Problem 72
Question
Give the derived SI units for each of the following quantities in base SI units: (a) acceleration \(=\) distance \(/\) time \(^{2}\) (b) force \(=\) mass \(\times\) acceleration (c) work \(=\) force \(\times\) distance (d) pressure \(=\) force/area (e) power = work/time (f) velocity = distance/time (g) energy \(=\) mass \(\times(\text { velocity })^{2}\)
Step-by-Step Solution
Verified Answer
(a) m/s², (b) N, (c) J, (d) Pa, (e) W, (f) m/s, (g) J.
1Step 1: Analyzing Acceleration
Acceleration is given by the formula \( a = \frac{d}{t^2} \), where \( d \) is distance and \( t \) is time. In base SI units, distance is measured in meters (m) and time is in seconds (s). Thus, the derived SI unit for acceleration is \( \frac{\text{m}}{\text{s}^2} \), or \( \text{m/s}^2 \).
2Step 2: Determining Force Units
Force is calculated using \( F = m \cdot a \), where \( m \) is mass and \( a \) is acceleration. Mass in SI units is in kilograms (kg) and acceleration is in meters per second squared (m/s²). Therefore, the derived unit for force is \( \text{kg}\cdot\text{m/s}^2 \), known as a newton (N).
3Step 3: Calculating Work Units
Work is given by \( W = F \cdot d \), where \( F \) is force and \( d \) is distance. The derived unit for force is newtons (N) and distance is in meters (m). Thus, work is measured in newton-meters (N⋅m), also known as a joule (J).
4Step 4: Establishing Pressure Units
Pressure is defined as \( P = \frac{F}{A} \), where \( F \) is force and \( A \) is area. The force is measured in newtons (N) and area is in square meters (m²). Thus, the derived SI unit for pressure is \( \frac{\text{N}}{\text{m}^2} \), which is called a pascal (Pa).
5Step 5: Deriving Power Units
Power is defined by \( P = \frac{W}{t} \), where \( W \) is work and \( t \) is time. Work is measured in joules (J) and time in seconds (s). Therefore, the unit for power is \( \frac{\text{J}}{\text{s}} \), known as a watt (W).
6Step 6: Analyzing Velocity Units
Velocity is given by \( v = \frac{d}{t} \), with distance \( d \) in meters (m) and time \( t \) in seconds (s). Thus, the unit for velocity is meters per second (m/s).
7Step 7: Calculating Energy Units
Energy is calculated using \( E = m \cdot v^2 \). Mass \( m \) is in kilograms (kg) and velocity \( v \) is in meters per second (m/s), squared in this case. Thus, the derived unit for energy is \( \text{kg}\cdot(\text{m/s})^2 \), which simplifies to a joule (J).
Key Concepts
AccelerationForceWorkPressurePowerVelocityEnergy
Acceleration
Acceleration is a measure of how quickly something speeds up or slows down. It involves a change in velocity over time. To calculate acceleration, we use the formula \( a = \frac{d}{t^2} \), where \( d \) is distance and \( t \) is time.
- Distance is measured in meters \( (\text{m}) \).
- Time is measured in seconds \( (\text{s}) \).
Force
Force describes the push or pull on an object, affecting its motion. It is calculated using the formula \( F = m \cdot a \), where:
- \( m \) is mass in kilograms \( (\text{kg}) \).
- \( a \) is acceleration in meters per second squared \( (\text{m/s}^2) \).
Work
Work refers to the energy transferred when a force moves an object over a distance. The equation for work is \( W = F \cdot d \), where:
- \( F \) is force in newtons \( (\text{N}) \).
- \( d \) is distance in meters \( (\text{m}) \).
Pressure
Pressure is the amount of force applied per unit area. It is defined by the formula \( P = \frac{F}{A} \), where:
- \( F \) is force in newtons \( (\text{N}) \).
- \( A \) is area in square meters \( (\text{m}^2) \).
Power
Power measures how quickly work is done or energy is transferred. It is calculated using \( P = \frac{W}{t} \), which breaks down as follows:
- \( W \) is work in joules \( (\text{J}) \).
- \( t \) is time in seconds \( (\text{s}) \).
Velocity
Velocity describes the speed of an object in a particular direction. It is expressed by \( v = \frac{d}{t} \), where:
- \( d \) represents distance in meters \( (\text{m}) \).
- \( t \) is time in seconds \( (\text{s}) \).
Energy
Energy is the capacity to do work. It is determined with \( E = m \cdot v^2 \), involving:
- \( m \) as mass in kilograms \( (\text{kg}) \).
- \( v \) as velocity in meters per second \( (\text{m/s}) \).
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