Problem 72
Question
Perform the operations and simplify. $$ \frac{x^{3}+1}{4} \div \frac{x+1}{2} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{1}{2}(x^2-x+1) \).
1Step 1: Rewrite Division as Multiplication
To simplify the expression, start by rewriting the division problem as a multiplication problem. Use the property \( \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} \). Thus, \( \frac{x^3 + 1}{4} \div \frac{x+1}{2} \) becomes \( \frac{x^3 + 1}{4} \times \frac{2}{x+1} \).
2Step 2: Combine the Fractions
Now that we have a multiplication problem, multiply the numerators together and the denominators together. This gives us: \[ \frac{(x^3 + 1) \times 2 }{4 \times (x+1)} = \frac{2(x^3 + 1)}{4(x+1)}. \]
3Step 3: Simplify the Expression
Simplify the expression \( \frac{2(x^3 + 1)}{4(x+1)} \). Notice that \( x^3 + 1 \) can be factored using the sum of cubes formula: \( x^3 + 1 = (x+1)(x^2-x+1) \). Substituting this back into the expression, we have: \[ \frac{2((x+1)(x^2-x+1))}{4(x+1)}. \]
4Step 4: Cancel Common Factors
In the fraction \( \frac{2((x+1)(x^2-x+1))}{4(x+1)} \), \( (x+1) \) is a common factor in the numerator and the denominator. Cancel \( (x+1) \) to simplify the expression: \[ \frac{2(x^2-x+1)}{4}. \]
5Step 5: Reduce the Coefficients
The coefficients \(2\) and \(4\) can be simplified: \( \frac{2}{4} = \frac{1}{2} \). Therefore, the expression simplifies to: \( \frac{1}{2}(x^2-x+1) \). This can be left in its factored form or expanded: \[ \frac{x^2}{2} - \frac{x}{2} + \frac{1}{2}. \]
Key Concepts
Fraction DivisionMultiplication of FractionsSimplifying Algebraic ExpressionsFactoring Algebraic Expressions
Fraction Division
Understanding fraction division is key to many algebra problems. When dividing fractions, remember to multiply by the reciprocal of the divisor. For example, if we have \( \frac{a}{b} \div \frac{c}{d} \), it is the same as \( \frac{a}{b} \times \frac{d}{c} \). This works because dividing by a fraction is equivalent to multiplying by its inverse.
In our exercise, the division \( \frac{x^3 + 1}{4} \div \frac{x + 1}{2} \) converts into the multiplication \( \frac{x^3 + 1}{4} \times \frac{2}{x + 1} \). This step changes a division problem into a multiplication one, which is often simpler to handle with fractions.
In our exercise, the division \( \frac{x^3 + 1}{4} \div \frac{x + 1}{2} \) converts into the multiplication \( \frac{x^3 + 1}{4} \times \frac{2}{x + 1} \). This step changes a division problem into a multiplication one, which is often simpler to handle with fractions.
Multiplication of Fractions
Once you've rewritten a division problem as multiplication, combining the fractions becomes straightforward. Fractions are multiplied by multiplying their numerators together and their denominators together. In the exercise, after converting the division into multiplication, we obtain: \[ \frac{(x^3 + 1) \times 2}{4 \times (x + 1)}. \]
Here's how to do it:
Here's how to do it:
- Multiply the numerators: \( (x^3 + 1) \times 2 = 2(x^3 + 1) \).
- Multiply the denominators: \( 4 \times (x + 1) = 4(x + 1) \).
Simplifying Algebraic Expressions
Simplifying is about making an expression more manageable by eliminating unnecessary parts. In our exercise, we start with \( \frac{2(x^3 + 1)}{4(x + 1)} \).
To simplify:
To simplify:
- First, recognize any patterns - here, \( x^3 + 1 \) is a sum of cubes, which factors into \( (x+1)(x^2-x+1) \).
- Substitute this back into the fraction, giving \( \frac{2((x+1)(x^2-x+1))}{4(x+1)} \).
Factoring Algebraic Expressions
Factoring is an essential skill for simplifying and solving algebraic expressions. In the context of simplifying fractions, it helps in identifying terms that can be canceled.
Consider the expression \( x^3 + 1 \), which uses the sum of cubes formula: \( a^3 + b^3 = (a+b)(a^2-ab+b^2) \). With \( a = x \) and \( b = 1 \), it becomes \( (x+1)(x^2-x+1) \).
This allows for the expression to be rewritten and simplified:
Consider the expression \( x^3 + 1 \), which uses the sum of cubes formula: \( a^3 + b^3 = (a+b)(a^2-ab+b^2) \). With \( a = x \) and \( b = 1 \), it becomes \( (x+1)(x^2-x+1) \).
This allows for the expression to be rewritten and simplified:
- Cancel out \( (x+1) \) in the numerator and denominator: \( \frac{2((x+1)(x^2-x+1))}{4(x+1)} \Rightarrow \frac{2(x^2-x+1)}{4} \).
- Always check for commonality in expressions—eliminating them refines the solution.
Other exercises in this chapter
Problem 72
Use a proportion to solve each problem. Recommended Dosages. The recommended child's dose of the sedative hydroxine is 0.006 gram per kilogram of body mass. Fin
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Perform each division. \(\frac{2 x^{4}+3 x^{3}+3 x^{2}-5 x-3}{2 x^{2}-x-1}\)
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Simplify each expression. If an expression cannot be simplified, write "Does not simplify." $$ \frac{4 x^{2}+24 x+32}{16 x^{2}+8 x-48} $$
View solution Problem 73
Use synthetic division to perform each division. Divide \(a^{5}-1\) by \(a-1\)
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