Problem 72
Question
Select the lesser of the two given numbers. \(-|-2|,-|-3|\)
Step-by-Step Solution
Verified Answer
-|-3| is lesser.
1Step 1 - Understand Absolute Values
Firstly, recall what the absolute value function does. The absolute value of a number is its distance from zero on the number line, regardless of direction, denoted as \(|x|\). For example, \(|-2| = 2\) and \(|-3| = 3\).
2Step 2 - Calculate Inner Absolute Values
Calculate the absolute values within the given expressions: \(|-2| = 2\) and \(|-3| = 3\).
3Step 3 - Apply Negations
Apply the negation to the absolute values you calculated: \(-|2| = -2\) and \(-|3| = -3\).
4Step 4 - Compare the Results
Now compare the two values: \(-2\) and \(-3\) to determine which one is lesser. Since \(-3\) is less than \(-2\), \(-3\) is the smaller number.
Key Concepts
Absolute Value PropertiesNumber LineNegation of Absolute Value
Absolute Value Properties
The absolute value of a number is how far that number is from zero on the number line, without considering direction. The symbol for absolute value is two vertical bars around a number, such as \(|x|\). Here are some key properties of absolute value:
\[ |a| \geq 0 \]This means that the absolute value of any number is always non-negative.
\[ |a| = |-a| \]This property tells us that the absolute value of a number is the same as its opposite. For example, \(|-5| = 5\) and \(|5| = 5\).
\[ |a \cdot b| = |a| \cdot |b| \]The absolute value of a product is the product of the absolute values. For instance, \(|2 \cdot -4| = |2| \cdot |-4| = 8\).
Understanding these properties helps us simplify expressions involving absolute values, such as in our exercise where \(|-2| == 2\) and \(|-3| == 3\).
\[ |a| \geq 0 \]This means that the absolute value of any number is always non-negative.
\[ |a| = |-a| \]This property tells us that the absolute value of a number is the same as its opposite. For example, \(|-5| = 5\) and \(|5| = 5\).
\[ |a \cdot b| = |a| \cdot |b| \]The absolute value of a product is the product of the absolute values. For instance, \(|2 \cdot -4| = |2| \cdot |-4| = 8\).
Understanding these properties helps us simplify expressions involving absolute values, such as in our exercise where \(|-2| == 2\) and \(|-3| == 3\).
Number Line
A number line is a visual representation of numbers stretched out on a straight line.
Zero is located at the center, with positive numbers to the right and negative numbers to the left.
Absolute value represents the distance of a number from zero, without focusing on direction.
For example, on a number line:
By plotting numbers on a number line, it simplifies the comparison of values and their absolute equivalents.
Zero is located at the center, with positive numbers to the right and negative numbers to the left.
Absolute value represents the distance of a number from zero, without focusing on direction.
For example, on a number line:
- The distance between -2 and 0 is 2 units.
- The distance between -3 and 0 is 3 units.
By plotting numbers on a number line, it simplifies the comparison of values and their absolute equivalents.
Negation of Absolute Value
Negation involves changing the sign of a number.
When negating an absolute value, \-|x|\, you are essentially taking the positive distance and converting it to a negative value.
Let's look at our exercise:
In this context, \-3\ is smaller because it is further to the left on the number line.
When negating an absolute value, \-|x|\, you are essentially taking the positive distance and converting it to a negative value.
Let's look at our exercise:
- Calculate \(|-2| == 2\)
- Then negate: \(-|2| == -2\)
- Calculate \(|-3| == 3\)
- Then negate: \(-|3| == -3\)
In this context, \-3\ is smaller because it is further to the left on the number line.
Other exercises in this chapter
Problem 72
The sum of six-fifths of a number and 2 is 14 .
View solution Problem 72
Find each difference. $$ \frac{9}{10}-\left(\frac{1}{8}-\frac{3}{10}\right) $$
View solution Problem 72
Simplify each expression. \(5 x+3(7-2 x)\)
View solution Problem 72
Perform each indicated operation. \(4(-8)+|4-15|\)
View solution