Problem 72
Question
For the given representation of a function \(f,\) graph the reflection across the \(x\)-axis and graph the reflection across the \(y\)-axis. \(f(x)=\frac{1}{2}|x-2|+2\)
Step-by-Step Solution
Verified Answer
The x-axis reflection is \( g(x) = -\frac{1}{2}|x-2| - 2 \) and the y-axis reflection is \( h(x) = \frac{1}{2}|x+2| + 2 \).
1Step 1: Identify the Original Graph
The original function is given as \( f(x) = \frac{1}{2}|x-2| + 2 \). This is an absolute value function, \( g(x) = |x-2| \), vertically compressed by \(\frac{1}{2}\) and shifted up by 2 units. Additionally, it is shifted to the right by 2 units. The vertex of the original graph is at the point (2, 2).
2Step 2: Reflect Original Graph Across the x-axis
Reflecting a graph across the \(x\)-axis involves changing the sign of the \(y\)-values of the function. Therefore, for the reflection of \(f(x) = \frac{1}{2}|x-2| + 2\) across the \(x\)-axis, we get \( g(x) = -\left(\frac{1}{2}|x-2| + 2\right) = -\frac{1}{2}|x-2| - 2 \). This reflection will have its vertex at the point (2, -2).
3Step 3: Reflect Original Graph Across the y-axis
Reflecting a graph across the \(y\)-axis involves changing \(x\) to \(-x\) in the function. For \( f(x) = \frac{1}{2}|x-2| + 2 \), \( x \) becomes \(-x\), resulting in \( h(x) = \frac{1}{2}|-x-2| + 2 \), which simplifies to \( h(x) = \frac{1}{2}|x+2| + 2 \). This reflection has a vertex at (-2, 2).
4Step 4: Sketch the Graphs
Graph the original function \( f(x) \) with its vertex at (2, 2). For the reflection across the \(x\)-axis, sketch \( g(x) = -\frac{1}{2}|x-2| - 2 \) with a vertex at (2, -2). For the reflection across the \(y\)-axis, sketch \( h(x) = \frac{1}{2}|x+2| + 2 \) with a vertex at (-2, 2). Make sure to maintain the shape of the function as a V-shape with different locations for each graph.
Key Concepts
Absolute Value FunctionsReflections Across AxesVertex Form
Absolute Value Functions
An absolute value function is a type of piecewise function defined using the absolute value of a variable. The absolute value is always non-negative, reflecting the function's graphical representation as a "V" shape. In this context, the function is represented as \( f(x) = \frac{1}{2}|x-2| + 2 \). To understand how this function behaves, consider the following steps:
- Identify that \(|x-2|\) shifts the basic absolute value function \(|x|\) two units to the right on the x-axis.
- The coefficient \(\frac{1}{2}\) compresses the graph vertically, making the "V" less steep compared to the standard \(|x|\) function.
- Adding 2 to the entire function shifts the graph upward by two units.
Reflections Across Axes
Reflections across axes involve flipping a graph over a specified axis, thus changing the orientation of the graph.
When reflecting across the x-axis:
When reflecting across the x-axis:
- Change every \( y \) value to \(-y\) resulting in the equation \( g(x) = -\left(\frac{1}{2}|x-2| + 2\right) = -\frac{1}{2}|x-2| - 2 \).
- This flips the graph upside down, with the vertex now located at (2, -2).
- Substitute \(x\) with \(-x\) thus transforming the equation into \( h(x) = \frac{1}{2}|-x-2| + 2 \), which simplifies to \( h(x) = \frac{1}{2}|x+2| + 2 \).
- This moves the vertex of the function to (-2, 2), effectively mirroring the entire graph horizontally about the y-axis.
Vertex Form
The vertex form of a function makes it easy to identify key characteristics of a graph, particularly the vertex itself, which is crucial for graphing purposes.
For an absolute value function like \( f(x) = \frac{1}{2}|x-2| + 2 \):
For an absolute value function like \( f(x) = \frac{1}{2}|x-2| + 2 \):
- This form is clearly structured as \( y = a|x-h| + k \), where \((h, k)\) is the vertex.
- In our equation, \( (h, k) = (2, 2) \), showing the point where the graph changes direction.
- The coefficient \( a = \frac{1}{2} \) affects the steepness of the graph's arms.
Other exercises in this chapter
Problem 71
Solve the equation for \(y .\) Determine if y is a function of \(x\). $$ 3 x^{2}+4 y^{2}=12 $$
View solution Problem 72
Explain how to determine the solution set for the inequality \(a x^{2}+b x+c0 .\) How would the solution set change if \(a
View solution Problem 72
Solve. Write answers in standard form. $$ 3 x^{2}+x-x(5-x)-2 $$
View solution Problem 72
Solve the equation for \(y .\) Determine if y is a function of \(x\). $$ x-25 y^{2}=50 $$
View solution