Problem 72
Question
\(\frac{11}{12} h-\frac{5}{8} h+\frac{4}{5} k-\frac{1}{9} k\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{7}{24} h + \frac{31}{45} k \).
1Step 1: Combine Like Terms for 'h'
Identify and combine the like terms involving 'h'. The terms are \(\frac{11}{12} h \) and \(\frac{5}{8} h \). To combine them, find a common denominator for the fractions. The common denominator for 12 and 8 is 24.
2Step 2: Convert 'h' Terms to Common Denominator
Convert each fraction to have the common denominator of 24. \(\frac{11}{12} = \frac{11 \times 2}{12 \times 2} = \frac{22}{24}\) and \(\frac{5}{8} = \frac{5 \times 3}{8 \times 3} = \frac{15}{24}\). So, the expression becomes \(\frac{22}{24} h - \frac{15}{24} h \).
3Step 3: Simplify 'h' Terms
Subtract the fractions: \(\frac{22}{24} h - \frac{15}{24} h = \frac{22 - 15}{24} h = \frac{7}{24} h \).
4Step 4: Combine Like Terms for 'k'
Identify and combine the like terms involving 'k'. The terms are \(\frac{4}{5} k \) and \(\frac{1}{9} k \). To combine these, find a common denominator for the fractions. The common denominator for 5 and 9 is 45.
5Step 5: Convert 'k' Terms to Common Denominator
Convert each fraction to have the common denominator of 45. \(\frac{4}{5} = \frac{4 \times 9}{5 \times 9} = \frac{36}{45}\) and \(\frac{1}{9} = \frac{1 \times 5}{9 \times 5} = \frac{5}{45}\). So, the expression becomes \(\frac{36}{45} k - \frac{5}{45} k \).
6Step 6: Simplify 'k' Terms
Subtract the fractions: \(\frac{36}{45} k - \frac{5}{45} k = \frac{36 - 5}{45} k = \frac{31}{45} k \).
7Step 7: Combine Simplified Terms
Combine the simplified terms from Steps 3 and 6: \(\frac{7}{24} h + \frac{31}{45} k \).
Key Concepts
common denominatorsfraction subtractionsimplifying expressions
common denominators
When working with fractions, it’s important to have a common denominator if you want to add or subtract them. The common denominator is a shared multiple of the denominators of the fractions you’re working with. For instance, in our exercise, to combine \( \frac{11}{12} h \) and \( \frac{5}{8} h \), we needed to find a common denominator for 12 and 8. We found it to be 24, so we converted both fractions to have this denominator:
- \( \frac{11}{12} = \frac{22}{24} \)
- \( \frac{5}{8} = \frac{15}{24} \)
fraction subtraction
When you need to subtract fractions, the first step is often to convert your fractions so they all have a common denominator. This makes the subtraction process much simpler.
Step-by-step process for fraction subtraction:
Step-by-step process for fraction subtraction:
- Find a common denominator: Identify a number that both denominators divide into evenly.
- Convert the fractions: Modify each fraction to have the common denominator.
- Subtract the numerators: Perform the subtraction operation on the numerators while keeping the common denominator the same.
- Convert: \( \frac{11}{12}h - \frac{5}{8}h = \frac{22}{24}h - \frac{15}{24}h \)
- Subtract: \( \frac{22}{24} - \frac{15}{24} = \frac{7}{24}h \)
- Convert: \( \frac{4}{5}k - \frac{1}{9}k = \frac{36}{45}k - \frac{5}{45}k \)
- Subtract: \( \frac{36}{45} - \frac{5}{45} = \frac{31}{45}k \)
simplifying expressions
Simplifying algebraic expressions means making them as straightforward as possible. It often involves combining like terms and reducing fractions to their simplest forms. For our example, we took the terms involving 'h' and 'k' separately to simplify them.
Steps involved in simplifying expressions:
\( \frac{7}{24} h + \frac{31}{45} k \) This process shows how to take a complex expression and make it more manageable by breaking it down and simplifying step by step.
Steps involved in simplifying expressions:
- Combine like terms: Group terms with the same variable.
- Use common denominators: Make sure the fractions have common denominators if you need to add or subtract them.
- Simplify the fractions: Perform the arithmetic operations and simplify the fraction if possible.
- Combine like terms: \( \frac{22}{24}h - \frac{15}{24}h = \frac{7}{24} h \)
- Combine like terms: \( \frac{36}{45}k - \frac{5}{45}k = \frac{31}{45}k \)
\( \frac{7}{24} h + \frac{31}{45} k \) This process shows how to take a complex expression and make it more manageable by breaking it down and simplifying step by step.
Other exercises in this chapter
Problem 72
The original price of a box of cereal is \(\$ 4.59\). If the cereal is on sale at \(18 \%\) off, find the cost of 4 boxes of cereal. Round to the nearest hundre
View solution Problem 72
In November 2007 , U.S. airlines had 415,024 scheduled departures. Find the number of flights that landed close to their scheduled arrival time. Round to the ne
View solution Problem 73
Find the number of worker fatalities in private industry in construction. Out of 4,070 worker fatalities in private industry in calendar year 2010 , one-fifth .
View solution Problem 73
\(6\left(\frac{2}{3} x+\frac{4}{9}\right)\)
View solution