Problem 72
Question
Let the domain of \(f(x)\) be [-1,2] and the range be \([0,3] .\) Find the domain and range of the following. $$f(x-3)+1$$
Step-by-Step Solution
Verified Answer
Domain: [2, 5]; Range: [1, 4].
1Step 1: Determine the New Domain
To find the domain of the transformed function \(f(x-3)+1\), start with the original domain of \([-1, 2]\). Since \(x-3\) shifts the graph 3 units to the right, we need to set \(x-3 = a\) where \(a\) is in \([-1, 2]\). This implies \(x = a + 3\). Thus, the new domain is obtained by adding 3 to each element of the original domain: \[x \,\text{ranges from} \, -1 + 3 \,\text{to}\, 2 + 3\]making it \([2, 5]\).
2Step 2: Determine the New Range
For the range, start with the original range of \([0, 3]\). The transformation \(+1\) shifts all function values up by 1 unit. Thus, add 1 to each element of the original range: \[y \,\text{ranges from} \, 0 + 1 \,\text{to}\, 3 + 1\]making the new range \([1, 4]\).
3Step 3: Conclude the Domain and Range
After calculating the transformations: - The new domain of \(f(x-3)+1\) is \([2, 5]\).- The new range of \(f(x-3)+1\) is \([1, 4]\).
Key Concepts
Domain and RangeShifts in GraphsPiecewise Functions
Domain and Range
Understanding the domain and range of a function is crucial for analyzing its behavior. The **domain** refers to all the possible input values (usually represented as "x") of a function. In our original function, the domain is after this transformation becomes
- - Finding New Domain: Since the function transforms with "\(- 3\)", each input is effectively moved right by 3. Add 3 to the starting and ending values of the original domain.
- - Finding New Range: The "\(+1\)" in the function shifts every output ymax and ymin upwards by 1, tweaking the original range intervals.
Shifts in Graphs
Graph shifts form a fundamental part of function transformations. These shifts can occur either horizontally or vertically, depending on how the equation of a function is structured.
- **Horizontal Shifts**: If you have a function \(f(x)\) and replace x with \((x-c)\), it shifts the graph horizontally.
- **Vertical Shifts**: When you see a \(+c\) or \(-c\) outside the function, it shifts "up" or "down" accordingly.
Piecewise Functions
Piecewise functions represent scenarios where a function changes its behavior at certain points within its domain. They are often written like this:\[ f(x) = \begin{cases} \text{expression 1,} & \text{for x in range 1} \ \text{expression 2,} & \text{for x in range 2} \end{cases} \] Piecewise functions show different rules or expressions applied to different intervals of the domain. They are particularly insightful for modeling situations with distinct phases.In the context of transformations like \(f(x-3)+1\), you can think about applying transformations to each piece or interval separately. For example:
- **Handling Domain**: Shifts in the expression could influence which part of the piecewise function is relevant when evaluating a particular range of values.
- **Adapting Range**: The vertical shifts affect the resulting outputs of the entire function.
Other exercises in this chapter
Problem 72
Each function is either even or odd Evaluate \(f(-x)\) to determine which situation applies. $$f(x)=\frac{x^{2}+5}{x}$$
View solution Problem 72
For each function find (a) \(f(x+h)\) and (b) \(f(x)+f(h)\) $$f(x)=5 x^{2}+x$$
View solution Problem 73
Each function is either even or odd Evaluate \(f(-x)\) to determine which situation applies. $$f(x)=\sqrt[3]{x^{3}-5 x}$$+
View solution Problem 73
For each function find (a) \(f(x+h)\) and (b) \(f(x)+f(h)\) $$f(x)=3 x-x^{2}$$
View solution