Problem 72
Question
Find the term in the expansion of \(\left(x^{2}+y^{2}\right)^{5}\) containing \(x^{4}\) as a factor.
Step-by-Step Solution
Verified Answer
The term in the expansion of \(\left(x^{2}+y^{2}\right)^{5}\) that contains \(x^{4}\) as a factor is \(10x^{4}y^{2}\).
1Step 1: Use of Binomial Expansion
Expand \((x^{2}+y^{2})^{5}\) using binomial theorem. This theorem dictates that \((a + b)^{n}=\sum _{k=0}^{n} \binom{n}{k} a^{n-k}b^{k}\). Here, \(a\) and \(b\) are \(x^{2}\) and \(y^{2}\) respectively and \(n=5\). With this theorem, all terms in the expansion can be constructed.
2Step 2: Identify Needed Term
Since we need a term with \(x^{4}\) as a factor, we need \(x^{2}\) to be squared, implying \(a^{n-k} = (x^{2})^{2}\), hence \(n-k = 2\). This provides one value of \(k = n - 2 = 5 - 2 = 3\). Substituting this into the binomial expansion yields the required term, \(\binom{5}{3}x^{4}y^{2}\). By definition, \(\binom{5}{3}\) is equal to \(\frac{5!}{3!(5-3)!}\), which simplifies to 10.
3Step 3: Multiply Result to Simplify
Multiply 10 by \(x^{4}\) and \(y^{2}\) to get the term needed, \(10x^{4}y^{2}\).
Other exercises in this chapter
Problem 71
In the sequence \(21,700,23,172,24,644,26,116, \ldots,\) which term is \(314,628 ?\)
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How many four-digit odd numbers less than 6000 can be formed using the digits \(2,4,6,7,8,\) and \(9 ?\) Digits may be repeated.
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Use the formula for the value of an annuity. Round answers to the nearest dollar. To save for a new home, you invest 500 dollar per month in a mutual fund with
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Explain the best way to evaluate \(\frac{900 !}{899 !}\) without calculator.
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