Problem 72
Question
Sketch a graph of a quadratic function that satisfies each set of given conditions. Use symmetry to label another point on your graph. Minimum value of \(-4\) at \(x=-3 ; y\) -intercept is \((0,3)\)
Step-by-Step Solution
Verified Answer
The quadratic function is \( y = \frac{7}{9}(x+3)^2 - 4 \), with a symmetric point at \((-6, 3)\).
1Step 1: Understanding the vertex form of a quadratic function
The vertex form of a quadratic function is given by \( y = a(x-h)^2 + k \), where \( (h, k) \) is the vertex of the parabola. In this exercise, the minimum value of the quadratic function (which is the vertex) is given as \((-4, -3)\). This tells us that the vertex is \((-3, -4)\).
2Step 2: Using the vertex information
We can substitute the vertex \((-3, -4)\) into the vertex form of the quadratic function, getting \( y = a(x+3)^2 - 4 \). We still need to find the value of \( a \).
3Step 3: Plugging in the y-intercept
We know the function passes through \((0, 3)\), the y-intercept. Substitute these values into the vertex form equation: \( 3 = a(0+3)^2 - 4 \).
4Step 4: Solving for the coefficient 'a'
Substituting in the y-intercept gives us \( 3 = 9a - 4 \). Solving for \( a \), we first add 4 to both sides to get \( 7 = 9a \), and then divide by 9 to get \( a = \frac{7}{9} \).
5Step 5: Writing the complete quadratic equation
Substituting \( a = \frac{7}{9} \) into the vertex form of the equation, we get: \( y = \frac{7}{9}(x+3)^2 - 4 \).
6Step 6: Identifying another point using symmetry
Using the axis of symmetry \(x = -3\), we can find a point symmetrical to \((0, 3)\). \( x = -3\) is the line of symmetry; since the distance from \(x = -3\) to \(x = 0\) is 3, another symmetrical point is \((-6, 3)\).
Key Concepts
Vertex FormParabolaY-interceptSymmetry in Graphs
Vertex Form
When it comes to quadratic functions, the vertex form is a powerful tool. This form is expressed as \( y = a(x-h)^2 + k \). Here, \((h, k)\) represents the vertex of the parabola, acting like a pinpointed location on the graph.
The "a" determines how open or narrow the parabola looks. If \(a\) is positive, the parabola opens upwards; if it's negative, it opens downwards.
The "a" determines how open or narrow the parabola looks. If \(a\) is positive, the parabola opens upwards; if it's negative, it opens downwards.
- The vertex \((h, k)\) is a key point where the parabola changes direction. For our exercise, that point is \((-3, -4)\), meaning the lowest spot on our graph occurs at this coordinate.
Parabola
A parabola is the curved shape that's formed by graphing a quadratic function. Think of it like a gentle U or sometimes an upside-down U, depending on the direction it faces.
Each parabola includes:
Each parabola includes:
- A vertex: the peak or the dip.
- An axis of symmetry: a vertical line passing through the vertex, dividing the shape into two identical parts.
- An opening direction determined by the sign of \(a\) in the vertex form equation.
Y-intercept
The y-intercept of a graph is the point where the graph crosses the y-axis. For our quadratic function, this point is given as \((0, 3)\).
It's easy to find because to do so, you just set \(x = 0\) in the function equation:
Substitute into \( y = \frac{7}{9}(x+3)^2 - 4 \):
\( y = \frac{7}{9}(0+3)^2 - 4 \) simplifies directly to \( y = 3 \), confirming the given y-intercept.
It's easy to find because to do so, you just set \(x = 0\) in the function equation:
Substitute into \( y = \frac{7}{9}(x+3)^2 - 4 \):
\( y = \frac{7}{9}(0+3)^2 - 4 \) simplifies directly to \( y = 3 \), confirming the given y-intercept.
- The y-intercept plays a crucial role in sketching graphs, acting as a reference for symmetry and helping identify the shape's scale and correct placement.
Symmetry in Graphs
Symmetry in graphs makes understanding and sketching parabolas easier. The axis of symmetry of a parabola with vertex form \( y = a(x-h)^2 + k \) is the vertical line \( x = h \).
This essentially splits the graph into two equal halves, so any point on one side has a twin over this axis.
This essentially splits the graph into two equal halves, so any point on one side has a twin over this axis.
- In our exercise, the axis of symmetry is \( x = -3 \).
- Given the y-intercept \((0, 3)\), you can find another point on the graph by reflecting across this symmetry line, resulting in \((-6, 3)\).
Other exercises in this chapter
Problem 71
Evaluate the discriminant, and use it to determine the number of real solutions of the equation. If the equation does have real solutions, tell whether they are
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Multiply as indicated. Write each product in standard form. $$(3-i)(3+i)(2-6 i)$$
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Use the given zero to completely factor \(P(x)\) into linear factors. $$\text { Zero: }-3 i ; P(x)=x^{5}+2 x^{4}+10 x^{3}+20 x^{2}+9 x+18$$
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