Problem 72
Question
Multiply. \((4+2 \sqrt{3})(6-3 \sqrt{3})\)
Step-by-Step Solution
Verified Answer
The product of \((4+2 \sqrt{3})(6-3 \sqrt{3})\) is 6.
1Step 1: Apply the FOIL method
Start by multiplying the two first terms together, followed by the outer terms, then the inner terms, and finally, the last terms. The FOIL method can be written as follows: \((4+2 \sqrt{3})(6-3 \sqrt{3})\) = \(4*6 + 4*(-3\sqrt{3}) + 2\sqrt{3}*6 + 2\sqrt{3}*(-3\sqrt{3})\)
2Step 2: Simplify the terms
Now, simplify each of the terms from the FOIL process: = \(24 - 12\sqrt{3} + 12\sqrt{3} - 18\)
3Step 3: Combine like terms
Combine the like terms: = \(24 - 18 = 6\)
Key Concepts
Multiplying BinomialsSimplifying Radical ExpressionsAlgebraic Expressions
Multiplying Binomials
When multiplying binomials, the FOIL method comes in handy. FOIL stands for First, Outer, Inner, Last. This is a systematic way of multiplying each term in one binomial by each term in the other binomial. Let's illustrate this with the binomials
- First: Multiply the first terms in each binomial: \(4 \times 6 = 24\).
- Outer: Multiply the outer terms: \(4 \times (-3\sqrt{3}) = -12\sqrt{3}\).
- Inner: Multiply the inner terms: \(2\sqrt{3} \times 6 = 12\sqrt{3}\).
- Last: Multiply the last terms: \(2\sqrt{3} \times (-3\sqrt{3}) = -18\).
Simplifying Radical Expressions
Simplifying radical expressions is an essential skill in many algebraic problems. In our example, after applying FOIL, you end up with terms like \(-12\sqrt{3}\) and \(12\sqrt{3}\). Simplifying these requires recognizing and combining like terms.
When two radicals are identical, you can treat them like variables or numbers in terms of addition and subtraction:
When two radicals are identical, you can treat them like variables or numbers in terms of addition and subtraction:
- For example, \(-12\sqrt{3} + 12\sqrt{3}\) results in \(0\sqrt{3}\), which simplifies to 0.
Algebraic Expressions
An algebraic expression consists of numbers, variables, and operational symbols. In our example, the expression \((4 + 2\sqrt{3})(6 - 3\sqrt{3})\) is a product of two binomials. We use the FOIL method to expand it and simplify the expression further.
Terms inside an algebraic expression can include integers, fractions, and radicals. When expanding, you must be mindful of handling these various elements correctly.
After multiplying and simplifying using the FOIL method, the result becomes: \(24 - 18\)
Terms inside an algebraic expression can include integers, fractions, and radicals. When expanding, you must be mindful of handling these various elements correctly.
After multiplying and simplifying using the FOIL method, the result becomes: \(24 - 18\)
- The radical expressions have already been simplified to 0, as they are canceled out.
- Finally, simplifying the entire expression, we find that it equals 6.
Other exercises in this chapter
Problem 72
Let \(f(x)=x^{2}+1\) and \(g(x)=3 x .\) Find each value. \((f \circ g)(-3)\)
View solution Problem 72
Find the inverse of each function, Is the inverse a function? $$ y=5-2 x $$
View solution Problem 72
Simplify each radical expression. Use absolute value bars where they are needed. $$ \sqrt[3]{-64 a^{3} b^{6}} $$
View solution Problem 73
Let \(f(x)=x^{2}+1\) and \(g(x)=3 x .\) Find each value. \((g \circ f)\left(\frac{1}{2}\right)\)
View solution