Problem 72
Question
If \(A\) is a \(2 \times 2\) matrix given by \(A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right],\) then \(A\) is invertible if and only if \(a d-b c \neq 0 .\) If \(a d-b c \neq 0,\) verify that the inverse is \(A^{-1}=\frac{1}{a d-b c}\left[\begin{array}{rr}d & -b \\ -c & a\end{array}\right]\).
Step-by-Step Solution
Verified Answer
The solution to verifying the inverse of the provided \(2 \times 2\) matrix \(A\) involves confirming the invertibility condition \(ad - bc \neq 0\). Then, form the supposed inverse using the formula and confirm it by multiplying with the original matrix \(A\) to ensure it produces the Identity Matrix. If it does, then the purported inverse is indeed the correct inverse.
1Step 1: Confirm the invertibility condition
To ensure that the matrix \(A\) is invertible, it's necessary to confirm whether the determinant of the matrix \(A\) does not equal to zero. That means, \(ad - bc \neq 0\) given the matrix \(A\).
2Step 2: Write down the form of inverse
Following the formula for inverse of 2x2 matrix, the inverse matrix \(A^{-1}\) should be \(\frac{1}{a d-b c}\left[\begin{array}{rr}d & -b \ -c & a\end{array}\right]\) if \(A\) is invertible.
3Step 3: Demonstrate the multiplication
To prove the correctness of determined inverse, multiply matrix \(A\) with its inverse \(A^{-1}\), in both orders, because matrix multiplication is not generally commutative. The result of the multiplication should yield the Identity matrix in both cases, as this is a primary property of matrix inverses. For \(A \times A^{-1}\) and \(A^{-1} \times A\), both should equal to the \(2 \times 2\) Identity Matrix \(\left[\begin{array}{ll}1 & 0 \ 0 & 1\end{array}\right]\). This shows that the given 'inverse' of matrix \(A\) is indeed its true inverse.
Key Concepts
Matrix Determinant2x2 MatrixIdentity MatrixMatrix Multiplication
Matrix Determinant
The determinant of a matrix is a special number that can help us to understand many properties of the matrix, such as whether it is invertible. For a 2x2 matrix, which is structured like this:
- Matrix A: \[A = \begin{bmatrix} a & b \ c & d \end{bmatrix}\]
- Determinant of A: \[det(A) = ad - bc\]
2x2 Matrix
A 2x2 matrix is one of the simplest forms of matrices, consisting of 2 rows and 2 columns. Each entry in the matrix can be represented by a notation that relates it to its position in the matrix, usually like this:
- Matrix A:\[A = \begin{bmatrix} a & b \ c & d \end{bmatrix}\]
Identity Matrix
An Identity Matrix acts like the number 1 in regular arithmetic, serving as the neutral element in matrix multiplication. For a 2x2 matrix, the identity matrix is expressed as:
- Identity Matrix I: \[I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}\]
- For matrix \(A\): \(A \times A^{-1} = I\) and \(A^{-1} \times A = I\)
Matrix Multiplication
Matrix multiplication involves combining two matrices to produce another matrix. This operation is pivotal when verifying the inverse of a matrix. The procedure for multiplying a 2x2 matrix by another 2x2 matrix involves taking the dot product of rows and columns.Suppose we multiply matrices \(A\) and \(B\):
- Matrix A: \[A = \begin{bmatrix} a & b \ c & d \end{bmatrix}\]
- Matrix B: \[B = \begin{bmatrix} e & f \ g & h \end{bmatrix}\]
- First row of \(C\): \([ae + bg, af + bh]\)
- Second row of \(C\): \([ce + dg, cf + dh]\)
Other exercises in this chapter
Problem 72
Write the partial fraction decomposition for the rational expression. Check your result algebraically by combining fractions, and check your result graphically
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(A) find the determinant of \(A,\) (b) find \(A^{-1},\) (c) find \(\operatorname{det}\left(A^{-1}\right),\) and (d) compare your results from parts (a) and (c).
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