\) or \(=\) in the appropriate space to make each statement true. $$ \left|\frac{2}{5}\right| \quad\left|-\frac{2}{5}\right| $$
View solution