Problem 72
Question
The normal melting point of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), is \(5.5^{\circ} \mathrm{C}\) For the process of melting, what is the sign of each of the following? (a) \(\Delta H^{\circ}\) (b) \(\Delta S^{\circ}\) (c) \(\Delta G^{\circ}\) at \(5.5^{\circ} \mathrm{C}\) (d) \(\Delta G^{\circ}\) at \(0.0^{\circ} \mathrm{C}\) (e) \(\Delta G^{\circ}\) at \(25.0^{\circ} \mathrm{C}\)
Step-by-Step Solution
Verified Answer
(a) Positive, (b) Positive, (c) Zero, (d) Positive, (e) Negative.
1Step 1: Understanding the Concepts
Before solving the exercise, it's important to understand that the process of melting (fusion) is endothermic, which means heat is absorbed. This implies that \(\Delta H^{\circ}\) is positive. Melting also increases the randomness of the system, which means \(\Delta S^{\circ}\) is positive. \(\Delta G^{\circ}\) at the melting point is zero.
2Step 2: Evaluating \(\Delta H^{\circ}\) for Melting
For the process of melting, the enthalpy change, \(\Delta H^{\circ}\), represents the heat absorbed. Since melting is endothermic, \(\Delta H^{\circ}\) is positive.
3Step 3: Evaluating \(\Delta S^{\circ}\) for Melting
During melting, the disorder of the system increases as solid transforms into liquid. Therefore, the entropy change, \(\Delta S^{\circ}\), is positive.
4Step 4: Evaluating \(\Delta G^{\circ}\) at the Melting Point
At the melting point of a substance, the process is at equilibrium. Therefore, the Gibbs free energy change, \(\Delta G^{\circ}\), is zero at \(5.5^{\circ} \mathrm{C}\).
5Step 5: Evaluating \(\Delta G^{\circ}\) Below the Melting Point (0.0°C)
Below the melting point, the solid is more stable than the liquid form, so melting is non-spontaneous. This means \(\Delta G^{\circ}\) is positive at \(0.0^{\circ} \mathrm{C}\).
6Step 6: Evaluating \(\Delta G^{\circ}\) Above the Melting Point (25.0°C)
Above the melting point, the liquid is more stable than the solid, so melting is spontaneous. This means \(\Delta G^{\circ}\) is negative at \(25.0^{\circ} \mathrm{C}\).
Key Concepts
EnthalpyEntropyGibbs Free Energy
Enthalpy
Enthalpy (\(\Delta H\)) is a core concept in thermodynamics, especially when we talk about changes during a chemical reaction or physical process. It represents the total heat content of a system.
In the context of melting, like when benzene changes from solid to liquid at its melting point, enthalpy change tells us how much heat is absorbed. Melting is an endothermic process, meaning it requires heat. As a result:
In the context of melting, like when benzene changes from solid to liquid at its melting point, enthalpy change tells us how much heat is absorbed. Melting is an endothermic process, meaning it requires heat. As a result:
- \(\Delta H^{\circ}\) for melting is positive because heat is gained by the substance.
- This absorbed heat is necessary to overcome the forces keeping the molecules in a solid structure.
Entropy
Entropy (\(\Delta S\)) measures the degree of chaos or disorder within a system. It's a fundamental aspect of the second law of thermodynamics, which states that the entropy of an isolated system will tend to increase over time.
When a substance like benzene melts, it transitions from a structured, orderly solid to a more disordered liquid form. This change in structure naturally leads to an increase in entropy:
When a substance like benzene melts, it transitions from a structured, orderly solid to a more disordered liquid form. This change in structure naturally leads to an increase in entropy:
- \(\Delta S^{\circ}\) for melting is positive, as the disorder increases with melting.
- This increase in disorder signifies that the molecules have more freedom to move around in the liquid state.
Gibbs Free Energy
Gibbs Free Energy (\(\Delta G\)) combines enthalpy and entropy into one value, determining whether a process is spontaneous. It's calculated through the equation:\[\Delta G = \Delta H - T\Delta S\]where \(T\) is the temperature in Kelvin.
For benzene:
For benzene:
- At the melting point (\(5.5^{\circ}C\)), \(\Delta G^{\circ}\) is zero, indicating equilibrium between the solid and liquid phases.
- Below \(5.5^{\circ}C\), \(\Delta G^{\circ}\) is positive, meaning the liquid to solid transition is non-spontaneous.
- Above \(5.5^{\circ}C\), \(\Delta G^{\circ}\) is negative, indicating melting is spontaneous as the liquid phase becomes more favorable.
Other exercises in this chapter
Problem 66
Explain why each of the following statements is incorrect. (a) Entropy increases in all spontaneous reactions. (b) Reactions with a negative free energy change
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