Problem 72
Question
The minimum value of \(a \tan ^{2} x+b \cot ^{2} x\) equals the maximum value of \(a \sin ^{2} \theta+b \cos ^{2} \theta\) where \(a>b>0\), when (A) \(a=b\) (B) \(a=2 b\) (C) \(a=3 b\) (D) \(a=4 b\)
Step-by-Step Solution
Verified Answer
The answer is (D) \(a=4b\).
1Step 1: Expression for Minimum Value
To find the minimum value of the expression \(a \tan^2 x + b \cot^2 x\), we express it as \(a \frac{\sin^2 x}{\cos^2 x} + b \frac{\cos^2 x}{\sin^2 x}\). Let \(t = \tan^2 x\). Then the expression becomes \(a t + \frac{b}{t}\).
2Step 2: Using AM-GM Inequality
By the AM-GM inequality, \(a t + \frac{b}{t} \geq 2 \sqrt{a \cdot \frac{b}{t} \cdot t} = 2 \sqrt{ab}\). The equality holds when \(a t = \frac{b}{t}\), giving \(t = \sqrt{\frac{b}{a}}\). Thus, the minimum value is \(2 \sqrt{ab}\).
3Step 3: Expression for Maximum Value
To find the maximum value of \(a \sin^2 \theta + b \cos^2 \theta\), we express it as \(a \sin^2 \theta + b (1 - \sin^2 \theta) = (a-b) \sin^2 \theta + b\). This is a quadratic in \(\sin^2 \theta\).
4Step 4: Maximizing the Quadratic Expression
The expression \((a-b) \sin^2 \theta + b\) is maximized when \(\sin^2 \theta = 1\) if \(a-b > 0\). Thus, the maximum value is \(a\).
5Step 5: Equating Minimum and Maximum Values
We set the minimum value \(2 \sqrt{ab}\) equal to the maximum value \(a\). Solving the equation \(a = 2 \sqrt{ab}\), square both sides to get \(a^2 = 4ab\) leading to \(a = 4b\).
6Step 6: Conclusion
From the calculations, the correct answer is choice \(a=4b\) that satisfies the requirement of the minimum value of the given expression equaling the maximum value.
Key Concepts
Trigonometric IdentitiesAM-GM InequalityQuadratic Optimization
Trigonometric Identities
In trigonometry, identities play a crucial role in simplifying and solving equations. A **trigonometric identity** is an equation involving trigonometric functions that is true for all angles. These identities help us transform complex expressions into more manageable forms.
For example, the Pythagorean identity, \( \sin^2 \theta + \cos^2 \theta = 1 \), is fundamental when dealing with expressions like \( a \sin^2 \theta + b \cos^2 \theta \). By substituting trigonometric identities, we can rewrite expressions to make calculations easier or extract maximum or minimum values.
Another important identity is \( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} \). This allows expressions involving tangent and cotangent, like \( a \tan^2 x + b \cot^2 x \), to be written in a way that's more convenient for application of tools like the AM-GM inequality. Identifying and using these identities effectively is key to solving many trigonometric problems in mathematics.
For example, the Pythagorean identity, \( \sin^2 \theta + \cos^2 \theta = 1 \), is fundamental when dealing with expressions like \( a \sin^2 \theta + b \cos^2 \theta \). By substituting trigonometric identities, we can rewrite expressions to make calculations easier or extract maximum or minimum values.
Another important identity is \( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} \). This allows expressions involving tangent and cotangent, like \( a \tan^2 x + b \cot^2 x \), to be written in a way that's more convenient for application of tools like the AM-GM inequality. Identifying and using these identities effectively is key to solving many trigonometric problems in mathematics.
AM-GM Inequality
The **Arithmetic Mean-Geometric Mean (AM-GM) Inequality** is a useful tool in optimization problems. It states that for any non-negative real numbers \( x \) and \( y \), the arithmetic mean is always greater than or equal to the geometric mean:
In the problem, we utilize this inequality to find the minimum of \( a t + \frac{b}{t} \) where \( t = \tan^2 x \). Applying AM-GM to the terms gives \( a t + \frac{b}{t} \geq 2\sqrt{ab} \), showing that the minimum value occurs when \( t = \sqrt{\frac{b}{a}} \). The AM-GM inequality is particularly handy in proving minimum/maximum values where variables are constrained by a product or sum.
- AM: \( \frac{x + y}{2} \)
- GM: \( \sqrt{xy} \)
In the problem, we utilize this inequality to find the minimum of \( a t + \frac{b}{t} \) where \( t = \tan^2 x \). Applying AM-GM to the terms gives \( a t + \frac{b}{t} \geq 2\sqrt{ab} \), showing that the minimum value occurs when \( t = \sqrt{\frac{b}{a}} \). The AM-GM inequality is particularly handy in proving minimum/maximum values where variables are constrained by a product or sum.
Quadratic Optimization
**Quadratic optimization** involves finding the extrema (minimum or maximum values) of quadratic functions. Such functions can be of the form \( ax^2 + bx + c \). Optimization requires analyzing the function's behavior, usually its vertex, which gives the function's minimum or maximum value.
In this exercise, to find the maximum of \( a \sin^2 \theta + b \cos^2 \theta \), we rearrange it as \( (a - b) \sin^2 \theta + b \). This peaks when \( \sin^2 \theta = 1 \), if \( a > b \), yielding a maximum value of \( a \).
Quadratic optimization involves using calculus, completing the square, or leveraging symmetrical properties to efficiently/effectively find these extreme points. Understanding this process is crucial in many applied mathematics fields, including physics and economics, where optimizing outcomes is often required.
In this exercise, to find the maximum of \( a \sin^2 \theta + b \cos^2 \theta \), we rearrange it as \( (a - b) \sin^2 \theta + b \). This peaks when \( \sin^2 \theta = 1 \), if \( a > b \), yielding a maximum value of \( a \).
Quadratic optimization involves using calculus, completing the square, or leveraging symmetrical properties to efficiently/effectively find these extreme points. Understanding this process is crucial in many applied mathematics fields, including physics and economics, where optimizing outcomes is often required.
Other exercises in this chapter
Problem 69
The equation \(x+e^{x}=0\) has (A) only one real root (B) only two real roots (C) no real root (D) None of these
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If \(f^{\prime \prime}(x)
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If \(f(x)=\frac{x^{2}-1}{x^{2}+1}\), for every real number, then minimum value of \(f\) (A) Does not exist (B) Is note attained even through \(f\) is bounded (C
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If \(y=a \log |x|+b x^{2}+x\) has its extremum values at \(x=-1\) and \(x=2\), then (A) \(a=2, b=-1\) (B) \(a=2, b=-1 / 2\) (C) \(a=-2, b=1 / 2\) (D) None of th
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