Problem 72
Question
Give an example of: An invertible function whose graph contains the point (0,3).
Step-by-Step Solution
Verified Answer
An example is the function \( f(x) = x + 3 \), which passes through (0,3) and is invertible.
1Step 1: Define an Invertible Function
To define an invertible function, we can start with a simple linear function, such as \( f(x) = mx + b \). Linear functions are typically invertible unless they are constant. The function needs to be one-to-one and onto for it to have an inverse.
2Step 2: Ensure the Exact Point Fits
To ensure the function passes through the point (0,3), we substitute \((x, y) = (0, 3)\) into \( f(x) \). This gives us \( f(0) = m \times 0 + b = 3 \). So, set \(b = 3\).
3Step 3: Choose a Suitable 'M' Value
To ensure the function remains invertible, we choose any non-zero value for \(m\). For simplicity, we choose \(m = 1\), making our function \( f(x) = x + 3 \).
4Step 4: Verify Function is Invertible
To confirm \( f(x) = x + 3 \) is invertible, we find its inverse. Solve for \( x \) in terms of \( y \). Starting with \( y = x + 3 \), solve to get \( x = y - 3 \). So, the inverse function is \( f^{-1}(x) = x - 3 \). Both functions are linear and therefore invertible.
Key Concepts
Linear FunctionInverse FunctionOne-to-One and Onto
Linear Function
Linear functions are one of the most basic and essential types of functions in mathematics. They have the general form:
Linear functions are very predictable due to their constant rate of change. They are used in many real-world situations where one thing depends linearly on another. As long as \( m eq 0 \), linear functions are invertible, meaning there exists an inverse function for each linear function.
- \( f(x) = mx + b \)
Linear functions are very predictable due to their constant rate of change. They are used in many real-world situations where one thing depends linearly on another. As long as \( m eq 0 \), linear functions are invertible, meaning there exists an inverse function for each linear function.
Inverse Function
An inverse function essentially reverses the operation of the original function. For a function to have an inverse, each output should map to exactly one input. If \( f(x) \) takes an input \( x \) and provides an output \( y \), then the inverse function \( f^{-1}(x) \) does the opposite: it takes \( y \) back to \( x \).For a function \( f(x) = x + 3 \), the process of finding an inverse involves swapping the roles of \( x \) and \( y \). Thus:
- Start with \( y = x + 3 \)
- Solve for \( x \), which gives \( x = y - 3 \)
- Thus, the inverse is \( f^{-1}(x) = x - 3 \)
One-to-One and Onto
For a function to have an inverse, it's essential for the function to be both "one-to-one" and "onto." These two concepts define the nature of the function's invertibility:- **One-to-One:** This means that each input corresponds to a unique output. Mathematically, if \( f(a) = f(b) \) implies that \( a = b \), then the function is one-to-one. In simpler terms, no two different inputs should produce the same output.
- **Onto:** Also called "surjective." This indicates that every possible output in the codomain is mapped to by some input from the domain. Essentially, the function covers all values in the target set. The linear function \( f(x) = x + 3 \) designed in the exercise is both one-to-one and onto, making it invertible. This means every output has an exact pre-image in the domain, fitting all requirements to have an inverse function.
- **Onto:** Also called "surjective." This indicates that every possible output in the codomain is mapped to by some input from the domain. Essentially, the function covers all values in the target set. The linear function \( f(x) = x + 3 \) designed in the exercise is both one-to-one and onto, making it invertible. This means every output has an exact pre-image in the domain, fitting all requirements to have an inverse function.
Other exercises in this chapter
Problem 71
Explain what is wrong with the statement. The inverse of \(f(x)=x\) is \(f^{-1}(x)=1 / x\).
View solution Problem 71
In Problems \(64-71\), find a value of the constant \(k\) such that the limit exists. $$\lim _{x \rightarrow-\infty} \frac{3^{k x}+6}{3^{2 x}+4}$$
View solution Problem 72
For each value of \(\epsilon\) in Problems \(72-73,\) find a positive value of \(\delta\) such that the graph of the function leaves the window \(a-\delta
View solution Problem 72
Are the statements true or false? Give an explanation for your answer. The function \(f(x)=|\sin x|\) is even.
View solution