Problem 72
Question
In Exercises 67-72, (a) determine the quadrant in which \( u/2 \) lies, and (b) find the exact values of \( \sin(u/2) \), \( \cos(u/2) \), and \( \tan(u/2) \) using the half-angle formulas. \( \sec u = \dfrac{7}{2}, \dfrac{3\pi}{2} < u < 2\pi \)
Step-by-Step Solution
Verified Answer
The exact values of the half-angles are: \( \sin(u/2) = \sqrt{\frac{5}{14}} \), \( \cos(u/2) = -\sqrt{\frac{9}{14}} \), and \( \tan(u/2) = \sqrt{\frac{5}{9}} \). And \( u/2 \) lies in the 2nd quadrant.
1Step 1: Determine the quadrant of \( u/2 \)
Given the relation \( \frac{3\pi}{2} < u < 2\pi \), the division of each part by 2 gives \( \frac{3\pi}{4} < \frac{u}{2} < \pi \). This shows that \( u/2 \) is located in the 2nd quadrant.
2Step 2: Calculate \( \cos u \)
We know \( \sec u = \frac{7}{2} \), and since \( \sec u = \frac{1}{\cos u} \), this allows us to find \( \cos u = \frac{2}{7} \).
3Step 3: Apply half-angle formulas for each trigonometric function
For half-angle formulas, the sine, cosine and tangent of \( u/2 \) are computed as follows: \( \sin(u/2) = \pm \sqrt{\frac{1 - \cos u}{2}} = \sqrt{\frac{1 - 2/7}{2}} = \sqrt{\frac{5}{14}} \), \( \cos(u/2) = \pm \sqrt{\frac{1 + \cos u}{2}} = \sqrt{\frac{1 + 2/7}{2}} = \sqrt{\frac{9}{14}} \), and \( \tan(u/2) = \frac{\sin(u/2)}{\cos(u/2)} = \frac{\sqrt{\frac{5}{14}}}{\sqrt{\frac{9}{14}}} = \sqrt{\frac{5}{9}} \). In the 2nd quadrant, \( \sin \) and \( \tan \) are positive, and \( \cos \) is negative, so we choose the positive root for \( \sin \) and \( \tan \), and the negative root for \( \cos \).
Key Concepts
Trigonometric IdentitiesSecant FunctionQuadrants of AnglesExact Trigonometric Values
Trigonometric Identities
Trigonometric identities are essential tools in mathematics that help simplify expressions, solve equations, and prove relationships involving trigonometric functions. One of the key sets of identities involves half-angle identities, which are particularly useful when finding the sine, cosine, or tangent of half an angle.
To find the trigonometric functions for half angles, we use specific formulas:
To find the trigonometric functions for half angles, we use specific formulas:
- For sine: \( \sin(\frac{u}{2}) = \pm \sqrt{\frac{1 - \cos u}{2}} \)
- For cosine: \( \cos(\frac{u}{2}) = \pm \sqrt{\frac{1 + \cos u}{2}} \)
- For tangent: \( \tan(\frac{u}{2}) = \frac{\sin(\frac{u}{2})}{\cos(\frac{u}{2})} \)
Secant Function
The secant function, denoted as \( \sec \), is the reciprocal of the cosine function. In trigonometry, it is defined as \( \sec u = \frac{1}{\cos u} \).
This relationship hints at how knowing either \( \sec u \) or \( \cos u \) can help us find the other. For example, given \( \sec u = \frac{7}{2} \), we can deduce that \( \cos u = \frac{2}{7} \).
The secant function is particularly useful in various applications, including solving problems involving right triangles and simplifying expressions. Since secant is related to the cosine, it's important to remember that when \( \cos u \) approaches zero, \( \sec u \) tends toward infinity, highlighting their reciprocal nature.
This relationship hints at how knowing either \( \sec u \) or \( \cos u \) can help us find the other. For example, given \( \sec u = \frac{7}{2} \), we can deduce that \( \cos u = \frac{2}{7} \).
The secant function is particularly useful in various applications, including solving problems involving right triangles and simplifying expressions. Since secant is related to the cosine, it's important to remember that when \( \cos u \) approaches zero, \( \sec u \) tends toward infinity, highlighting their reciprocal nature.
Quadrants of Angles
Understanding the quadrants of an angle is crucial in determining the sign of trigonometric functions. The coordinate plane is divided into four quadrants: 1st, 2nd, 3rd, and 4th, and they are counterclockwise from the positive x-axis.
Each quadrant affects the sign of trigonometric functions:
Each quadrant affects the sign of trigonometric functions:
- 1st Quadrant: All trigonometric functions are positive.
- 2nd Quadrant: Sine is positive; cosine and tangent are negative.
- 3rd Quadrant: Tangent is positive; sine and cosine are negative.
- 4th Quadrant: Cosine is positive; sine and tangent are negative.
Exact Trigonometric Values
Exact trigonometric values are values that can be represented without approximation. They often involve square roots or fractions and are preferred in mathematics for precision.
Using half-angle formulas enables us to express trigonometric values exactly. For instance, with \( \cos u = \frac{2}{7} \), one can find:
Using half-angle formulas enables us to express trigonometric values exactly. For instance, with \( \cos u = \frac{2}{7} \), one can find:
- \( \sin(\frac{u}{2}) = \sqrt{\frac{5}{14}} \)
- \( \cos(\frac{u}{2}) = -\sqrt{\frac{9}{14}} \)
- \( \tan(\frac{u}{2}) = \sqrt{\frac{5}{9}} \)
Other exercises in this chapter
Problem 71
In Exercises 71 and 72, determine whether the statement is true or false. Justify your answer. There can be more than one way to verify a trigonometric identity
View solution Problem 71
In Exercises 71 - 74, perform the multiplication and use the fundamental identities to simplify. There is more than one correct form of each answer. \( \left(\s
View solution Problem 72
In Exercises 71 - 74, simplify the expression algebraically and use a graphing utility to confirm your answer graphically. \( \cos(\pi + x) \)
View solution Problem 72
In Exercises 63 - 74, use inverse functions where needed to find all solutions of the equation in the interval \( [0,2\pi) \). \( \sec^2 x + 2 \sec x - 8 = 0 \)
View solution